A movie theater sold 480
boxes of gummy worms during the
month of June. At this rate, how
many boxes of gummy worms will
the movie theater sell in a year?

Answer:

-2.375

Step-by-step explanation:

43/8=5.375

5+5.375=10.375

8-10.375=-2.375

Answer:

Answer should be b the volume

Answer:

The function that represents exponential decay is y = 50 [tex](0.95)^{x}[/tex] ⇒ B

Step-by-step explanation:

The form of the exponential growth function is y = a [tex](1+r)^{x}[/tex]

The form of the exponential decay function is y = a [tex](1-r)^{x}[/tex]

∵ The function represents exponential decay with 5%

→ By using the second rule above

∴ y = a [tex](1-r)^{x}[/tex]

∵ The rate of decrease is 5%

∴ r = 5%

→ Change it to decimal by dividing it by 100

∵ 5% = 5 ÷ 100 = 0.05

∴ r = 0.05

→ Substitute it in the equation

∵ y = a [tex](1-0.05)^{x}[/tex]

∴ y = a [tex](0.95)^{x}[/tex]

→ Look at the answer to find which equation is written in this form

∴ y = 50 [tex](0.95)^{x}[/tex]

∴ The function that represents exponential decay is y = 50 [tex](0.95)^{x}[/tex]

Answer: D. (4, 1)

Step-by-step explanation:

When we have a reflection over a line, the perpendicular distance to that line is invariant.

Then, if we have the point

(-7, 4) and we have a reflection over the line x = -3

The distance between the x component and the line is:

I -7 - (-3)I = 4

Then the reflected point will also be at a distance of 4 units to the line x = 3, and this is at the point x = 1.

Then the new point is (1, 4)

Now we do a reflection over the line x = y.

This type of reflection just changes the x-component by the y-component, and the y-component by the x-component.

Then the new point will be (4, 1)

Then the correct option is D.

Answer:

1/2

Step-by-step explanation:

Answer:

8:12:3

Step-by-step explanation:

Flats:Terraced is 2:3

Detached:Terraced is 1:4

First make the Terraced the same.

Flats:Terraced is 8:12

Detached:Terraced is 3:12

Terraced:Detached is 12:3

Now that we know, we can combine it.

Flats:Terraced:Detached is 8:12:3

Hope this helps :D

Step-by-step explanation:

5/8 binod

be happy binod here's ur answer binod

Answer:

5/8

Step-by-step explanation:

Answer:

it is a simultaneous equation.

the -9d can be cancelled to find the answer

The requried solution of the given system of equations is c = 8 and d = -7.

Simultaneous linear equations are two- or three-variable linear equations that can be solved together to arrive at a common solution.

here,
Given a system of equations,
6c-9d=111  - - - - - (1)
5c-9d=103 - - - - -(2)

Solving the above two equations,
by subtracting 2 from 1|
c = 111 - 103
c = 8

Now,
6(8) - 9d = 111
d = - [111 - 48] / 9
d = -63 / 9
d = -7

Thus, the requried solution of the given system of equations is c = 8 and d = -7.

Learn more about simultaneous equations here:

https://brainly.com/question/16763389

#SPJ2

Answer: 47 inches

Step-by-step explanation:

Let x = length of the shortest piece

188 inches = 3x + x

188 inches = 4x

47 inches = x

Answer:

The shorter piece is 47 unches long

Step-by-step explanation:

l + s = 188

l = 3s

3s + 3 = 188

4s = 188

4s/4 = 188/4

s = 47

l = 3s

l = 3(47)

l = 141

Answer:

3/35

Step-by-step explanation:

Answer:

we conclude that the rule will be:

[tex]a_n=\frac{31}{12}+\frac{1}{6}n[/tex]

Step-by-step explanation:

Given

[tex]a_6=3\frac{7}{12}=\frac{43}{12}[/tex]

[tex]a_1=2\frac{3}{4}=\frac{11}{4}[/tex]

We know the arithmetic sequence with the common difference is defined as

[tex]a_n=a_1+\left(n-1\right)d[/tex]

where a₁ is the first term and d is a common difference.

so

a₆ = a₁ + (6-1) d

substituting a₆ = 43/12 and a₁ = 11/4 to determine d

[tex]\frac{43}{12}=\:\frac{11}{4}\:+\:5d[/tex]

switch sides

[tex]\frac{11}{4}+5d=\frac{43}{12}[/tex]

subtract 11/4 from both sides

[tex]\frac{11}{4}+5d-\frac{11}{4}=\frac{43}{12}-\frac{11}{4}[/tex]

[tex]5d=\frac{5}{6}[/tex]

Divide both sides by 5

[tex]\frac{5d}{5}=\frac{\frac{5}{6}}{5}[/tex]

[tex]d=\frac{1}{6}[/tex]

as

a₁ = 11/4

[tex]d=\frac{1}{6}[/tex]

Therefore, the nth term of the Arithmetic sequence will be:

[tex]a_n=a_1+\left(n-1\right)d[/tex]

substituting d = 1/6 and a₁ = 11/4

[tex]a_n=\frac{11}{4}+\left(n-1\right)\frac{1}{6}[/tex]

    [tex]=\frac{11}{4}+\frac{1}{6}n-\frac{1}{6}[/tex]

    [tex]=\frac{31}{12}+\frac{1}{6}n[/tex]

Therefore, we conclude that the rule will be:

[tex]a_n=\frac{31}{12}+\frac{1}{6}n[/tex]

Answer:

Step-by-step explanation:

add then subtact D from 3

Answer:

Brand A

Its easy

Mark as Brainliest.

Because I am Indian and solving your question from India.

Answer:

Step-by-step explanation:

9

3

4

Answer:

1. 9

2. 3

3. 4

Step-by-step explanation:

I have taken the test and got 100% on it so I hope this helped you!

Answer:

Hope it helpsssssss

Step-by-step explanation:

4/7, 8/14, 12/21, 16/28, 20/35, 24/42, 28/49, 32/56, 36/63, 40/70, and so on

Answer:

[tex]122 = x - 58 \\ x = 122 + 58 \\ x = 180 \\ error = 0.5 \times {10}^{ - 3} \\ = 0.0005[/tex]

Answer:

Step-by-step explanation:

Grace should have added 58 to both sides of the equation instead of subtracting.

Answer:

55?

Step-by-step explanation:

........................

Answer:

AB=55

Step-by-step explanation:

9x+1=7x+13

2x=12

x=6

9x+1=9(6)+1

55

Answer:

what do you need help with the answer is going to be anything under -6 for example -7, -8, -9, -6.5 something along those lines

Step-by-step explanation:

Answer:

24

Step-by-step explanation:

Given that:

Baseball album holds 3 baseball cards per page

Number of pages in album = 8

3 baseball cards per page

Number of baseball cards album can hold

(Number of baseball cards per page * number of pages in album)

(3 * 8) = 24

Answer:

[tex]\boxed{\pink{\sf (x + 3) \ is\ the \ LCM . }}[/tex]

Step-by-step explanation:

Given two expressions ,

[tex] \qquad (1)\: x^2 - 9 \\\\ \qquad (2)\:3x^3 + 81 [/tex]

And , we need to find the LCM , that is lowest common factor . So , let's factorise them seperately .

Factorising x² - 9 :-

[tex]= x^2 - 9 \\\\= x^2 - 3^2 \\\\ \red{= (x+3)(x-3)} \qquad\bf [Using \ a^2-b^2 = (a+b)(a-b) ][/tex]

Factorising 3x³ + 81

[tex]= 3x^3 + 81\\\\= 3(x^3+27) \\\\= 3( x^3+27) \\\\ = 3(x^3+3^3) \\\\ \red{= 3 [ (x+3)(x^2+9-3x) ] } \qquad \bf{[ Using \ a^3+b^3=(a+b)(a^2+b^2-ab) ] } [/tex]

Hence we can see that (x+3) is common factor in both expressions.

Hence the LCM is ( x+3 ) .

Answer:

d = 50t

Step-by-step explanation:

In the table, the values across from each other are equivalent.

[tex]\begin{tabular}{|c|c|}\cline{1-2} Time in hours (t) & Distance in miles (d) \\\cline{1-2} 0 & 0 \\\cline{1-2} 1 & 50 \\\cline{1-2} 2 & 100 \\\cline{1-2} 3 & 150 \\\cline{1-2}\end{tabular}[/tex]

By looking at the second row of the provided table, we can see that d is equal 50 times the value of t. We can write this as an equation:

d = 50t

The correct answer choice is d = 50t, or the 4th option.

Let me know if you have any questions!

Answer:

4,900

Step-by-step explanation:

Because i just know

Answer: 25%

Explanation:

1. Turn it into a fraction 150/200

2. Divide numerator (150) by denominator (200) to get 0.75

3. Subtract 0.75 from 1 to get 0.25

4. Turn 0.25 into a percentage by simply taking away the “0.” and adding a “%” at the end (25%)

Answer:

[tex]d=\dfrac{t^2}{a}[/tex]

Step-by-step explanation:

The time  in seconds, required for an object accelerating at a constant rate of a meters/second to travel a distance of d meters is given by this  equation.

t = va

We need to find the expression for d in terms of t and a.

As velocity = distance/time

[tex]t=\dfrac{d}{t}a\\\\t^2=da\\\\d=\dfrac{t^2}{a}[/tex]

So, the distance d is [tex]\dfrac{t^2}{a}[/tex].

Answer:

i guess its b and d

Step-by-step explanation:

-2+2=0

Answer:

option B is correct

B and D

because B is -2 and D is 2

to make 0

we can combined that 2numbers then we got -2+2=0

Step-by-step explanation:

hope my answer is helpful to you

Answer:

-8

Step-by-step explanation:

if you add negitive 8 to 8 then the sum will be 0

Answer:

-8

Step-by-step explanation:

when you add a negative number your basically subtracting its absolute value.

Answer:

(0,6) ==> y-axis

(5,-2) ==> Quadrant IV

(-1,10) ==> Quadrant II

(5,0) ==> x-axis

(8.7,2.3) ==> Quadrant I

[tex]( - \frac{1}{4} \: \: \: - 6 \frac{1}{2} ) \: = = > quadrant \: iii[/tex]

Answer:

According to the Heron's formula, Area (A) of the triangle having sides a,b,c units is

A=

s(s−a)(s−b)(s−c)

where

s=

2

a+b+c

For the given triangle,

a=18 cm

b=24 cm

c=30 cm

s=

2

18+24+30

=36

A=

36(36−18)(36−24)(36−30)

A=

36×18×12×6

A=

216×216

=216 cm

2

Smallest side =18 cm

Area of the triangle =

2

1

×base×altitude=216

2

1

×18× altitude=216

Altitude =

9

216

=24 cm

Step-by-step explanation:

hope this will help

[tex]\boxed{\boxed{\pink{\bf \leadsto The \ length \ of \ shortest \ altitude \ is \ 2.4\sqrt{6} \ units . }}}[/tex]

Here given measure of sides are 18 , 24 and 30 units. Firstly let's find the area of ∆ using Heron's Formula.

[tex]\boxed{\red{\bf Area_{\triangle} =\sqrt{s(s-a)(s-b)(s-c)}}}[/tex]

Where s is semi Perimeter . And here s will be ( 18 + 24 + 30 ) / 2 = 36 units .

[tex]\bf \implies Area = \sqrt{s(s-a)(s-b)(s-c)} [/tex]

[tex]\bf \implies Area = \sqrt{ 36 ( 36 - 18)(36-24)(36-30)}[/tex]

[tex]\bf \implies Area = \sqrt{ 36 \times 18 \times 12} [/tex]

[tex]\bf \implies Area = \sqrt{ 6^2 \times 6\times 6 \times 2 \times 3} [/tex]

[tex]\bf \implies Area = 6^2\sqrt{6} unit^2 [/tex]

[tex]\bf \boxed{ \implies Area_{triangle} = 36\sqrt{6} units^2} [/tex]

Also we know that ,

[tex]\boxed{\red{\bf Area_{\triangle} = \dfrac{1}{2}\times (base)\times (height)}}[/tex]

Let's find the altitudes now ,

Altitude on side of 18 units :-

[tex]\bf \implies Area = \dfrac{1}{2} \times (base)(height) \\\\\bf \implies 36\sqrt{6} unit^2 = \dfrac{1}{2} \times 18 \times h_1 = 36\sqrt{6} u^2 \\\\\bf\implies h_1 =\dfrac{ 36\sqrt6 \times 2 }{18} \\\\\boxed{\bf\implies h_1 = 4\sqrt6 units }[/tex]

Altitude on side of 24 units :-

[tex]\bf \implies Area = \dfrac{1}{2} \times (base)(height) \\\\\bf \implies 36\sqrt{6} unit^2 = \dfrac{1}{2} \times 24 \times h_1 = 36\sqrt{6} u^2 \\\\\bf\implies h_1 =\dfrac{ 36\sqrt6 \times 2 }{24} \\\\\boxed{\bf\implies h_1 = 3\sqrt6 units }[/tex]

Altitude on side 30 units :-

[tex]\bf \implies Area = \dfrac{1}{2} \times (base)(height) \\\\\bf \implies 36\sqrt{6} unit^2 = \dfrac{1}{2} \times 30 \times h_1 = 36\sqrt{6} u^2 \\\\\bf\implies h_1 =\dfrac{ 36\sqrt6 \times 2 }{30} \\\\\boxed{\bf\implies h_1 = 2.4\sqrt6 units }[/tex]