Answer: there are 20 people who claimed to be neither CDO partisans nor ANC partisans.
Step-by-step explanation:
To determine the number of people who are none of these two parties, we need to subtract the total number of people who claimed to be CDO partisans, ANC partisans, and those who claimed to be both from the total number of people surveyed.
Total surveyed people = 130
Number claiming to be CDO partisans = 80
Number claiming to be ANC partisans = 60
Number claiming to be both ANC and CDO = 30
To find the number of people who are none of these two parties, we can calculate it as follows:
None of these two parties = Total surveyed people - (CDO partisans + ANC partisans - Both ANC and CDO)
None of these two parties = 130 - (80 + 60 - 30)
None of these two parties = 130 - 110
None of these two parties = 20
0.005627 to 3 decimal places
(i) Correcting the figures to 3 decimal places:
-0.005627 ≈ -0.006
0.0056 ≈ 0.006
-0.0049327 ≈ -0.005
0.0049 ≈ 0.005
-0.001342 ≈ -0.001
(ii) Correcting the figures to 3 significant figures:
-0.005627 ≈ -0.00563
0.0056 ≈ 0.00560
-0.0049327 ≈ -0.00493
0.0049 ≈ 0.00490
-0.001342 ≈ -0.00134
(i) When rounding to 3 decimal places, we look at the fourth decimal place and round the figure accordingly. If the fourth decimal place is 5 or above, we round up the preceding third decimal place. If the fourth decimal place is less than 5, we simply drop it.
(ii) When rounding to 3 significant figures, we consider the digit in the third significant figure. If the digit in the fourth significant figure is 5 or above, we round up the preceding third significant figure. If the digit in the fourth significant figure is less than 5, we simply drop it.
Rounding to the correct number of decimal places or significant figures is important to maintain precision and accuracy in calculations and measurements. It helps to ensure that the reported values are appropriate for the level of precision required in a given context.
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Adults are encouraged to visit the dentist at least once a year. In the 2019 National College Health
Assessment, 28,021 out of a random sample of 38,433 college students said they had a dental exam in
the last 12 months.
¹American College Health Association-National College Health Assessment (2020). Undergraduate student
reference group data report, Fall 2019. https://www.acha.org/NCHA/ACHA-
NCHA Data/Publications and Reports/NCHA/Data/Reports ACHA-NCHAIIl.aspx
Use the appropriate data analysis tool to construct a 99% confidence interval to estimate the
population proportion of college students who said they had a dental exam in the last 12 months.
Lower Bound
Upper Bound
The boundaries of the 99% confidence interval are
Lower bound = 0.7232Upper bound = 0.7348Constructing the 99% confidence intervalFrom the question, we have the following parameters that can be used in our computation:
Selected, x = 28021
Sample, n = 38433
This means that the proportion, p is
p = 28021/38433
p = 0.729
The 99% confidence interval is then calculated as
CI = p ± z * √(p * (1 - p)/n)
Where
z = 2.576 i.e. the z-score at 99% confidence interval
So, we have
CI = 0.729 ± 2.576 * √(0.729 * (1 - 0.729)/38433)
Evaluate
CI = 0.729 ± 0.0058
Evaluate
CI = (0.7232, 0.7348)
Hence, the confidence interval is (0.7232, 0.7348)
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The area of a triangular road sign is 70 square ft. If the base of the sign measures 14 ft, what is the height of the sign?
Answer:
height = 10 ft
Step-by-step explanation:
the area (A) of a triangle is calculated as
A = [tex]\frac{1}{2}[/tex] bh ( b is the base and h the height )
given A = 70 and b = 14 , then
[tex]\frac{1}{2}[/tex] × 14 × h = 70
7h = 70 ( divide both sides by 7 )
h = 10 ft
Triangle ABC has the following coordinates: A=(5,-5), B=(3,-3), C=(5,-3) What are the coordinates of triangle A'B'C' if it is created by dilating triangle ABC with the origin (0,0) as the center of dilation and with a scale factor of 3?
Answer:A' = (15, -15), B' = (9, -9), and C' = (15, -9)
Step-by-step explanation:
To dilate triangle ABC with a center of dilation at the origin (0,0) and a scale factor of 3, you need to multiply the coordinates of each vertex by the scale factor.
Let's calculate the coordinates of triangle A'B'C':
For point A:
x-coordinate of A' = scale factor * x-coordinate of A = 3 * 5 = 15
y-coordinate of A' = scale factor * y-coordinate of A = 3 * (-5) = -15
Therefore, A' = (15, -15)
For point B:
x-coordinate of B' = scale factor * x-coordinate of B = 3 * 3 = 9
y-coordinate of B' = scale factor * y-coordinate of B = 3 * (-3) = -9
Therefore, B' = (9, -9)
For point C:
x-coordinate of C' = scale factor * x-coordinate of C = 3 * 5 = 15
y-coordinate of C' = scale factor * y-coordinate of C = 3 * (-3) = -9
Therefore, C' = (15, -9)
Hence, the correct coordinates of triangle A'B'C' are A' = (15, -15), B' = (9, -9), and C' = (15, -9).
A store has a sale with 20% off every item. When you enter the store, you receive a coupon that states that you receive an additional 30% off. Is this equal to a 50% discount? Explain your answer
Answer: Nope
Step-by-step explanation:
No, receiving a 20% discount followed by an additional 30% discount does not result in a total discount of 50%.
To understand why, let's consider an example with an item priced at $100.
If there is a 20% discount applied initially, the price of the item would be reduced by 20%, which is $100 * 0.20 = $20. So the new price after the first discount would be $100 - $20 = $80.
Now, if there is an additional 30% discount applied to the $80 price, the discount would be calculated based on the new price. The 30% discount would be $80 * 0.30 = $24. So the final price after both discounts would be $80 - $24 = $56.
Comparing the final price of $56 to the original price of $100, we can see that the total discount is $100 - $56 = $44.
Therefore, the total discount received is $44 out of the original price of $100, which is a discount of 44%, not 50%.
Hence, receiving a 20% discount followed by an additional 30% discount does not result in a total discount of 50%.
Aschalew is able to do apiece of work in 15 days and Abay can do the same work in 20 daya. if they can work together for 4 days, what is the fraction of the work left?
Answer:
8/15
Step-by-step explanation:
1/15(4 + 1/20(4)
4/15 + 4/20 I can reduce 4/20 to 1/5
4/15 + 1/5
4/15 + 3/15 = 7/15
Together they can get 7/15 of the job done. 15/15 - 7/15 is 8/15.
That means that they have 8/15 left to do.
Helping in the name of Jesus.
Quadrilateral EFGH is an isosceles trapezoid with bases EH and FG. The measure of angle HGF is (9y + 3)°, and the measure of angle EFG is (By + 5)°.
What is the measure of angle HGF?
The correct Option is A. The measure of angle HGF is 20°.
Quadrilateral EFGH is an isosceles trapezoid with bases EH and FG.
The measure of angle HGF is (9y + 3)°, and the measure of angle EFG is (By + 5)°.
To find the measure of angle HGF, we need to solve for the value of y.
Since EFGH is an isosceles trapezoid, the opposite angles are congruent.
Therefore, the measure of angle EFG is also (9y + 3)°.
To find the value of y, we can set the two expressions equal to each other: (9y + 3)° = (By + 5)°.
Next, we can solve for y by isolating it.
We subtract 3° from both sides: 9y = By + 2.
To get y by itself, we subtract By from both sides: 9y - By = 2.
Finally, we can factor out y: y(9 - B) = 2.
To solve for y, we divide both sides by (9 - B): y = 2 / (9 - B).
Now that we have the value of y, we can substitute it back into the expression for angle HGF: (9y + 3)°.
Thus, the measure of angle HGF is (9(2 / (9 - B)) + 3)°.
Therefore, The correct Option is A.
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A small college has 204 student athletes. The number of students who play soccer is 52. The number of students who play volleyball is 31. The probability that a student plays in both volleyball and soccer is 5/204.What is the probability that a randomly selected student athlete in this school: Plays both soccer and volleyball? Plays volleyball?
To calculate the probabilities, we can use the following information:
Total number of student athletes = 204
Number of students who play soccer = 52
Number of students who play volleyball = 31
Probability of a student playing both soccer and volleyball = 5/204
1. Probability that a student plays both soccer and volleyball:
Let's denote the probability of playing both soccer and volleyball as P(Soccer and Volleyball). From the given information, we know that the number of students who play both soccer and volleyball is 5.
P(Soccer and Volleyball) = Number of students who play both soccer and volleyball / Total number of student athletes
P(Soccer and Volleyball) = 5 / 204
2. Probability that a student plays volleyball:
We want to find the probability of a student playing volleyball, denoted as P(Volleyball).
P(Volleyball) = Number of students who play volleyball / Total number of student athletes
P(Volleyball) = 31 / 204
Therefore, the probability that a randomly selected student athlete in this school plays both soccer and volleyball is 5/204, and the probability that they play volleyball is 31/204.
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