check the dimensional consistencies of s =vot+1/2at2​

Answer:

it is applicable on all bodies having mass and the bodies Will be governed by the same law

Answer:

d = 1.022 [m]

Explanation:

Work in physics is defined as the product of force by distance. In this way we have the following expression.

[tex]W=F*d[/tex]

where:

W = work done = 180 [J] (units of Joules)

F = force = 176 [N]

d = distance [m]

[tex]d = W/F\\d = 180/176\\d = 1.022 [m][/tex]

Explanation:

The theory which is linked to person and climate is more concerned with Mother Nature and human's position within it. It is a misconception that humans are the most important species on this planet and they are relying on other species for their life. Conservation ethics also revolve around making human societies and habitats healthier, preserving vital resources for the present and future. This philosophical approach values the human/nonhuman interaction of nature, understanding how humans and the world have a continuing causal association with one another.

Answer:

zero

Explanation:

The linear momentum is conserved when the system is closed. Therefore, the net force is zero.

Answer:

The magnitude and direction of the force on the charge is 120 N in the direction of the charge.

Explanation:

Given;

magnitude of the charge, q = 0.6 C

electric field strength, E = 200 N/C

The magnitude of the electric force is calculated as;

F = Eq

where;

F is the magnitude of the force

Substitute the given values and solve for F;

F = (200)(0.6)

F = 120 N in the direction of the charge.

Therefore, the magnitude and direction of the force on the charge is 120 N in the direction of the charge.

Answer:

40×（9.8+2）＝432n

Explanation:

9.8m/s^2 is acceleration of gravity

Explanation:

Fnet = ma = (3kg)(8m/s²) = 24N.

50N - 24N = 26N.

Hence the frictional force is 26N.

Answer:

The displacement of Sudhir is 0.781 km.

Explanation:

Given;

initial distance, d₁ = 0.4 km = 400 m, N60.0°W

final distance, d₂ = 0.5 km

Make a sketch of Sudhir motion to form a right angled triangle;

(Check image uploaded).

Apply cosine rule to determine d "displacement"

d² = 500² + 400² - (2 x 500 x 400 x cos 120)

d² = 410,000 - (400,000 x -0.5)

d² = 410,000 - (-200,000)

d² = 410,000  + 200,000

d² = 610,000

d = √610000

d = 781.03 m

d = 0.781 km

Therefore, the displacement of Sudhir is 0.781 km.

Answer:

B. Arc blast

Explanation:

Arc blast are as a result of rapid injection of electrical energy into an arc. These shock waves and arc blast pressure wave at low level can lead to damage of eardrums at lower levels and cardiac arrest at high levels.

Strong magnetic fields created by high currents (> 100 kA) can result to equipment destruction. These arc blast hazards are mostly found in high-energy power circuits and large capacitor banks.

Answer:

weight of the person and reaction force according to that weight by the elevator

every action has an equal and opposite reaction

Weight of the person and reaction force according to that weight by the elevator is balanced.

According to the third law, when two objects interact, they exert equal-sized and opposite-direction forces upon one another.

A person rides in an elivator then the equal and opposite force for the force of the elevator floor pushing up on the person as described by Newton’s third law and are balanced.

Weight of the person and reaction force according to that weight by the elevator is balanced.

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Answer:

increases the voltage output

Explanation:

By Increasing the number of turns on the generator coil , the output volatge of a generator increases. However, there are various other methods availbble to increase the output voltage of a generator. Some of these can be

1. By increasing the rpm of generator coil.

2. By using stronger magnets

Answer: 75 ft

Explanation:

Breaking distance = Speed²/ 20

= 30²/20

= 45 feet

Stopping distance = Speed + braking distance

= 30 + 45

= 75 ft

Answer:

Final speed of security car v = 65 m/s

Explanation:

Given:

Speed of race car u1 = 35m/s

Speed of security car u2 = 5 m/s

Acceleration = 5 m/s²

Find:

Final speed of security car v

Computation:

Assume, they chase S meter

So

S = u1t + [1/2]at²

S = 35t

S = u2t + [1/2]at²

so,

35t = 5t +  [1/2](5)t²

t = 12 s

So

v = u + at

v = 5 + 5(12)

Final speed of security car v = 65 m/s

Answer:

This is due to a relative decrease in atmospheric pressure in high places.

Explanation:

Given that atmospheric pressure decreases at the higher point or ground, this reduced atmospheric pressure, however, will be unable to contain the Mercury in the barometer tube.

Therefore, at the top of the mountain where the air pressure is low, the barometer reading ultimately goes down.

Hence, the level of mercury falls in a barometer while taking it to a mountain "due to a relative decrease in atmospheric pressure in high places."

Answer:

biking

Explanation:

To make the Bike move you peddle with your legs.

Answer:

I tried...

Explanation:

Assuming the English system of mass and weight is the same as the Imperial system, the measurements are:

• 1 pound (lb) = 16 ounces (oz)

• 2,000 pounds (lbs) = 1 ton (T)

I think that's everything?

In the English system, mass is measured in pounds and weight is also measured in pounds. However, it is important to understand the difference between mass and weight.

Mass is a measure of the amount of matter in an object and is a scalar quantity. It does not change with location or gravitational force. In the English system, mass is typically measured using a scale or balance, which compares the object's mass to a standard mass. The pound (lb.) is the unit of mass in the English system.

Weight, on the other hand, is a measure of the force exerted on an object due to gravity and is a vector quantity. It depends on the object's mass and the gravitational force acting on it. In the English system, weight is typically measured using a spring scale or a balance that incorporates a spring. The pound (lb.) is also used as the unit of weight in the English system.

Weight = Mass x Acceleration due to gravity

Mass is measured in pounds (lb.) and weight is also measured in pounds (lb.).It is important to note that weight can vary depending on the gravitational force acting on an object.

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Answer:

10.90km

Explanation:

Magnitude of the total displacement is expressed using the equation

d = √dx²+dy²

dx is the horizontal component of the displacement

dy is the vertical component of the displacement

dy = -6.7sin27°

dy = -6.7(0.4539)

dy = -3.042

For the  horizontal component of the displacement

dx = -4.5 - 6.7cos27

dx = -4.5 -5.9697

dx = -10.4697

Get the magnitude of the bicyclist's total displacement

Recall that: d = √dx²+dy²

d = √(-3.042)²+(-10.4697)²

d = √9.2538+109.6146

d = √118.8684

d = 10.90km

Hence the magnitude of the bicyclist's total displacement is 10.90km

The bicyclist magnitude of displacement is equal to 9.62m

To find the resultant magnitude of the bicyclist total displacement, we have to find the x and y component.

For the first direction, the components are

[tex]x_1 = -4.5i[/tex]

sine we don't have any vertical displacement, the y-component is equal to zero.

for the second direction,

[tex]x_2 = -6.7sin27i\\y_2= 6.7cos27j[/tex]

The resultant x and y component are;

Let's find the magnitude of displacement

[tex]R = \sqrt{R_x^2 + R_x^2}\\R = \sqrt{(-7.54)^2 + (5.97)^2 }\\\\R = 9.62m[/tex]

The bicyclist magnitude of displacement is equal to 9.62m

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Answer:

O Intense rain or an earthquake

Explanation:

Landslides can be initiated in slopes already on the verge of movement by rainfall, snowmelt, changes in water level, stream erosion, changes in ground water, earthquakes, volcanic activity, disturbance by human activities, or any combination of these factors.

Intense rain or an earthquake can trigger a landslide.

In conclusion, intense rain or an earthquake can trigger a landslide.

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Answer:

Power = 1200 [W].

Explanation:

The efficiency of an electrical equipment is defined as the relationship between the power realized, over the power that is consumed. For this case, they give us the data of consumed power and efficiency in this way we can calculate the power that the equipment performs.

[tex]Efficency=\frac{Power_{done}}{P_{consumed}}\\0.8 = \frac{Power_{done}}{1500} \\Power_{done}=1500*0.8\\Power_{done} = 1200 [W][/tex]

This means that of the 1500 [W], 1200 [W] are actually used to get the job done. This is established by means of the first law of thermodynamics.

Answer:

0.4329 seconds

Explanation:

We are given;

Distance; d = 0.635 m

Velocity; v = 3.22 m/s

Angle; θ = 62.9°

To find the time, we have to find the horizontal component of the velocity.

Thus, Vx = 3.22 × cos 62.9

Formula for time is;

t = d/Vx

t = 0.635/(3.22 × cos 62.9)

t = 0.4329 sec

Thus the time he will take to clear the hurdle is 0.4329 sec

Answer:

your pretty no matter what others say

Explanation:

Answer:

two bros chillin in a hot tub five feet apart cuz there not gay

Explanation:

do you remember this vine

Answer:

is it 3?

Explanation:

Im taking a guess and just dividing 6 and 2

Answer:

The answer is "DACB".

Explanation:

The missing data of the question is defined in the attached file please find it.

Using formula:

[tex]\to F= m \cdot a\\\\ \to m= 5 \ kg[/tex]

In object A:

[tex]F= 15 \\\\a =\frac{F}{m} = \frac{15}{5} = 3[/tex]

In object B:

[tex]F= 30 \\\\a =\frac{F}{m} = \frac{30}{5} = 6[/tex]

In object C:

[tex]F= 20 \\\\a =\frac{F}{m} = \frac{20}{5} = 4[/tex]

In object D:

[tex]F= 0 \\\\a =\frac{F}{m} = \frac{0}{5} = 30[/tex]

That's why the answer is "DACB" .

Let r be the distance between the man and point Q. He applies a torque of

(r i ) × ((-800 N) j ) = ((-800 N) r ) k

pointing "into the page" with magnitude (800 N) r.

Meanwhile, the rope applies a torque of

((3.0 m) i ) × ((500 N) j ) = (1500 N•m) k

pointing out of the "page" with mag. 1500 N•m

The beam is held in place in a horizontal position, so the torques cancel and

(800 N) r = 1500 N•m

r = (1500 N•m)/(800 N) = 1.875 m ≈ 1.9 m

I HAVE ATTACHED A FILE..

Please find the attached photograph for your answer

Answer: C. electricity and magnetism  

Explanation:

Answer:

B.

electricity and magnetism

is the ans

I find this in physics

Answer:

In the wild, clownfish rarely leave their anemone home. In fact, part of its purpose is to defend the anemone from other fish. However, clownfish bred in aquariums (without an anemone home) may still have this instinct, but it’s much calmer than wild harvested species.

Explanation:

Answer:

a) The initial speed of the projectile is approximately 42.410 meters per second.

b) The speed of the projectile after 4 seconds is approximately 21.352 meters per second.

c) The horizontal range of the projectile is 169.64 meters.

d) The maximum height of the projectile is 68.775 meters.

e) The speed of the projectile when it landed on the ground is approximately 46.807 meters per second.

Explanation:

According to the statement, the projects shows a parabolic motion, which consists in the combination of horizontal uniform motion and vertical uniformly accelerated motion due to gravity. This motion is represented by the following equations of motion:

[tex]x = x_{o} + v_{o}\cdot t\cdot \cos \theta[/tex] (1)

[tex]y = y_{o} + v_{o}\cdot t\cdot \sin \theta + \frac{1}{2}\cdot g\cdot t^{2}[/tex] (2)

Where:

[tex]x_{o}[/tex], [tex]x[/tex] - Initial and current horizontal position, measured in meters.

[tex]y_{o}[/tex], [tex]y[/tex] - Initial and current vertical position, measured in meters.

[tex]\theta[/tex] - Launch angle, measured in sexagesimal angle.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]t[/tex] - Time, measured in second.

a) By using (2) and knowing that [tex]y_{o} = 20\,m[/tex], [tex]y = 0\,m[/tex], [tex]t = 8\,s[/tex], [tex]\theta = 60^{\circ}[/tex] and [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], then initial speed of the projectile is:

[tex]v_{o}\cdot t \cdot \sin \theta = y-y_{o}-\frac{1}{2}\cdot g\cdot t^{2}[/tex]

[tex]v_{o} = \frac{y-y_{o}-\frac{1}{2}\cdot g\cdot t^{2} }{t\cdot \sin \theta}[/tex]

[tex]v_{o} = \frac{0\,m-20\,m-\frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right)\cdot (8\,s)^{2} }{(8\,s)\cdot \sin 60^{\circ}}[/tex]

[tex]v_{o} \approx 42.410\,\frac{m}{s}[/tex]

The initial speed of the projectile is approximately 42.410 meters per second.

b) The vertical component of the velocity of the projectile is determine by differentiating (2) in time and substitute all known values:

[tex]v_{y} = v_{o}\cdot \sin \theta +g\cdot t[/tex] (3)

([tex]v_{o} \approx 42.410\,\frac{m}{s}[/tex], [tex]\theta = 60^{\circ}[/tex], [tex]g = -9.807\,\frac{m}{s^{2}}[/tex] and [tex]t = 4\,s[/tex])

[tex]v_{y} = -2.5\,\frac{m}{s}[/tex]

The horizontal component of the velocity of the projectile is:

[tex]v_{x} = v_{o}\cdot \cos \theta[/tex]

[tex]v_{x} = 21.205\,\frac{m}{s}[/tex]

And the speed of the projectile is determined by Pythagorean Theorem:

[tex]v = \sqrt{v_{x}^{2}+v_{y}^{2}}[/tex]

[tex]v = \sqrt{\left(21.205\,\frac{m}{s} \right)^{2}+\left(-2.5\,\frac{m}{s} \right)^{2}}[/tex]

[tex]v \approx 21.352\,\frac{m}{s}[/tex]

The speed of the projectile after 4 seconds is approximately 21.352 meters per second.

c) By (1) we find the horizontal range of the projectile:

([tex]x_{o} = 0\,m[/tex], [tex]v_{o} \approx 42.410\,\frac{m}{s}[/tex], [tex]\theta = 60^{\circ}[/tex], [tex]g = -9.807\,\frac{m}{s^{2}}[/tex] and [tex]t = 8\,s[/tex])

[tex]x = 0\,m + \left(42.410\,\frac{m}{s} \right)\cdot (8\,s)\cdot \cos 60^{\circ}[/tex]

[tex]x = 169.64\,m[/tex]

The horizontal range of the projectile is 169.64 meters.

d) The projectile reaches its maximum height when velocity is zero. By (3) and knowing that [tex]v_{y} = 0\,\frac{m}{s}[/tex], [tex]v_{o} \approx 42.410\,\frac{m}{s}[/tex] and [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], the time associated with maximum height is:

[tex]0\,\frac{m}{s} = \left(42.410\,\frac{m}{s}\right)\cdot \sin 60^{\circ}+\left(-9.807\,\frac{m}{s^{2}} \right) \cdot t[/tex]

[tex]t = 3.745\,s[/tex]

And by (2) and knowing that [tex]y_{o} = 20\,m[/tex], [tex]v_{o} \approx 42.410\,\frac{m}{s}[/tex], [tex]t = 3.745\,s[/tex], [tex]\theta = 60^{\circ}[/tex] and [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], the maximum height reached by the projectile is:

[tex]y = 20\,m + \left(42.410\,\frac{m}{s} \right)\cdot (3.745\,s)\cdot \sin 60^{\circ}+\frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right)\cdot (3.745\,s)^{2}[/tex]

[tex]y = 68.775\,m[/tex]

The maximum height of the projectile is 68.775 meters.

e) If we know that [tex]y_{o} = 20\,m[/tex], [tex]v_{o} \approx 42.410\,\frac{m}{s}[/tex], [tex]t = 8\,s[/tex], [tex]\theta = 60^{\circ}[/tex] and [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], the components of the speed are, respectively:

[tex]v_{y} = \left(42.410\,\frac{m}{s}\right)\cdot \sin 60^{\circ} + \left(-9.807\,\frac{m}{s^{2}} \right)\cdot (8\,s)[/tex]

[tex]v_{y} = -41.728\,\frac{m}{s}[/tex]

[tex]v_{x} = v_{o}\cdot \cos \theta[/tex]

[tex]v_{x} = 21.205\,\frac{m}{s}[/tex]

And the speed of the projectile is determined by Pythagorean Theorem:

[tex]v = \sqrt{v_{x}^{2}+v_{y}^{2}}[/tex]

[tex]v = \sqrt{\left(21.205\,\frac{m}{s} \right)^{2}+\left(-41.728\,\frac{m}{s} \right)^{2}}[/tex]

[tex]v \approx 46.807\,\frac{m}{s}[/tex]

The speed of the projectile when it landed on the ground is approximately 46.807 meters per second.

Answer:

The answer is C. Ralph: “I’m not sure about bananas. I’d have to think about it.”

Explanation:

I did the practice.

Answer:

C.) Ralph: "I'm not sure about bananas. I'd have to think about it."

Explanation:

Just took the practice

Answer:

Organs are made of collections of tissues, which are groups of cells.

Explanation: