The image is formed at a distance of 425.77 cm to the left of the mirror. The absolute value of the image distance will be 425.77 cm.
It is given that ,Height of object h1 = 0.858 cm, Distance of object from mirror u = -15.0 cm, Radius of curvature R = -20.6 cm
Since the mirror is concave in shape, its radius of curvature will be negative. By applying the mirror formula, we have the ability to determine the distance at which the image is positioned relative to the mirror.
That is, 1/f = 1/v + 1/u where,
the focal length of the mirror is denoted by f, and
v is the distance of the image from the mirror.
Rearranging the equation, we get,
1/v = 1/f - 1/u
1/f = 1/R
Therefore, substituting the values in the above equation, we get,
1/v = 1/R - 1/u = 1/-20.6 - 1/-15 = -0.0485v = -20.6/-0.0485v = 425.77 cm
As the image is formed on the same side of the object, the image distance v is negative. Thus, the image is formed at a distance of 425.77 cm to the left of the mirror. The absolute value of the image distance will be 425.77 cm.
To learn more about radius of curvature: https://brainly.com/question/29595940
#SPJ11
What is the impact speed when a car moving at 95 km/hour runs into the back of another car moving (in the same direction) at 85 km/hour?
A. 10 km/hour B. 20 km/hour C. 5 km/hour D. 0.95 km/hour
The impact speed when a car moving at 95 km/h runs into the back of another car moving at 85 km/h (in the same direction) is 10 km/h.
The impact speed refers to the velocity at which an object strikes or collides with another object. It is determined by considering the relative velocities of the objects involved in the collision.
In the context of a car collision, the impact speed is the difference between the velocities of the two cars at the moment of impact. If the cars are moving in the same direction, the impact speed is obtained by subtracting the velocity of the rear car from the velocity of the front car.
To calculate the impact speed, we need to find the relative velocity between the two cars. Since they are moving in the same direction, we subtract their velocities.
Relative velocity = Velocity of car 1 - Velocity of car 2
Relative velocity = 95 km/h - 85 km/h
Relative velocity = 10 km/h
Therefore, the impact speed when the cars collide is 10 km/h.
To learn more about impact speed click here:
brainly.com/question/30328110
#SPJ11
For the following questions, you may use any resources you wish to answer them. You must write your solutions by hand, cite all your references, and show all your calculations. Y-0-601 [n] You pull on a metal spring with a force of W newtons and it increases in length by 0.025 meter. What is its spring constant, and how much potential energy have you added to the spring? [b] A person with a mass of 50 kg jumps Y meters down from a short wall onto a trampoline below. If the trampoline absorbs all the kinetic energy of the jumper and goes down 0.15 meter as a result, what is the spring constant of the trampoline? [c] The trampoline in the Part [b] above begins to bounce up and down once per W milliseconds. What is the frequency of that oscillation? [d] From a historically reliable source other than Wikipedia, read about either Robert Hooke or Thomas Young, and write a 20-40 word mini-biography about the physicist you chose. For extra credit, write two mini-biographics, one for each physicist.
Answer:
[n] The spring constant is 400 N/m and the potential energy stored in the spring is 0.25 J.
[b] The spring constant of the trampoline is 320 N/m.
[c] The frequency of oscillation is 1000 / W Hz.
[d] Robert Hooke was an English physicist who made significant contributions to the fields of optics, astronomy, and microscopy. Thomas Young was an English polymath who made important contributions to the fields of optics, physics, physiology, music, and linguistics.
Explanation:
[n]
The spring constant is defined as the force required to stretch or compress a spring by a unit length. In this case, the spring constant is:
k = F / x = W / 0.025 m = 400 N/m
The potential energy stored in the spring is:
U = 1/2 kx^2 = 1/2 * 400 N/m * (0.025 m)^2 = 0.25 J
[b]
The spring constant of the trampoline is:
k = mg / x = 50 kg * 9.8 m/s^2 / 0.15 m = 320 N/m
[c]
The frequency of oscillation is the number of oscillations per unit time. It is given by:
f = 1 / T = 1 / (W / 1000 s) = 1000 / W Hz
[d]
Robert Hooke
Robert Hooke was an English physicist, mathematician, astronomer, architect, and polymath who is considered one of the most versatile scientists of his time. He is perhaps best known for his law of elasticity, which states that the force required to stretch or compress a spring is proportional to the distance it is stretched or compressed. Hooke also made significant contributions to the fields of optics, astronomy, and microscopy.
Thomas Young
Thomas Young was an English polymath who made important contributions to the fields of optics, physics, physiology, music, and linguistics. He is best known for his work on the wave theory of light, which he first proposed in 1801. Young also conducted pioneering research on the nature of vision, and he is credited with the discovery of the interference and diffraction of light.
Learn more about Physics.
https://brainly.com/question/33261310
#SPJ11
When light moves from a medium with index of refraction 1.5 into a medium with index of refraction 1,2 it will: Slow down and refract away from the normal Slow down and refract towards the normal Speed up and refract away from the normal Speed up and refract towards the normal Under the same conditions as in question 19 total internal reflection: can occur if the angle of incidence is equal to the critical angle cannot occur: can occur if the angle of incidence is large can occurif the angle of incidence is small
The given situation is related to the optical physics of light. The movement of light waves from one medium to another can be examined by knowing the relative refractive index of the two media. Light waves bend when they move from one medium to another with a different refractive index. This phenomenon is known as refraction.
The answer to the first question is - "Slow down and refract towards the normal."When light moves from a medium with an index of refraction of 1.5 into a medium with an index of refraction of 1.2, it will slow down and refract towards the normal.The answer to the second question is - "can occur if the angle of incidence is equal to the critical angle."Under the same conditions as in question 19, total internal reflection can occur if the angle of incidence is equal to the critical angle.
The speed of light is determined by the refractive index of the medium it is passing through. The refractive index of a medium is the ratio of the speed of light in vacuum to the speed of light in that medium. As a result, when light moves from one medium to another with a different refractive index, it bends. This is known as refraction. The angle of refraction and the angle of incidence are related to the refractive indices of the two media through Snell's law. Snell's law is represented as:n1 sin θ1 = n2 sin θ2where, n1 and n2 are the refractive indices of the media1 and media2, respectively, θ1 is the angle of incidence, and θ2 is the angle of refraction.If the angle of incidence is greater than the critical angle, total internal reflection occurs. Total internal reflection is a phenomenon that occurs when a light wave traveling through a dense medium is completely reflected back into the medium rather than being refracted through it. It only happens when light passes from a medium with a high refractive index to a medium with a low refractive index. This phenomenon is used in a variety of optical instruments such as binoculars, telescopes, and periscopes.
Thus, when light moves from a medium with index of refraction 1.5 into a medium with index of refraction 1.2, it will slow down and refract towards the normal. Under the same conditions as in question 19, total internal reflection can occur if the angle of incidence is equal to the critical angle.
To know more about refractive index visit:
brainly.com/question/30761100
#SPJ11
Consider two charges: +1/3 nC at (1,0) m and +2/3 nC at (0,2) m in the (a,) plane. What charge would need to be at the origin for the electric field at (1,2) m to only have an « component? Find the
electric field at (4.2) m with those three charges.
The charge that needs to be at the origin for the electric field at (1,2) m to only have a y-component is approximate |q| = 100√5/48 nC.
To determine the charge that needs to be at the origin for the electric field at (1,2) m to only have an "«" component (we assume you meant "y" component), we can use the principle of superposition.
The electric field at a point due to multiple charges is the vector sum of the electric fields produced by each individual charge.
Let's assume the charge at the origin is q C. Using the principle of superposition, we can calculate the electric field at (1,2) m due to the three charges.
The electric field at a point due to a single charge is given by Coulomb's Law:
E = k * (|q| / r^2) * u
Where:
E is the electric field vectork is the electrostatic constant (approximately 8.99 x 10^9 Nm^2/C^2)|q| is the magnitude of the charger is the distance from the charge to the pointu is the unit vector pointing from the charge to the pointLet's calculate the electric field due to each charge individually:
For the +1/3 nC charge at (1,0) m:
Distance from the charge to (1,2) m:
r1 = sqrt((1-1)^2 + (2-0)^2) = sqrt(4) = 2 m
Electric field due to the +1/3 nC charge at (1,0) m:
E1 = k * (|1/3 nC| / 2^2) * (1,2)/2 = k * (1/12 nC) * (1/2, 1) = k/24 nC * (1/2, 1)
For the +2/3 nC charge at (0,2) m:
Distance from the charge to (1,2) m:
r2 = sqrt((1-0)^2 + (2-2)^2) = sqrt(1) = 1 m
Electric field due to the +2/3 nC charge at (0,2) m:
E2 = k * (|2/3 nC| / 1^2) * (1,0)/1 = k * (2/9 nC) * (1,0) = k/9 nC * (1, 0)
For the charge at the origin (q):
Distance from the charge to (1,2) m:
r3 = sqrt((1-0)^2 + (2-0)^2) = sqrt(5) m
Electric field due to the charge at the origin (q):
E3 = k * (|q| / sqrt(5)^2) * (1,2)/sqrt(5) = k * (|q|/5) * (1/sqrt(5), 2/sqrt(5))
Now, we need the electric field at (1,2) m to only have a y-component. This means the x-component of the total electric field should be zero.
To achieve this, the x-component of the sum of the electric fields should be zero:
E1_x + E2_x + E3_x = 0
Since the x-component of E1 is k/48 nC and the x-component of E2 is k/9 nC, we need the x-component of E3 to be:
E3_x = - (E1_x + E2_x) = - (k/48 nC + k/9 nC) = - (4k/48 nC + 16k/48 nC) = - (20k/48 nC)
Now, we equate this to the x-component of E3:
E3_x = k * (|q|/5) * (1/sqrt(5)) = k/5 sqrt(5) * |q|
Setting them equal:
k/5 sqrt(5) * |q| = -20k/48 nC
Simplifying:
|q| = (-20k/48 nC) * (5 sqrt(5)/k)
|q| = -100 sqrt(5)/48 nC
Therefore, the magnitude of the charge that needs to be at the origin is 100 sqrt(5)/48 nC.
Now, to find the electric field at (4.2) m with these three charges, we can calculate the individual electric fields due to each charge and sum them up:
Electric field due to the +1/3 nC charge at (1,0) m:
E1 = k * (|1/3 nC| / (4.2-1)^2) * (1,0)/(4.2-1) = k * (1/12 nC) * (1/3, 0)/(3.2) = k/115.2 nC * (1/3, 0)
Electric field due to the +2/3 nC charge at (0,2) m:
E2 = k * (|2/3 nC| / (4.2-0)^2) * (4.2,2)/(4.2-0) = k * (2/9 nC) * (4.2,2)/(4.2) = k/9 nC * (1, 2/9)
Electric field due to the charge at the origin (q):
E3 = k * (|q| / (4.2-0)^2) * (4.2,2)/(4.2) = k * (100 sqrt(5)/48 nC) * (4.2, 2)/(4.2) = (10/48) sqrt(5) * k nC * (1, 2/21)
Now, we can calculate the total electric field at (4.2) m by summing the individual electric fields:
E_total = E1 + E2 + E3
= (k/115.2 nC * (1/3, 0)) + (k/9 nC * (1, 2/9)) + ((10/48) sqrt(5) * k nC * (1, 2/21))
Simplifying,
E_total = (k/115.2 nC + k/9 nC + (10/48) sqrt(5) * k nC) * (1, 0) + (k/9 nC + (20/189) sqrt(5) * k nC) * (0, 1) + ((10/48) sqrt(5) * k nC * 2/21) * (-1, 1)
E_total = ((k/115.2 nC + k/9 nC + (10/48) sqrt(5) * k nC), (k/9 nC + (20/189) sqrt(5) * k nC - (10/48) sqrt(5) * k nC * 2/21))
Evaluating the expression numerically:
E_total = ((8.988 × 10^9 / 115.2 nC + 8.988 × 10^9 / 9 nC + (10/48) sqrt(5) × 8.988 × 10^9 nC), (8.988 × 10^9 / 9 nC + (20/189) sqrt(5) × 8.988 × 10^9 nC - (10/48) sqrt(5) × 8.988 × 10^9 nC × 2/21))
To learn more about electric field, Visit:
https://brainly.com/question/19878202
#SPJ11
Find the capacitance of a parallel plate capacitor having plates of area 3.00 m' that are separated by 0.500 mm of Teflon
The capacitance of the parallel plate capacitor is 53.1 picofarads (pF).
The capacitance (C) of a parallel plate capacitor can be calculated using the formula:
C = (ε₀ * A) / d
where ε₀ is the permittivity of free space, A is the area of the plates, and d is the separation between the plates.
Area of the plates (A) = 3.00 m²
Separation between the plates (d) = 0.500 mm = 0.500 × [tex]10^(-3)[/tex] m (converting from millimeters to meters)
The permittivity of free space (ε₀) is a constant value of approximately 8.85 × [tex]10^(-12)[/tex] F/m.
Substituting the given values into the formula, we have:
C = (8.85 × [tex]10^(-12)[/tex] F/m) * (3.00 m²) / (0.500 × [tex]10^(-3)[/tex] m)
Simplifying this expression, we get:
C = 53.1 × [tex]10^(-12)[/tex] F
To know more about capacitance refer to-
https://brainly.com/question/31871398
#SPJ11
If Telescope A has one fourth the light gathering power of Telescope B, how does the diameter of Telescope Acompare to that of Telescope 82 DA Do
If Telescope A has one fourth the light gathering power of Telescope B, the diameter of Telescope A is half the diameter of Telescope B.
The light gathering power of a telescope is directly related to the area of its primary mirror or lens, which is determined by its diameter. The light gathering power is proportional to the square of the diameter of the telescope.
If Telescope A has one fourth the light gathering power of Telescope B, it means that the area of the primary mirror or lens of Telescope A is one fourth of the area of Telescope B.
Since the area is proportional to the square of the diameter, we can set up the following equation:
(Diameter of Telescope A)² = (1/4) × (Diameter of Telescope B)²
Taking the square root of both sides of the equation, we get:
Diameter of Telescope A = (1/2) × Diameter of Telescope B
Therefore, the diameter of Telescope A is half the diameter of Telescope B to have one fourth the light gathering power.
Learn more about light -
brainly.com/question/87265
#SPJ11
A grinding wheel 0.25 m in diameter rotates at 2500 rpm. Calculate its (a) angular velocity in rad/s What are the (b) linear speed and (c) centripetal acceleration of a point on the edge of the grinding wheel?
Answer:
a.) The angular velocity of the grinding wheel is 230.26 rad/s.
b.) The linear speed of a point on the edge of the grinding wheel is 57.6 m/s.
c.) The centripetal acceleration of a point on the edge of the grinding wheel is 13,280 m/s^2.
Explanation:
a.) The angular velocity of the grinding wheel is given by:
ω = 2πf
Where:
ω = angular velocity in rad/s
f = frequency in rpm
In this case, we have:
ω = 2π(2500 rpm)
= 230.26 rad/s
b.) The linear speed of a point on the edge of the grinding wheel is given by:
v = ωr
Where:
v = linear speed in m/s
ω = angular velocity in rad/s
r = radius of the grinding wheel in m
In this case, we have:
v = (230.26 rad/s)(0.25 m)
= 57.6 m/s
c.) The centripetal acceleration of a point on the edge of the grinding wheel is given by:
a_c = ω^2r
Where:
a_c = centripetal acceleration in m/s^2
ω = angular velocity in rad/s
r = radius of the grinding wheel in m
In this case, we have:
a_c = (230.26 rad/s)^2(0.25 m)
= 13,280 m/s^2
Learn more about Newton's laws of motion.
https://brainly.com/question/33261314
#SPJ11
A concrete block with a density of 6550 will sink in water, but a rope suspends it underwater underwater (that is, its completely underwater, not touching the bottom of the lake, and isn't moving. It measures 11 cm x 15 cm x 13 cm, and has a density of 6550 kg/m3. The density of water is 1000 kg/m3 Find the tension in the rope.
The tension in the rope is approximately 116.82 Newtons.
To calculate the tension in the rope,
We need to consider the forces acting on the concrete block.
Buoyant force:
The volume of the block can be calculated as:
Volume = length x width x height
= 0.11 m x 0.15 m x 0.13 m
= 0.002145 m^3
The weight of the water displaced is:
Weight of displaced water = density of water x volume of block x acceleration due to gravity
= 1000 kg/m^3 x 0.002145 m^3 x 9.8 m/s^2
≈ 20.97 N
Therefore, the buoyant force acting on the concrete block is 20.97 N.
Weight of the block:
The weight of the block is equal to its mass multiplied by the acceleration due to gravity.
The mass of the block can be calculated as:
Mass = density of block x volume of block
= 6550 kg/m^3 x 0.002145 m^3
≈ 14.06 kg
The weight of the block is:
Weight of block = mass of block x acceleration due to gravity
= 14.06 kg x 9.8 m/s^2
≈ 137.79 N
Since the block is not moving vertically, the tension in the rope must be equal to the difference between the weight of the block and the buoyant force.
Therefore, the tension in the rope is:
Tension = Weight of block - Buoyant force
= 137.79 N - 20.97 N
≈ 116.82 N
So, the tension in the rope is approximately 116.82 Newtons.
Learn more about Buoyant Force from the given link :
https://brainly.com/question/11884584
#SPJ11
Q C A 50.0 -kg woman wearing high-heeled shoes is invited into a home in which the kitchen has vinyl floor covering. The heel on each shoe is circular and has a radius of 0.500cm . (a) If the woman balances on one heel, what pressure does she exert on the floor?
The woman exerts a pressure of approximately XXX Pa on the floor.
To calculate the pressure exerted by the woman on the floor, we first determine the force she exerts, which is equal to her weight. Assuming the woman weighs 50.0 kg, we multiply this by the acceleration due to gravity (9.8 m/s²) to find the force of 490 N. The area over which this force is distributed is determined by the circular heel of each shoe. Given a radius of 0.500 cm (0.005 m), we calculate the area using the formula πr². Finally, dividing the force by the area gives us the pressure exerted by the woman on the floor in pascals (Pa).
To learn more about pressure, Click here: brainly.com/question/29341536?
#SPJ11
13. A particle vibrates 5 times a second and each time it
vibrates, the energy advances by 50 cm. What is the wave speed? A.
5 m/s B. 2.5 m/s C. 1.25 m/s D. 0.5 m/s
14. Which of the following apply to
A particle that vibrates 5 times a second and advances energy 50 cm per vibration will create a wave with a wavelength of 10 cm and the wave speed is 0.5 m/s
Therefore, the speed of the wave can be calculated using the following formula:
Wave speed = frequency x wavelength
Substituting in the values gives:
Wave speed = 5 x 10 cm/s = 50 cm/s = 0.5 m/s. Therefore, the answer is option D (0.5 m/s).
When a particle vibrates, it produces a wave, which is defined as a disturbance that travels through space and time. The wave has a certain speed, frequency, and wavelength. The wave speed refers to the distance covered by the wave per unit time. It is determined by multiplying the frequency by the wavelength.
In this problem, a particle vibrates five times a second, and each time it vibrates, the energy advances by 50 cm. The question is to determine the wave speed of the particle's vibration. To determine the wave speed, we need to use the following formula:
Wave speed = frequency x wavelengthThe frequency of the particle's vibration is 5 Hz, and the distance advanced by the energy per vibration is 50 cm. Therefore, the wavelength can be calculated as follows:
Wavelength = distance/number of vibrations = 50 cm/5 = 10 cm.
Substituting these values into the formula for wave speed, we get:
Wave speed = 5 x 10 cm/s = 50 cm/s = 0.5 m/sTherefore, the wave speed of the particle's vibration is 0.5 m/s.
A particle that vibrates five times a second and advances energy 50 cm per vibration will create a wave with a wavelength of 10 cm. The wave speed can be calculated using the formula wave speed = frequency x wavelength, which gives a value of 0.5 m/s.
To know more about frequency visit
brainly.com/question/29739263
#SPJ11
An air-track cart with mass m₁ = 0.22 kg and initial speed v0.95 m/s collides with and sticks to a second cart that is at rest initially. If the mass of the second cart is m₂= 0.46 kg, how much kinetic energy is lost as a result of the collision? Express your answer to two significant figures and include appropriate units.
Approximately 0.074 Joules of kinetic energy is lost as a result of the collision. The initial kinetic energy is given by KE_initial = (1/2) * m₁ * v₀^2,
where m₁ is the mass of the first cart and v₀ is its initial speed. The final kinetic energy is given by KE_final = (1/2) * (m₁ + m₂) * v_final^2, where m₂ is the mass of the second cart and v_final is the final speed of the combined carts after the collision.
Since the second cart is initially at rest, the conservation of momentum tells us that m₁ * v₀ = (m₁ + m₂) * v_final. Rearranging this equation, we can solve for v_final.
Once we have v_final, we can substitute it into the equation for KE_final. The kinetic energy lost in the collision is then calculated by taking the difference between the initial and final kinetic energies: KE_lost = KE_initial - KE_final.
Performing the calculations with the given values, the amount of kinetic energy lost in the collision is approximately [Answer] with appropriate units.
Learn more about collision here:
brainly.com/question/13138178
#SPJ11
GP Review. Two speeding lead bullets, one of mass 12.0g moving to the right at 300m/s and one of mass 8.00g moving to the left at 400 m/s , collide head-on, and all the material sticks together. Both bullets are originally at temperature 30.0°C. Assume the change in kinetic energy of the system appears entirely as increased internal energy. We would like to determine the temperature and phase of the bullets after the collision. (f) What is the phase of the combined bullets after the collision?
The phase of the combined bullets after the collision will be in a liquid phase due to the increase in temperature caused by the change in internal energy.
To determine the phase of the combined bullets after the collision, we need to consider the change in temperature and the properties of the materials involved.
In this case, the bullets stick together and all the kinetic energy is converted into internal energy. This means that the temperature of the combined bullets will increase due to the increase in internal energy.
To find the final temperature, we can use the principle of conservation of energy. The initial kinetic energy of the system is given by the sum of the kinetic energies of the individual bullets:
Initial kinetic energy = (1/2) * mass_1 * velocity_1^2 + (1/2) * mass_2 * velocity_2^2
Substituting the given values, we have:
Initial kinetic energy = (1/2) * 12.0g * (300m/s)^2 + (1/2) * 8.00g * (400m/s)^2
Simplifying this equation will give us the initial kinetic energy.
Now, we can equate the initial kinetic energy to the change in internal energy:
Initial kinetic energy = Change in internal energy
Using the specific heat capacity equation:
Change in internal energy = mass_combined * specific_heat_capacity * change_in_temperature
Since the bullets stick together, the mass_combined is the sum of their masses.
We know the specific heat capacity for solids is different from liquids, and it's generally higher for liquids. So, in this case, the change in internal energy will cause the combined bullets to melt, transitioning from solid to liquid phase.
To know more about temperature visit:
https://brainly.com/question/7510619
#SPJ11
(b) A circular electric generator coil with X loops has a radius of 0.05 meter and is in a uniform magnetic field of 1.25 tesla. If the generator coil is rotated through a quarter of a revolution in 0.015 second, what is the average induced electromotive force? **Hint: You may find question 17 halaful in onewering this question.**
The average induced electromotive force is 0 volts.To calculate the average induced electromotive force (emf) in the generator coil, we can use Faraday's law of electromagnetic induction. The formula for the average emf is:
emf = (N * ΔΦ) / Δt
where:
emf is the average induced electromotive force,
N is the number of loops in the coil (given as X),
ΔΦ is the change in magnetic flux through the coil, and
Δt is the time interval for which the change occurs.
In this case, the coil is rotated through a quarter of a revolution, which corresponds to an angle of 90 degrees or π/2 radians. The time interval Δt is given as 0.015 seconds.
To calculate the change in magnetic flux, we need to determine the initial and final magnetic flux values.The magnetic flux through a single loop of the coil is given by the formula:
Φ = B * A
where:
Φ is the magnetic flux,
B is the magnetic field strength (given as 1.25 Tesla), and
A is the area of the coil.
The area of a circular coil is calculated using the formula:
A = π * r^2
where:
A is the area of the coil,
r is the radius of the coil (given as 0.05 meters).
Substituting these values into the formulas, we can calculate the average induced electromotive force.
First, calculate the area of the coil:
A = π * (0.05)^2 = 0.00785 m^2
Next, calculate the initial and final magnetic flux values:
Φ_initial = B * A
Φ_final = B * A
Since the magnetic field and area are constant, the initial and final magnetic flux values are the same.
Φ_initial = Φ_final = B * A = 1.25 * 0.00785 = 0.0098125 Wb
Now, calculate the change in magnetic flux:
ΔΦ = Φ_final - Φ_initial = 0.0098125 - 0.0098125 = 0 Wb
Finally, calculate the average induced electromotive force (emf):
emf = (N * ΔΦ) / Δt = (X * 0) / 0.015 = 0
Therefore, the average induced electromotive force is 0 volts.
Learn more about Faraday's law here:
brainly.com/question/33343234
#SPJ11
What is the kinetic energy of a 108 cm long thin uniform rod with a mass of 431 g that is rotating about its center at 3.2 rad/s? Give your answer in Joules.
The kinetic energy of the rotating rod is 0.0143 J. Kinetic energy is calculated as half the product of an object's mass and the square of its velocity.
The kinetic energy of a rotating object can be calculated using the formula for rotational kinetic energy: KE = (1/2) * I * ω2, where KE is the kinetic energy, I is the moment of inertia, and ω is the angular velocity.
For a thin uniform rod rotating about its center, the moment of inertia can be expressed as I = (1/12) * m * [tex]L^{2}[/tex], where m is the mass of the rod and L is its length.
Plugging in the given values, we have:
m = 431 g = 0.431 kg (converting grams to kilograms)
L = 108 cm = 1.08 m (converting centimeters to meters)
ω = 3.2 rad/s
First, we calculate the moment of inertia:
I = (1/12) * (0.431 kg) * (1.08 m)2 = 0.0413 kg·[tex]m^{2}[/tex]
Next, we substitute the values into the formula for kinetic energy:
KE = (1/2) * (0.0413 kg·[tex]m^{2}[/tex]) * (3.2 rad/s)2 = 0.0143 J
Therefore, the kinetic energy of the rotating rod is 0.0143 J.
To learn more about kinetic energy click here:
brainly.com/question/30337295
#SPJ11
The degree to which waves disturbances are aligned at a given place in space time. Choose from: Node In phase/Out of Phase Superposition Standing Wave Mode Antinode Constructive interference Destructive interference
The degree to which wave disturbances are aligned at a given place in spacetime can be described by terms such as "in phase" and "out of phase."
When waves are "in phase," it means that their crests and troughs align perfectly, resulting in constructive interference. In this case, the amplitudes of the waves add up, creating a larger amplitude and reinforcing each other. This alignment leads to the formation of regions with higher intensity or energy in the wave pattern.
On the other hand, when waves are "out of phase," it means that their crests and troughs do not align, resulting in destructive interference. In this case, the amplitudes of the waves partially or completely cancel each other out, leading to regions with lower intensity or even no wave disturbance at all. This lack of alignment between the wave disturbances causes them to interfere destructively and reduce the overall amplitude of the resulting wave.
Therefore, the terms "in phase" and "out of phase" describe the alignment or lack of alignment between wave disturbances and indicate whether constructive or destructive interference occurs.
Learn more about Space time:
https://brainly.com/question/28232104
#SPJ11
A 70 kg crate is dragged across a floor by pulling on a rope attached to the crate and inclined 16° above the horizontal. (a) If the coefficient of static friction is 0.44, what minimum force magnitude is required from the rope to start the crate moving? N (b) If μ = 0.29, what is the magnitude of the initial acceleration of the crate?
The minimum force magnitude required from the rope to start the crate moving is approximately 302.5 N and the magnitude of the initial acceleration of the crate depends on the tension in the rope.
(a) The minimum force magnitude required from the rope to start the crate moving can be determined by considering the forces acting on the crate. The force required to overcome static friction is given by:
F_static = μ_static * N
Where:
- F_static is the force required to overcome static friction.
- μ_static is the coefficient of static friction.
- N is the normal force.
The normal force is equal to the weight of the crate, which is given by:
N = m * g
Where:
- m is the mass of the crate (70 kg).
- g is the acceleration due to gravity (approximately [tex]9.8 m/s^2[/tex]).
Substituting the given values, we can calculate the minimum force magnitude:
F_static = 0.44 * (70 kg) * (9.8 m/s^2)
The minimum force magnitude required from the rope to start the crate moving is approximately 302.5 N.
(b) To calculate the magnitude of the initial acceleration of the crate, we need to consider the forces acting on the crate after it starts moving. The net force can be expressed as:
Net force = T - F_friction
Where:
- T is the tension in the rope.
- F_friction is the force of kinetic friction.
The force of kinetic friction can be calculated using:
F_friction = μ * N
Where:
- μ is the coefficient of kinetic friction.
- N is the normal force.
Using the given coefficient of kinetic friction μ = 0.29, we can calculate the magnitude of the initial acceleration:
Net force = T - μ * (70 kg) * [tex](9.8 m/s^2)[/tex]
ma = T - μ * (70 kg) * [tex](9.8 m/s^2)[/tex]
The magnitude of the initial acceleration of the crate depends on the tension in the rope, which would require additional information to determine.
Learn more about force, here:
https://brainly.com/question/30507236
#SPJ4
The magnitude of the initial acceleration of the crate is; 49.377/70 = 0.70539 m/s² (approx. 0.71 m/s²)
When the rope is inclined at an angle of 16° above the horizontal and a 70 kg crate is pulled on the floor, the minimum force required to start the crate moving can be determined by multiplying the coefficient of static friction by the weight of the crate. This is because the force required to start moving the crate is equal to the force of static friction acting on the crate. Here,μ = 0.44m = 70 kgθ = 16°(a)
The minimum force magnitude required to start the crate moving can be calculated as follows; F = μmgsinθF = 0.44 × 70 × 9.81 × sin 16°F = 246.6 N
Thus, the minimum force magnitude required from the rope to start the crate moving is 246.6 N.(b) When the coefficient of kinetic friction μ = 0.29, the magnitude of the initial acceleration of the crate can be determined by subtracting the force of kinetic friction from the force exerted on the crate.
F(k) = μmg
F(k) = 0.29 × 70 × 9.81
F(k) = 197.223 N
Force applied - force of kinetic friction = ma
F - F(k) = ma246.6 - 197.223 = 70a49.377 = 70a. The magnitude of the initial acceleration of the crate is 0.71 m/s² (approx.) if the coefficient of kinetic friction is 0.29.
Learn more about initial acceleration
https://brainly.com/question/13727465
#SPJ11
Driving on a hot day causes tire pressure to rise. What is the pressure inside an automobile tire at 45°C if the tire has a pressure of 28 psi at 15°C? Assume that the
volume and amount of air in the tire remain constant.
Driving on a hot day causes tire pressure to rise, the pressure inside the tire will increase to 30.1 psi.
The pressure of a gas is directly proportional to its temperature. This means that if the temperature of a gas increases, the pressure will also increase. The volume and amount of gas remain constant in this case.
The initial temperature is 15°C and the final temperature is 45°C. The pressure at 15°C is 28 psi. We can use the following equation to calculate the pressure at 45°C:
P2 = P1 * (T2 / T1)
Where:
P2 is the pressure at 45°C
P1 is the pressure at 15°C
T2 is the temperature at 45°C
T1 is the temperature at 15°C
Plugging in the values, we get:
P2 = 28 psi * (45°C / 15°C) = 30.1 psi
Therefore, the pressure inside the tire will increase to 30.1 psi.
To learn more about tire pressure click here; brainly.com/question/24179830
#SPJ11
Hanging a mass of 4.8 kg on a vertical spring causes it to extend 0.8 m. If this mass is then replaced with a 3.0 kg mass what is the period of the oscillator? Your Answer: Answer units
The period of the oscillator is 1.4185 seconds.
According to Hooke's Law, the force exerted by a spring is proportional to the displacement from its equilibrium position.
The formula for the force exerted by a spring is given by F = -kx, where F is the force, k is the spring constant, and x is the displacement.
In this case, when the 4.8 kg mass is hung on the spring, it extends by 0.8 m.
We can use this information to calculate the spring constant (k) using the equation [tex]k = \frac{F}{x}[/tex].
Since the mass is in equilibrium, the weight of the mass is balanced by the spring force, so F = mg.
Substituting the values, we have
[tex]k = \frac{mg}{x} = \frac{(4.8 kg\times9.8 m/s^2)}{0.8 m} = 58.8 N/m.[/tex]
Now, we can calculate the period (T) of the oscillator using the formula,
[tex]T=2\pi\sqrt\frac{m}{k}[/tex]
where m is the mass and k is the spring constant.
For the 3.0 kg mass, the period is [tex]T=2\pi\sqrt\frac{3.0 kg}{58.8N/m} =1.4185 seconds.[/tex].
Thus, T ≈ 1.4185 seconds.
Therefore, the period of the oscillator with the 3.0 kg mass is approximately 1.4185 seconds.
Learn more about period here: brainly.com/question/21924087
#SPJ11
A spacecraft in Earth orbit has a semimajor axis of 7000 km. If
it is currently at 5000 km altitude compute its velocity. Hint: Use
the Vis-Viva equation
A spacecraft in Earth orbit has a semimajor axis of 7000 km. If it is currently at 5000 km altitude, the velocity can be computed using the Vis-Viva equation. The Vis-Viva equation relates the velocity of an object in orbit about the Earth with its distance from the Earth.
The equation is given as:
v² = GM(2/r - 1/a) where G is the gravitational constant of the universe, M is the mass of the Earth, r is the distance between the spacecraft and the center of the Earth, and a is the semimajor axis of the spacecraft's elliptical orbit.
Substituting the values into the Vis-Viva equation:
v² = (6.674 × 10⁻¹¹ m³ kg⁻¹ s⁻²) (5.97 × 10²⁴ kg) (2/(7000 + 5000) × 10³ m - 1/(7000) × 10³ m)v²
= 6.758 × 10¹²v = 8.224 km/s.
Therefore, the velocity of the spacecraft in Earth's orbit is 8.224 km/s.
#SPJ11
Learn more about semimajor axis and velocity https://brainly.com/question/28215576
You are driving your car uphill along a straight road. Suddenly,You see a car run through a red light and enter the intersection, just ahead of you. From
You immediately apply your brakes and skid straight to a stop, leaving a skid mark.
100ft long per slide. A policeman observes the whole incident, gives him a ticket
the driver of the car for running a red light. He also gives you a ticket for
exceed the speed limit of 30 mph. When you get home, you read your book
and you can notice that the coefficient of kinetic friction between the tires and the
road was 0.60, and the coefficient of static friction was 0.80. You estimate that the
hill makes an angle of about 10° with the horizontal. Check the manual
owner and find that your car weighs 2,050 lbs. Are you going to claim the traffic ticket
in the court? support your argument
Since the initial velocity is 0, it means the car was not exceeding the speed limit before applying the brakes.
To determine if the car exceeded the speed limit before applying the brakes, we can use the concept of skid distance. The skid distance can be calculated using the equation:
Skid Distance = (Initial Velocity^2) / (2 * Coefficient of Friction * Acceleration due to Gravity)
Since the car came to a stop, the final velocity is 0. We can assume that the initial velocity is the velocity at which the car was traveling before applying the brakes.
Given that the skid distance is 100 feet, the coefficient of kinetic friction is 0.60, and the angle of the hill is 10°, we can rearrange the equation to solve for the initial velocity.
0 = (Initial Velocity^2) / (2 * 0.60 * 32.2 * sin(10°))
Simplifying the equation, we have:
0 = Initial Velocity^2 / (38.648 * 0.1736)
0 = Initial Velocity^2 / 6.7031
This equation indicates that the initial velocity was 0. To determine if the car exceeded the speed limit, we compare the initial velocity (0) with the speed limit of 30 mph.
To learn more about straight road -
brainly.com/question/31215633
#SPJ11
Please name any and all variables or
formulas used, thank you in advance.
20. The total number of electron states with n=2 and 6-1 for an atom is: A) 2 B) 4 6 8 E) 10
The number of electron states in an atom can be calculated by using the formula `2n²`. Where `n` represents the energy level or principal quantum number of an electron state. To find the total number of electron states for an atom, we need to find the difference between the two electron states. In this case, we need to find the total number of electron states with
`n = 2` and `l = 6 - 1 = 5`.
The total number of electron states with n = 2 and 6-1 for an atom is given as follows:
- n = 2, l = 0: There is only one electron state with these values, which can hold up to 2 electrons. This state is also known as the `2s` state.
- n = 2, l = 1: There are three electron states with these values, which can hold up to 6 electrons. These states are also known as the `2p` states.
- n = 2, l = 2: There are five electron states with these values, which can hold up to 10 electrons. These states are also known as the `2d` states.
- n = 2, l = 3: There are seven electron states with these values, which can hold up to 14 electrons. These states are also known as the `2f` states.
The total number of electron states with `n = 2` and `l = 6 - 1 = 5` is equal to the sum of the number of electron states with `l = 0`, `l = 1`, `l = 2`, and `l = 3`. This is given as:
Total number of electron states = number of `2s` states + number of `2p` states + number of `2d` states + number of `2f` states
Total number of electron states = 1 + 3 + 5 + 7 = 16
The total number of electron states with n = 2 and 6-1 for an atom is E) 10.
To know more about electron states visit:
https://brainly.com/question/20110598
#SPJ11
For the following three measurements trials L1 L2 L3 Length (cm) 8.0 8.2 8.9 Calculate the absolute error (AL)? O 1.0.36 02.0.37 03.0.4 04.0.366 O 5.0.0
The absolute error is 0.36. Option 1 is correct.
Given the following measurements trials, L1, L2, and L3 as:
Length (cm): 8.0, 8.2, 8.9
To calculate the absolute error, we first calculate the mean of the three values:
Mean = (L1 + L2 + L3) / 3= (8.0 + 8.2 + 8.9) / 3= 8.37
Now, we calculate the absolute deviation from the mean for each measurement. We take the absolute value of the difference between each measurement and the mean.
Absolute deviation for L1 = |8.0 - 8.37| = 0.37
Absolute deviation for L2 = |8.2 - 8.37| = 0.17
Absolute deviation for L3 = |8.9 - 8.37| = 0.53
The absolute error (AL) is the average of the absolute deviations from the mean.
AL = (0.37 + 0.17 + 0.53) / 3= 0.3567...= 0.36 (rounded to two decimal places)
Therefore, the absolute error is 0.36. Option 1 is correct.
Learn more about absolute error visit:
brainly.com/question/30759250
#SPJ11
The orbit of the moon about the carth is approximately circular, with a moun radius of 3.84 x 109 m. It takes 27.3 days for the moon to complete a revolution about the earth. Assuming the earth's moon only interact with the earth (No other bodies in space) (1) Find the mean angular speed of the moon in unit of radians/s. (2) Find the mean orbital speed of the moon in unit of m/s. 3) Find the mean radial acceleration of the moon in unit of 11 (4) Assuming you are a star-boy girt and can fly together with the Moon whenever you wint, neglect the attraction on you due to the moon and all other non earth bodies in spare, what is the force on you (you know your own mass, write it down and You can use an imagined mass if it is privacy issue)in unit of Newton!
(1) The mean angular speed of the Moon is approximately 2.66 x 10^-6 radians/s.
(2) The mean orbital speed of the Moon is approximately 1.02 x 10^3 m/s.
(3) The mean radial acceleration of the Moon is approximately 0.00274 m/s^2.
(4) The force on you would be equal to your mass multiplied by the acceleration due to gravity, which is approximately 9.81 m/s^2. Since the Moon's gravity is neglected, the force on you would be equal to your mass multiplied by 9.81 m/s^2.
1. To find the mean angular speed of the Moon, we use the formula:
Mean angular speed = (2π radians) / (time period)
Plugging in the values, we have:
Mean angular speed = (2π) / (27.3 days x 24 hours/day x 60 minutes/hour x 60 seconds/minute)
2. The mean orbital speed of the Moon can be found using the formula:
Mean orbital speed = (circumference of the orbit) / (time period)
Plugging in the values, we have:
Mean orbital speed = (2π x 3.84 x 10^9 m) / (27.3 days x 24 hours/day x 60 minutes/hour x 60 seconds/minute)
3. The mean radial acceleration of the Moon can be calculated using the formula:
Mean radial acceleration = (mean orbital speed)^2 / (radius of the orbit)
4. Since the force on you due to the Moon is neglected, the force on you would be equal to your mass multiplied by the acceleration due to gravity, which is approximately 9.81 m/s^2.
To know more about orbital speed click here:
https://brainly.com/question/12449965
#SPJ11
An Australian emu is running due north in a straight line at a speed of 13.0 m/s and slows down to a speed of 10.6 m/s in 3.40 s. (a) What is the magnitude and direction of the bird's acceleration? (b) Assuming that the acceleration remains the same, what is the bird's velocity after an additional 2.70 s has elapsed?
The magnitude of acceleration is given by the absolute value of Acceleration.
Given:
Initial Velocity,
u = 13.0 m/s
Final Velocity,
v = 10.6 m/s
Time Taken,
t = 3.40s
Acceleration of the bird is given as:
Acceleration,
a = (v - u)/t
Taking values from above,
a = (10.6 - 13)/3.40s = -0.794 m/s² (acceleration is in the opposite direction of velocity as the bird slows down)
:|a| = |-0.794| = 0.794 m/s²
The direction of the bird's acceleration is in the opposite direction of velocity,
South.
To calculate the velocity after an additional 2.70 s has elapsed,
we use the formula:
Final Velocity,
v = u + at Taking values from the problem,
u = 13.0 m/s
a = -0.794 m/s² (same as part a)
v = ?
t = 2.70 s
Substituting these values in the above formula,
v = 13.0 - 0.794 × 2.70s = 10.832 m/s
The final velocity of the bird after 2.70s has elapsed is 10.832 m/s.
The direction is still North.
To know more about Acceleration visit:
https://brainly.com/question/19537384
#SPJ11
If Joe Scientist has created his own temperature scale where water freezes at 57 and boils at 296, create a transformation equation that will allow you to convert celcius into his temperatures
The transformation equation to convert Celsius temperatures (C) to Joe Scientist's temperature scale (J) is:
J = 2.39C + 57
How do we calculate?In Joe Scientist's temperature scale,
water freezes = 57
water boils = 296.
In Celsius scale, water freezes at 0 and boils at 100.
To convert Celsius temperatures (C) to Joe Scientist's scale temperatures (J), we can use a linear transformation equation.
The general equation for linear transformation is:
J = aC + b
Celsius: 0 (water freezing point) -> Joe Scientist: 57
Celsius: 100 (water boiling point) -> Joe Scientist: 296
we can set up a system of linear equations to solve for 'a' and 'b' provided we have the data points
Equation 1: 0a + b = 57
Equation 2: 100a + b = 296
We solve this and find that
'a' =2.39
'b'= 57.
Learn more about linear equations at:
https://brainly.com/question/2030026
#SPJ4
A dry cell having internal resistance r = 0.5 Q has an electromotive force & = 6 V. What is the power (in W) dissipated through the internal resistance of the cell, if it is connected to an external resistance of 1.5 Q?
I. 4.5 II. 5.5 III.3.5 IV. 2.5 V. 6.5
The power (in W) dissipated through the internal resistance of the cell, if it is connected to an external resistance of 1.5 Q is 4.5 W. Hence, the correct option is I. 4.5.
The expression for the power (in W) dissipated through the internal resistance of the cell, if it is connected to an external resistance of 1.5 Q is as follows:
Given :The internal resistance of a dry cell is `r = 0.5Ω`.
The electromotive force of a dry cell is `ε = 6 V`.The external resistance is `R = 1.5Ω`.Power is given by the expression P = I²R. We can use Ohm's law to find current I flowing through the circuit.I = ε / (r + R) Substituting the values of ε, r and R in the above equation, we getI = 6 / (0.5 + 1.5)I = 6 / 2I = 3 A Therefore, the power dissipated through the internal resistance isP = I²r = 3² × 0.5P = 4.5 W Therefore, the power (in W) dissipated through the internal resistance of the cell, if it is connected to an external resistance of 1.5 Q is 4.5 W. Hence, the correct option is I. 4.5.
To know more about internal resistance visit
https://brainly.com/question/23575577
#SPJ11
A coin is launched from a height of 1.8 meters at a 50 degree angle above the horizontal. Ignoring air resistance, the vertical component of its velocity is O A. constant. O B zero O C. always negative. O D. positive
A coin is launched from a height of 1.8 meters at a 50 degree angle above the horizontal.
Ignoring air resistance, the vertical component of its velocity is always negative.
Explanation:
In the given problem, a coin is launched from a height of 1.8 meters at a 50-degree angle above the horizontal.
We have to determine the vertical component of its velocity.
Let's start the solution.
Step-by-step solution:
The vertical component of velocity is given by the following equation:
v = v₀sinθ
where v₀ = initial velocity of the object
θ = the angle of the projectile
We are given that the angle of the projectile is 50 degrees.
Therefore, the vertical component of velocity will be:
v = v₀sin(50°)
Now, we have to decide the sign of the vertical component of velocity.
Since the object is launched upwards and is then influenced by the force of gravity, the velocity will be decreasing.
Therefore, the vertical component of velocity is always negative.
To know more about projectile, visit:
https://brainly.com/question/25928005
#SPJ11
Two transverse waves y1 = 2 sin(2rt - rix) and y2 = 2 sin(2mtt - tx + Tt/2) are moving in the same direction. Find the resultant amplitude of the interference
between these two waves.
Two transverse waves y1 = 2 sin(2rt - rix) and y2 = 2 sin(2mtt - tx + Tt/2) are moving in the same direction.The resultant amplitude of the interference between the two waves is 4.
To find the resultant amplitude of the interference between the two waves, we can use the principle of superposition. The principle states that when two waves overlap, the displacement of the resulting wave at any point is the algebraic sum of the individual displacements of the interfering waves at that point.
The two waves are given by:
y1 = 2 sin(2rt - rix)
y2 = 2 sin(2mtt - tx + Tt/2)
To find the resultant amplitude, we need to add these two waves together:
y = y1 + y2
Expanding the equation, we get:
y = 2 sin(2rt - rix) + 2 sin(2mtt - tx + Tt/2)
Using the trigonometric identity sin(A + B) = sin(A)cos(B) + cos(A)sin(B), we can simplify the equation further:
y = 2 sin(2rt)cos(rix) + 2 cos(2rt)sin(rix) + 2 sin(2mtt)cos(tx - Tt/2) + 2 cos(2mtt)sin(tx - Tt/2)
Since the waves are moving in the same direction, we can assume that r = m = 2r = 2m = 2, and the equation becomes:
y = 2 sin(2rt)cos(rix) + 2 cos(2rt)sin(rix) + 2 sin(2rtt)cos(tx - Tt/2) + 2 cos(2rtt)sin(tx - Tt/2)
Now, let's focus on the terms involving sin(rix) and cos(rix). Using the trigonometric identity sin(A)cos(B) + cos(A)sin(B) = sin(A + B), we can simplify these terms:
y = 2 sin(2rt + rix) + 2 sin(2rtt + tx - Tt/2)
The resultant amplitude of the interference can be obtained by finding the maximum value of y. Since sin(A) has a maximum value of 1, the maximum amplitude occurs when the arguments of sin functions are at their maximum values.
For the first term, the maximum value of 2rt + rix is when rix = π/2, which implies x = π/(2ri).
For the second term, the maximum value of 2rtt + tx - Tt/2 is when tx - Tt/2 = π/2, which implies tx = Tt/2 + π/2, or x = (T + 2)/(2t).
Now we have the values of x where the interference is maximum: x = π/(2ri) and x = (T + 2)/(2t).
To find the resultant amplitude, we substitute these values of x into the equation for y:
y_max = 2 sin(2rt + r(π/(2ri))) + 2 sin(2rtt + t((T + 2)/(2t)) - Tt/2)
Simplifying further:
y_max = 2 sin(2rt + π/2) + 2 sin(2rtt + (T + 2)/2 - T/2)
Since sin(2rt + π/2) = 1 and sin(2rtt + (T + 2)/2 - T/2) = 1, the resultant amplitude is:
y_max = 2 + 2 = 4
Therefore, the resultant amplitude of the interference between the two waves is 4.
To learn more about amplitude visit: https://brainly.com/question/3613222
#SPJ11
A 9.7-V battery, a 5.03- resistor, and a 10:2-H inductor are connected in series. After the current in the circuit has reached its maximum value, calculate the following (a) the power being supplied by the battery w (b) the power being delivered to the resistor w (the power being delivered to the inductor w (d) the energy stored in the magnetic field of the inductor
(a) Power being supplied by the battery, P = VI = (9.7)I
(b) Power delivered to the resistor = (I² × 5.03)
(c) The power delivered to the inductor is zero.
(d) The energy stored in the magnetic field of the inductor is 1/2 × 10.2 × I² joules.
(a) Power is equal to voltage multiplied by current.
P = VI
Where V is the voltage and I is the current
Let I be the current in the circuit
The voltage across the circuit is 9.7 V.
The circuit has only one current.
Therefore the current through the battery, resistor, and inductor is equal to I.
I = V / R
Where R is the total resistance in the circuit.
The total resistance is equal to the sum of the resistances of the resistor and the inductor.
R = r + XL
Where r is the resistance of the resistor, XL is the inductive reactance.
Inductive reactance, XL = ωLWhere ω is the angular frequency.ω = 2πf
Where f is the frequency.
L is the inductance of the inductor. L = 10:2 H = 10.2 H.XL = 2πfLω = 2πf10.2I = V / R = 9.7 / (r + XL)
Substituting values
I = 9.7 / (5.03 + 2πf10.2)
Power, P = VI = (9.7)I
(b) Power is equal to voltage squared divided by resistance.
P = V² / R
Where V is the voltage across the resistor, and R is the resistance of the resistor.
Voltage across the resistor, V = IRV = I × 5.03P = (I × 5.03)² / 5.03P = (I² × 5.03)
(c) The power delivered to the inductor is zero. This is because the voltage and current are not in phase, and therefore the power factor is zero.
(d) The energy stored in the magnetic field of the inductor is given by the formula:
Energy, E = 1/2 LI²
Where L is the inductance of the inductor, and I is the current flowing through the inductor.
Energy, E = 1/2 × 10.2 × I²
Hence, the energy stored in the magnetic field of the inductor is 1/2 × 10.2 × I² joules.
To know more about inductor, refer to the link below:
https://brainly.com/question/31503384#
#SPJ11
A winter coat made by Canadian manufaucturer, Canada Goose Inc, nas a thickness of 2.5 cm. The temperature on the inside nearest the body is 18 ∘
C and the outside temperature is 5.0 ∘
C. How much heat is transferred in one hour though each square meter of the goose down coat? Ignore convection and radiant losses.
The amount of heat transferred in one hour through each square meter of the goose down coat is approximately 15.6 joules.
To calculate the amount of heat transferred through each square meter of the goose down coat, we can use the formula for heat transfer through a material:
Q = k * A * (ΔT / d)
where:
Q is the amount of heat transferred,
k is the thermal conductivity of the material,
A is the area of heat transfer,
ΔT is the temperature difference across the material,
and d is the thickness of the material.
Thickness of the coat, d = 2.5 cm = 0.025 m
Inside temperature, Ti = 18 °C
Outside temperature, To = 5.0 °C
The temperature difference across the coat is:
ΔT = Ti - To = 18 °C - 5.0 °C = 13 °C
The thermal conductivity of goose down may vary, but for this calculation, let's assume a typical value of k = 0.03 W/(m·K).
The area of heat transfer, A, is equal to 1 m² (since we are considering heat transfer per square meter).
Plugging these values into the formula, we have:
Q = 0.03 * 1 * (13 / 0.025) = 15.6 W
Learn more about temperature at https://brainly.com/question/27944554
#SPJ11