DNA and RNA both use the same types of nucleotides

Answers

Answer 1

Answer:

No

Explanation:

In the nucleotide of DNA and RNA only Phosphate that is similar to both nucleic acid, They have different sugar portion and Nitrogenous base.

DNA nucleotide include

- Phosphate

- deoxyribose sugar

- NB Adenine, Thymine, Guanine and Cytosine

RNA nucleotide include

- Phosphate

- Ribose sugar

- NB Adenine, Uracil, Guanine and Cytosine

Therefore They do not use the same types of nucleotides because DNA has 2 strand that are joined together by weak hygrogen bond and it is long. while RNA has 1 strand and it is a short thus not coiled or helical.


Related Questions

41 3 points The part of the female reproductive system "lost" during menstruation is? A Myometrium o B. Stratum functionalis of the endometrium.. C. Stratum basalis of the endometrium D. Germinal epithelium 42 8 О О О О О 3 points Sexual excitation, erection, and orgasm is a function of: A Sympathetic reflexia. B. Parasympathetic reflexia. C. Both A and B. D. Neither Anor B. E. Precentral gyrus 43 3 points In Oogenesis, the first meiotic division occurs: A. During prenatal development of a female child. B. When the oocyte is fertilized. C. Upon ovulation of the oocyte. D. Monthly in response to FSH and LH. 44 3 points The uterine tubes: A. Transportova. B. Provide a site for normal fertilization. C. Provides a site for normal implantation D. All of the above. O E. Only two of the above.

Answers

41) The part of the female reproductive system "lost" during menstruation is the stratum functionalis of the endometrium.

42)

Sexual excitation, erection, and orgasm are functions of both the sympathetic and parasympathetic nervous systems (C).

The first meiotic division in oogenesis occurs during prenatal development of a female child (A).

The uterine tubes have multiple functions, including the transportation of ova, providing a site for normal fertilization, and potentially serving as a site for normal implantation (D).

Sexual reproduction

Sexual excitation, erection, and orgasm are functions of both sympathetic reflexia and parasympathetic reflexia. Both the sympathetic and parasympathetic nervous systems play a role in the sexual response, with the sympathetic system being responsible for sexual arousal and erection, and the parasympathetic system being involved in orgasm.

In Oogenesis, the first meiotic division occurs during prenatal development of a female child. Oogenesis begins during prenatal development, where oogonia undergo the first meiotic division to form primary oocytes. This process is initiated before birth and remains arrested until puberty.

The uterine tubes, also known as fallopian tubes, have multiple functions. They transport ova from the ovaries to the uterus, providing a site for normal fertilization where sperm can meet the egg, and also serve as a possible site for normal implantation of a fertilized egg.

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Which of the following is FALSE? a. Biological membranes usually contain lipids, proteins, and carbohydrates. b. Proteins can allow specific molecules to cross membranes. c. Simple membranes are impermeable to other molecules. d. Membrane are held together noncovalently. e. Membranes are two molecules thick.

Answers

The false statement is (c) Simple membranes are impermeable to other molecules.

Simple membranes are not impermeable to other molecules. Biological membranes, including cell membranes, are selectively permeable, meaning they allow certain molecules to pass through while restricting the passage of others. This is facilitated by various mechanisms such as protein channels, transporters, and receptors embedded within the membrane. These proteins can facilitate the transport of specific molecules across the membrane, allowing for the necessary exchange of substances between the cell and its environment.

Therefore, option C is the false statement.

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5) What is diffusion and give a specific example of diffusion that occurs within the h body (example can be simple or facilitated diffusion). How is active transport different from diffusion? Give a specific example of an active transport mechanism/action within the body.

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Diffusion is a process that takes place in a fluid when the molecules move from a high concentration area to a low concentration area. A specific example of diffusion that occurs within the human body is the movement of oxygen and carbon dioxide in and out of the cells.

Oxygen molecules move from high concentration areas in the lungs to low concentration areas in the bloodstream and then to low concentration areas in the cells, while carbon dioxide moves from high concentration areas in the cells to low concentration areas in the bloodstream and then to high concentration areas in the lungs. Active transport, on the other hand, requires the use of energy to move molecules from a low concentration area to a high concentration area. One example of active transport within the human body is the process by which sodium and potassium ions are transported across the cell membrane using ATP (adenosine triphosphate). This process is vital for nerve impulse transmission and muscle contraction.

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the specific name for serosa lining organs of the abdominal cavity is: parietal peritoneum parietal pericardium visceral peritoneum visceral pleura

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The specific name for serosa lining organs of the abdominal cavity is visceral peritoneum.

The abdominal cavity's organs are coated by the serosa, which is a double-layered membrane. The outer layer of the membrane is the parietal peritoneum, which lines the abdominal cavity's wall. On the other hand, the inner layer is the visceral peritoneum, which wraps around and covers the abdominal organs' outer surface. The peritoneum's serous fluid acts as a lubricant, allowing the organs to move freely against one another and the cavity wall.

The peritoneum connects organs to one another and to the abdominal wall, forming mesenteries that anchor them in place. The peritoneum's main function is to protect the abdominal organs by reducing friction between them and the abdominal wall. It also provides a passageway for blood vessels, nerves, and lymphatics that supply the abdominal organs.

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Which of the following statements is true. a. When the blood becomes too acidic, the anion chloride is reabsorbed by the kidneys b. Chloride has the ablility to restore blood pH because it is an anion. c. Bicarbonate is reabsorbed by the kdneys because it has the ability to restore blood pH. d. Both chlorid and bicarbonate have the ability to restore blood pH so they are both reabsorbed by the kidneys

Answers

The true statement is "Bicarbonate is reabsorbed by the kidneys because it has the ability to restore blood pH". Option C is the correct statement.

Bicarbonate plays a crucial role in maintaining blood pH within a normal range. When the blood becomes too acidic, bicarbonate acts as a buffer and helps restore the pH balance. The kidneys play a vital role in regulating blood pH by reabsorbing bicarbonate ions from the filtrate and returning them to the bloodstream. This process helps maintain the acid-base balance in the body. Chloride, on the other hand, does not directly restore blood pH and is primarily involved in maintaining electrolyte balance. Therefore, option C is the correct statement.

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Please answer and explain in 10 sentences.
1. Discuss the homology in the appendicular and
branchiomeric musculature across the different vertebrate
groups.

Answers

Homology refers to the similarity in anatomical structures or traits among different species, suggesting a common evolutionary origin. When considering the appendicular and branchiomeric musculature across vertebrate groups, we can observe both homologous and non-homologous structures.

Appendicular Musculature:

The appendicular musculature, which includes the muscles of the limbs, shows a high degree of homology across vertebrate groups. Despite variations in size, shape, and function, the basic organization and arrangement of muscles remain similar. For example, the presence of flexor and extensor muscles, their attachment sites, and their actions at specific joints are conserved across vertebrates.

Branchiomeric Musculature:

The branchiomeric musculature, which develops from the branchial arches, exhibits both homology and variation across vertebrate groups. Some muscles associated with feeding, respiration, vocalization, and facial expression are homologous and have similar functions. However, there are also species-specific adaptations and modifications in these muscles to suit specific ecological niches and behaviors. For instance, the specific muscles involved in jaw movements, gill cover control, or beak manipulation may vary in different groups.

Overall, homology is evident in the basic organization and functional characteristics of the appendicular musculature across vertebrate groups. In contrast, the branchiomeric musculature shows both homology and variation due to the evolutionary diversification and adaptations of these muscles in response to different ecological and functional demands. Understanding the homology in these muscle systems helps us trace the evolutionary relationships and adaptations of vertebrate species.

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AMH Part 3: Describe a mechanism that would cause an XX fetus with ovaries to develop the same internal genitalia and external genitalia found in the XY fetus with the AMH mutation in part 2

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In individuals with two X chromosomes, the absence of the SRY gene on the Y chromosome, which encodes the testis-determining factor (TDF), results in the development of ovaries.

In individuals with an XY genotype, the SRY gene is present, and testes develop instead of ovaries. The testes generate the hormone anti-Müllerian hormone (AMH), which suppresses the development of the Müllerian ducts in the fetus. The Wolffian ducts, which develop into male internal reproductive structures, develop as a result of the secretion of testosterone from the testes. Gonadal sex reversal occurs when the ovaries or testes do not form appropriately, resulting in the development of internal and external genitalia that are opposite to the individual's karyotype. When an XX individual develops as a male, it is known as XX male syndrome, while when an XY individual develops as a female, it is known as XY female syndrome.

A genetic disorder caused by mutations in the testis-determining factor (TDF) gene on the Y chromosome can cause individuals with an XX genotype to develop as males with male external and internal genitalia. Furthermore, the presence of anti-Müllerian hormone (AMH) in XX fetuses can result in the suppression of the Müllerian ducts, which leads to the development of male internal genitalia. The development of female internal and external genitalia is inhibited by the absence of the SRY gene and the lack of testosterone and AMH in XX fetuses with ovaries. When an XX fetus lacks anti-Müllerian hormone and testosterone, it may develop both male internal and external genitalia.

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Exercise-induced asthma O goes away by adulthood. O occurs only rarely. O is the intrinsic form. O is related to an allergy

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Exercise-induced asthma is related to an allergy, meaning it is triggered by specific allergens or hypersensitivity reactions during physical activity.

Exercise-induced asthma refers to the narrowing of airways and difficulty breathing that is triggered by physical exertion. It is a specific form of asthma that occurs during or after exercise. While some individuals may outgrow asthma symptoms, exercise-induced asthma can persist into adulthood for many people. It is characterized by the constriction of airway muscles and inflammation in response to physical activity. The exact cause of exercise-induced asthma is not fully understood, but it is believed to be related to underlying allergies or hypersensitivity to certain triggers, such as pollen, cold air, or pollutants. The release of histamines and other chemicals during exercise can lead to airway inflammation and bronchoconstriction, causing asthma symptoms. Proper management of exercise-induced asthma involves identifying triggers, using preventive medications, warming up before exercise, and maintaining good overall asthma control.

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Question 12 2 pts Which of the following is most likely to be involved in portal circulation? O glucose, galactase, fructase O starches O glucose, galactose, fructose O glycogen

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The most likely substances to be involved in portal circulation are glucose, galactose, and fructose.

Portal circulation refers to the movement of blood from the gastrointestinal tract to the liver through the portal vein. This specialized circulation allows the liver to receive nutrients, metabolites, and other substances absorbed from the digestive system before they reach the systemic circulation. Among the given options, glucose, galactose, and fructose are simple sugars that are commonly found in the diet and are absorbed from the gastrointestinal tract.

These sugars are transported via the portal vein to the liver, where they undergo further metabolism and regulation. Starches and glycogen are polysaccharides that are broken down into glucose molecules before absorption and subsequent entry into the portal circulation.

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QUESTION 3 Which of the following is not influenced by a change in the pH of body fluids? A. All of these would be affected B. enzyme activity. C. nerve and muscle excitability. D. potassium excretion. E. protein shape and activity.

Answers

The correct answer to the given question above is option D. Potassium excretion is not influenced by a change in the pH of body fluids.

What are body fluids? The term body fluids refer to all the liquids that are present within the body of an organism. These fluids include the blood, urine, saliva, cerebrospinal fluid, synovial fluid, and others. What is pH? pH is the measure of how acidic or basic a substance is. It is measured on a scale of 0 to 14, where 0 is the most acidic, and 14 is the most basic.

A pH of 7 is neutral. The pH of body fluids is important to maintain homeostasis. The pH of blood, for example, should be between 7.35 and 7.45.What is homeostasis? Homeostasis is the ability of the body to maintain a stable internal environment despite changes in the external environment. It involves maintaining the pH, temperature, blood sugar levels, and other variables within a narrow range to keep the body functioning properly.

 The following is not influenced by a change in the pH of body fluids: Option D. Potassium excretion.

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During your shift in the ER, a 21-year old noncompliant male with a history of type I (insulin-dependent) diabetes mellitus was found in a coma. Your triage assessment and the lab testing revealed the following:
Hyperglycemia: High blood glucose.
High urine glucose.
High urine ketones and serum ketones.
Low serum bicarbonate <12 mEq/L.
Exaggerated respiration.
Breath has acetone odor.
Hypotensive: blood pressure was 90/60 mm Hg.
Tachycardia: Pulse weak and rapid (120 bpm).
Based on your understanding of both the respiratory and renal regulation of blood pH, answer the following:
1. Is this patient experiencing respiratory or metabolic acidosis?
2. Based on your answer to #1, discuss the mechanism(s) which led to this complication.
3. The formula below represents the respiratory & renal systems' regulation of acid-base balance (remember that the enzyme carbonic anhydrase catalyzes the forward reaction between carbon dioxide and water).

Answers

The patient is experiencing metabolic acidosis, likely caused by diabetic ketoacidosis (DKA) in the context of uncontrolled diabetes. Metabolic acidosis is characterized by a decrease in serum bicarbonate levels. Prompt medical intervention is essential to treat DKA, restore acid-base balance, and prevent complications.

1. The patient is experiencing **metabolic acidosis**.

2. In metabolic acidosis, the primary disturbance is a decrease in serum bicarbonate (HCO3-) levels, which is evident in this case with low serum bicarbonate (<12 mEq/L). Metabolic acidosis can occur due to several factors, but in the context of a patient with type I diabetes mellitus, the most likely cause is diabetic ketoacidosis (DKA). DKA is a severe complication of uncontrolled diabetes characterized by high blood glucose levels, the production of ketones (ketosis), and metabolic acidosis. In this case, the elevated urine glucose and ketones, along with the acetone odor on the breath, suggest the presence of DKA.

Insufficient insulin levels lead to a relative lack of glucose utilization by cells, resulting in increased lipolysis and ketone production. The accumulation of ketones (such as acetoacetate and beta-hydroxybutyrate) leads to an increased production of hydrogen ions, contributing to metabolic acidosis.

3. The formula that represents the respiratory and renal systems' regulation of acid-base balance is the Henderson-Hasselbalch equation:

pH = pKa + log ([HCO3-] / [CO2])

This equation relates the pH (acidity), pKa (acid dissociation constant), bicarbonate (HCO3-) concentration, and carbon dioxide (CO2) concentration in the blood. The enzyme carbonic anhydrase catalyzes the reaction between carbon dioxide and water, resulting in the formation of carbonic acid (H2CO3), which then dissociates into bicarbonate ions and hydrogen ions.

The ratio of bicarbonate to carbon dioxide is important for maintaining the acid-base balance. Changes in bicarbonate levels (metabolic component) or carbon dioxide levels (respiratory component) can influence blood pH. In the case of metabolic acidosis, there is a decrease in bicarbonate levels, leading to a decrease in pH.

It is worth noting that immediate medical attention is required for the patient in the scenario described, as diabetic ketoacidosis is a medical emergency. Prompt treatment, including insulin administration, fluid replacement, and correction of electrolyte imbalances, is necessary to restore acid-base balance and prevent further complications.

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Scenario D . June is a young female aged 22. Since adolescence, she has kept fit, with an exclusive aerobic training program at her local indoor gym. She is currently studying at University and is planning on being a life long learner. She follows a low protein diet as her grandma insists this diet is the key to a long life. She plans on living this lifestyle for the rest of her life. I. Describe how June's lifestyle has helped her maximize her physiological and cognitive functions and may provide physiological/cognitive benefits during aging. II. Considering her current lifestyle, what modifications could June make for the rest of her life to ensure she ages successfully?

Answers

June should ensure that she gets sufficient sleep each night to help her maintain her health and prevent illnesses. Maintaining sleep hygiene, such as limiting technology use in the bedroom, can help promote restful sleep.

June's lifestyle has helped her maximize her physiological and cognitive functions and may provide physiological/cognitive benefits during aging in the following ways:

Maximizing Physiological Benefits of June's Lifestyle:June's lifestyle can maximize the following

physiological benefits:Boosts Cardiovascular Functioning: Her aerobic training program promotes a healthy cardiovascular system by helping her to maintain a healthy weight and improve her cholesterol levels. Promotes Muscular Strength and Endurance: Her workout program can help her to develop her muscular strength and endurance.

Helps in Regulating Hormonal Balance: The physical activity of her lifestyle can stimulate hormonal secretions to keep them in balance. Enhances Respiratory Function: June's exercise regimen can help improve her lung capacity and function to keep her active.

Maximizing Cognitive Benefits of June's Lifestyle: June's lifestyle can help maximize the following cognitive benefits: Improves Mental Functioning: Aerobic exercise can help keep the brain healthy and active, enhancing cognitive skills such as memory, attention, and reasoning.

Decreases Stress Levels: The physical activity of her lifestyle can help her cope with anxiety and depression symptoms while improving her mental health and mood .Boosts Learning and Academic Performance: Exercise has been shown to enhance learning and academic performance.

II. Considering June's current lifestyle, the following modifications could ensure that she ages successfully:Ensure Proper Protein Intake: June could eat an appropriate amount of protein to ensure that her body has sufficient protein for essential bodily functions and the maintenance of muscle mass. Increase Resistance Training: Incorporating resistance training into her exercise program would help her maintain her muscular strength and endurance, and it could be beneficial in maintaining bone health.

Maintain Cognitive Activity: June should remain intellectually engaged and mentally stimulated to help maintain cognitive function as she ages. It can be achieved by being engaged in intellectual pursuits like reading, learning, and trying new things.

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Of the various forms of nitrogen wastes animals excrete, their choice has much to do with the following factor(s) a. all of the answers are correct b. sensitivity to nitrogenous waste toxicity c. availability of water in the environment d. metabolic cost of synthesis

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Of the various forms of nitrogen wastes animals excrete, their choice has much to do with the following factor(s): sensitivity to nitrogenous waste toxicity, availability of water in the environment, and metabolic cost of synthesis. The answer is (A).

In the process of metabolism, animals produce nitrogenous waste, which must be excreted to prevent it from accumulating to toxic levels in the body. Animals excrete a range of nitrogenous waste products that differ in the amount of metabolic energy required to synthesize and the degree to which they are toxic. Nitrogenous wastes can be divided into three categories: ammonia, urea, and uric acid.

The excretory pathway used to excrete nitrogenous wastes is determined by many factors, including the availability of water, sensitivity to nitrogenous waste toxicity, and the metabolic expense of synthesizing each kind of waste product. Animals choose the type of nitrogenous waste to excrete based on their sensitivity to nitrogenous waste toxicity, the availability of water in the environment, and the metabolic cost of synthesis.

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Hydrocephalus is a buildup of cerebrospinal fluid in the ventricles of the brain. Explain why this buildup is a serious problem, and propose a sign or symptom that would indicate cerebrospinal fluid buildup

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Hydrocephalus is a medical condition where there is an excessive accumulation of cerebrospinal fluid in the brain's ventricles. The buildup of fluid is a serious problem because the increased pressure may cause brain damage, leading to cognitive and physical disabilities or even death.

A headache is a symptom of cerebrospinal fluid buildup. Cerebrospinal fluid helps to cushion the brain and spinal cord from injuries. In normal cases, it circulates in the brain and spinal cord to protect them from sudden movements and injuries. However, in hydrocephalus, the cerebrospinal fluid is unable to circulate correctly due to blockages or other reasons.

The excessive accumulation of cerebrospinal fluid leads to an enlarged head, visible in infants and younger children. In older children and adults, there may be a sudden onset of headaches, vomiting, nausea, blurred or double vision, difficulty walking, balance and coordination problems, poor coordination, and other cognitive problems, including memory loss and concentration problems.

Therefore, if one experiences a sudden headache or a headache that persists for a while, it may indicate cerebrospinal fluid buildup. It is a medical emergency, and you should seek medical attention promptly.

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Hydrocephalus is a serious condition that requires prompt treatment to avoid complications and mitigate its effects.

Hydrocephalus is a condition that occurs when there is a buildup of cerebrospinal fluid in the brain's ventricles. This buildup can cause a range of problems and can be serious if left untreated. One sign or symptom that may indicate cerebrospinal fluid buildup is a headache that worsens in intensity over time.Hydrocephalus can be caused by a range of factors, including a blockage in the ventricles, a decrease in cerebrospinal fluid absorption, or an overproduction of cerebrospinal fluid.

Regardless of the cause, the buildup of fluid in the brain can cause pressure to increase inside the skull, which can lead to a range of problems and complications.Among the most serious issues associated with hydrocephalus are brain damage, seizures, and loss of vision. As pressure increases in the brain, it can cause damage to the delicate tissues and structures inside, leading to cognitive problems, developmental delays, and other issues. Seizures are another potential complication of hydrocephalus, as the electrical activity in the brain may be disrupted due to the buildup of fluid.

Finally, the increased pressure in the brain can also lead to vision loss, particularly if it affects the optic nerves or other critical structures.In terms of identifying cerebrospinal fluid buildup, one of the most common signs is a headache that worsens over time. This is often accompanied by nausea, vomiting, and other symptoms of increased pressure inside the skull.

Other signs may include a change in vision, including double vision or loss of vision in one or both eyes. Finally, people with hydrocephalus may also experience difficulty with balance and coordination, as well as developmental delays or cognitive problems if the condition is present from birth.

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What are the 3 components of eukaryotic cells?
What is the difference between passive and active transport?
What 2 things make up the cytoplasm?
What is an organelle?
What function do the following organelles have: ribosomes, smooth endoplasmic reticulum, rough endoplasmic reticulum, mitochondria, lysosomes, nucleus

Answers

Eukaryotic cells are cells that have a nucleus and other membrane-bound organelles.

The three major components of eukaryotic cells are Plasma Membrane, Cytoplasm, and Nucleus. Active transport and passive transport are the two main types of cellular transport. Passive transport is a type of transport in which substances move across the cell membrane without the use of energy. Examples of passive transport are diffusion and osmosis.

Active transport, on the other hand, is a type of transport in which energy is required to move molecules across the cell membrane. Examples of active transport are endocytosis and exocytosis. Cytoplasm is the semifluid substance that fills a cell. Two things make up the cytoplasm: cytosol and organelles. An organelle is a specialized structure in the cytoplasm of eukaryotic cells that has a specific function. Organelles are membrane-bound and are found within the cytoplasm of eukaryotic cells.

Ribosomes are responsible for protein synthesis. The rough endoplasmic reticulum is responsible for the modification and transport of proteins. The smooth endoplasmic reticulum is responsible for lipid synthesis, detoxification, and calcium storage. Mitochondria are the powerhouses of the cell that generate ATP. Lysosomes are responsible for digestion and waste removal. The nucleus is responsible for storing genetic information and controlling the cell's activities.

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Question 2 Is part of the sympathetic nervous system. ◯ Parathyroid glands ◯ Pancreas ◯ Thyroid gland ◯ Pituitary gland (hypophysis) ◯ Adrenal medulla Necessary for coagulation. ◯ Fibrinogen ◯ Gamma globulins ◯ Alpha and beta globulins ◯ Albumin

Answers

The adrenal medulla is part of the sympathetic nervous system and Fibrinogen is necessary for coagulation. The correct option is E and A respectively.

Adrenal medulla:

The adrenal medulla is part of the sympathetic nervous system. It is located in the center of the adrenal glands.The adrenal medulla is responsible for the production and release of adrenaline (epinephrine) and noradrenaline (norepinephrine) into the bloodstream. These hormones play a crucial role in the body's response to stress and are involved in the "fight-or-flight" response.

Fibrinogen:

It is necessary for coagulation, also known as blood clotting. Fibrinogen is a protein found in the blood plasma and is synthesized in the liver.During the coagulation process, fibrinogen is converted into fibrin by the action of an enzyme called thrombin. Fibrin helps to stabilize blood clots and prevent excessive bleeding.

Thus, the correct option is E and A respectively.

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Is part of the sympathetic nervous system.

A. Parathyroid glands

B. Pancreas

C. Thyroid gland

D. Pituitary gland (hypophysis)

E. Adrenal medulla

Necessary for coagulation.

A. Fibrinogen

B. Gamma globulins

C. Alpha and beta globulins

D. Albumin

MALE REPRODUCTIVE SYSTEM PART A-Completion Add the word or words that correctly complete each of the following statements. 1. Another name for reproductive cells is 2. The name given to the male organs of reproduction is the 3 The two products of the testes are sperm cells and Suspended below the perineum is a fleshy pouch that contains the testes and is called the 5 The boundary between the two chambers of the scrotum is a raised thickening known as the 6. In the dermis of the scrotum there is a thin layer of muscle called the 7 The smooth muscle in the dermis of the scrotum contracts to give the scrotum a characteristic appearance of Within the fetus, the testes have moved into the scrotum by the end of month number The failure of the testes to descend into the scrotum is called 10 The nerves, ducts, and blood vessels emerging from the testes together form the The canal through which the spermatic cord passes into the peritoneal cavity is the The tightly coiled tubules of the testes are known as 13 Nourishing cells lining the seminiferous tubules are the On 14. The cells lying between the seminiferous tubules are 15 The interstitial cells of the testes are responsible for producing 16 The plexus formed by the union of the seminiferous tubules is the 17 Efferent ducts arising from the rete testes enter the tubule called the 18 The process through which sperm cells are produced is 19. Sperm cells are formed from primordial cells known as 20 The process of spermatogenesis takes place in the 21 The cells produced by duplication of the spermatogonia are 22 The cellular process by which spermatocytes form spermatids is called 23. Spermatids will mature to form sperm cells, also known as 24 During the process of meiosis, a spermatocyte with 46 chromosomes will produce a spermatid having chromosomes that number 25 The chromosomes of the sperm cell are packed into the region of the cell known as the 26. Enzymes important in fertilization are contained in the tip of the head of the sperm cell called the 27. 28 The mitochondria of the sperm cell are contained in a portion of the cell known as the The tail of the sperm cell provides motion by acting as a The site of sperm cell maturation over a period of about two weeks is a duct called the 29.

Answers

Sperm cells are produced in the testes and are responsible for fertilizing the female egg during reproduction.

Sperm cells, also called reproductive cells or gametes, are the male reproductive cells responsible for fertilizing the female egg to initiate the process of reproduction. These specialized cells are produced within the testes, the primary male reproductive organs. The testes are housed within a fleshy pouch called the scrotum, which is located below the perineum. The scrotum serves as a protective environment for the testes, helping to regulate their temperature, which is essential for the production and maturation of sperm cells.

The testes are composed of tightly coiled tubules known as seminiferous tubules, where the process of spermatogenesis occurs. Spermatogenesis is the process through which sperm cells are produced from primordial cells called spermatogonia. These cells undergo a series of divisions and differentiations to eventually form spermatocytes, which further develop into spermatids. Spermatids then mature to become sperm cells.

Within the testes, there are also interstitial cells, also known as Leydig cells, which are responsible for producing testosterone, the primary male sex hormone. The seminiferous tubules join together to form a complex network called the rete testis, which is connected to the efferent ducts. These ducts transport the sperm cells to the epididymis, a coiled duct where sperm cells undergo maturation and acquire the ability to move.

In summary, sperm cells are the male reproductive cells that are produced in the testes through the process of spermatogenesis. They are responsible for fertilizing the female egg during sexual reproduction. The testes, scrotum, seminiferous tubules, interstitial cells, and efferent ducts all play vital roles in the production, maturation, and transportation of sperm cells.

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Which of the following leaves the body via the vas deferens? A Gametes B Follicles c Zygotes D Corpora lutea

Answers

A. Gametes

The vas deferens is a duct that carries sperm from the testes to the urethra during ejaculation. It is a part of the male reproductive system and plays a crucial role in the transportation of mature sperm cells. The process of producing sperm, known as spermatogenesis, takes place in the testes. The testes contain seminiferous tubules where sperm cells are produced through a series of developmental stages.

During spermatogenesis, the diploid cells in the testes called spermatogonia undergo mitosis to produce primary spermatocytes. These primary spermatocytes then undergo meiosis, resulting in the formation of haploid secondary spermatocytes. Further division of secondary spermatocytes produces spermatids, which eventually mature into sperm cells. The maturation process involves the development of flagella and the loss of excess cytoplasm.

Once the sperm cells are fully developed, they are stored in the epididymis, a structure located on the posterior surface of each testicle. During ejaculation, the smooth muscles in the walls of the vas deferens contract, propelling the sperm cells through the vas deferens and into the urethra. From there, the sperm cells can be ejaculated out of the body during sexual intercourse.

In summary, the gametes, which are mature sperm cells, leave the body via the vas deferens. This structure serves as a conduit for transporting the sperm cells from the testes to the urethra, allowing them to be expelled during ejaculation.

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Gametes is the term that leaves the body via the vas deferens. So, term 'A' is true.

Gametes are cells that reproduce sexually.

They are found in the testicles of males and the ovaries of females.

Gametes are specialized cells that are responsible for sexual reproduction.

Gametes have half the number of chromosomes as body cells and are formed through a process called meiosis.

The vas deferens is a muscular tube that carries sperm from the epididymis to the urethra in males.

It is a part of the male reproductive system.

During ejaculation, the vas deferens contracts to propel the sperm forward, along with other fluids, into the urethra, from where it exits the body.

These structures produce progesterone, which is necessary for the maintenance of pregnancy.

It is not excreted through the vas deferens, thus, the correct option is A, gametes.

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9. Which of the following tarsal bones is located most laterally? A) Navicular B) Medial cuneiform C) Lateral cuneiform D) Cuboid E) Intermediate cuneiform 10. Which of the followings is not correct about Skull? A) Divided into two structural parts B) Facial skeleton holds 14 bones C) Neuro cranium holds 8 bones D) There are 2 maxilla bones E) Frontal is a double bone 11. Which of the followings is not correct about thoracic cage? A) Sternum is most anterior bony border of thorax B) Ribs are anterolateral border of thorax C) Vertebral column is most posterior border of thorax D) There are 12 pairs of ribs on thoracic cage E) Only two parts of sternum contribute to thoracic cage

Answers

Te cuboid tarsal bone is located most laterally. Tarsal bones are a group of seven small bones located in the ankle joint.

These bones are called the talus, calcaneus, navicular, cuboid, and the three cuneiform bones. The cuboid tarsal bone is located most laterally.

The following statement is not correct about the skull:

1) Frontal is a double bone. The skull is the bony structure that protects the brain and supports the face.

2) It is divided into two parts: the neurocranium, which protects the brain, and the facial skeleton, which consists of the bones that form the face.

3) The facial skeleton holds 14 bones, and there are 2 maxilla bones.

The following statement is not correct about the thoracic cage:

a) There are 12 pairs of ribs on the thoracic cage. The thoracic cage is made up of the sternum, ribs, and thoracic vertebrae.

b) The sternum is the most anterior bony border of the thorax, and the vertebral column is the most posterior border of the thorax.

c) The ribs are the anterolateral border of the thorax, and there are 12 pairs of ribs on the thoracic cage. Only two parts of the sternum contribute to the thoracic cage.

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Activity 7: Pathway .... Water molecule, glucose molecule Directions: You can create a concept map of flowehtart using words and arrows OR you can iketch the structures and then libel and use arrows to indicate pathway. Put a BIG STAR at the beqinning spot for each molecule if you do a sketch and use different colors for the pathways so they are clear. - Trace the pathway of a water molecule from the abdominal aorta to the kidney, into the filtrate, and out of the body, naming structures along the way. - Trace the pathway of a glucose molecule from the abdominal aorta to the kidney, into the filtrate and back into the blood, naming structures along the way.

Answers

Reabsorption of water and glucose carried in the blood occurs in the nephron of the kidneys. The required amount of water is reabsorbed and rest is secreted into urine, whereas glucose is completely reabsorbed in PCT.

The pathway of a water molecule from the abdominal aorta to the kidney, into the filtrate, and out of the body can be depicted as follows:

Abdominal aorta → Renal artery → Afferent arteriole → Glomerulus (kidney) → Bowman's capsule → Proximal convoluted tubule → Loop of Henle → Distal convoluted tubule → Collecting duct → Papillary duct → Minor calyx → Ureter → Urinary bladder → Urethra → Exit

The pathway of a glucose molecule from the abdominal aorta to the kidney, into the filtrate, and back into the blood can be depicted as follows:

Abdominal aorta → Renal artery → Afferent arteriole → Glomerulus (kidney) → Bowman's capsule → Proximal convoluted tubule → Sodium-glucose symporter → Tubule cell → Peritubular capillaries → Blood  

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PREPARATION OF STAINED BLOOD SMEAR QUESTION: 1. Describe the different blood cells and give their specific functions. 2. DRAW: STEPS OF THE DIFFERENT BLOOD TESTS STANDARD RESULT OF ABO BLOOD GROUPINGS

Answers

Blood Cells and their specific functions Red Blood Cells (RBCs) - also known as erythrocytes - have the primary function of carrying oxygen from the lungs to the rest of the body.

White Blood Cells (WBCs) - also known as leukocytes - are part of the immune system and help protect the body against infection and disease. Platelets - also known as thrombocytes - are cell fragments that are responsible for blood clotting. Steps of the different blood tests- Blood tests are used to help diagnose and manage a wide range of medical conditions. The most common blood tests include: Complete Blood Count (CBC): This test measures the levels of different blood cells in the body, including red blood cells, white blood cells, and platelets.

Basic Metabolic Panel (BMP): This test measures levels of different chemicals and minerals in the blood, such as glucose, sodium, and potassium. Lipid Panel: This test measures levels of different types of cholesterol in the blood. Liver Function Tests: This test measures the levels of different enzymes and proteins that are produced by the liver. Standard result of ABO blood groupings: ABO blood groupings are based on the presence or absence of certain antigens on the surface of red blood cells. The four different blood types are: A, B, AB, and O. The presence of certain antibodies in the blood can also affect the compatibility of blood transfusions.

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A muscle at rest exhibits no tension. Is this statement true or false? Explain your answer.

Answers

The statement "A muscle at rest exhibits no tension" is generally true.

Muscles are capable of developing tension when stimulated. However, when a muscle is at rest, it does not produce any tension. There are two types of muscle fibers: skeletal muscle fibers and smooth muscle fibers. The skeletal muscle fibers are voluntary and cause movement.

On the other hand, smooth muscle fibers are involuntary and operate the organs and vessels. The fibers of skeletal muscles have a basic unit of structure referred to as a sarcomere. It is the region of the muscle that develops tension or force. During the contraction phase, the sarcomere shortens, causing tension to increase. If a muscle is not stimulated by an action potential from a motor neuron, it cannot contract. Thus, the muscle is at rest and does not exhibit any tension.

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Notice that in the alignment table, the data are arranged so each globin pair can be compared.

b. Notice that the cells in the lower left half of the table are blank. Using the information already provided in the table, fill in the missing values. Why does it make sense that these cells were left blank?

Answers

The cells in the lower left half of the alignment table are left blank because they represent comparisons between the same sequences. In other words, they are self-comparisons.

When aligning sequences, it is important to compare each sequence with every other sequence in order to identify similarities and differences.

However, when comparing a sequence with itself, the result will always be identical.

Therefore, filling in these cells with the same sequence would be redundant and not provide any additional information.

By leaving these cells blank, we can focus on the unique comparisons between different sequences, which are more informative for understanding the relationship and similarities between the globin pairs. This allows us to efficiently organize and analyze the data without unnecessary repetition.

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Which of the following best describes how functions of regulatory transcription factor proteins modification occur in eukaryotic cells? A. The modification of the function of eukaryotic regulatory transcription factor proteins in eukaryotic cells occurs when they bind a small effector molecule, such as a hormone, to form a hormone-receptor complex that binds DNA and activates or inactivatos transcription B. The modification of the function of eukaryotic regulatory transcription factor proteinoin eukaryotic cells occurs when either two similar or non-similar regulatory transcription factor proteins Interact with one another forming a homodimeric protein or a heterodimeric protein that binds DNA to activate or inactivate transcription C. The modification of the function of eukaryotic regulatory transcription factor proteins in eukaryotic cells occurs when regulatory transcription factor proteins bind to DNA and are covalently modified through phosphorylation by kinases to activate or inactivate transcription D. Answers AB and Care the correct answer choices for this question E. None of the answers in the correct answer choice for this question QUESTION 43 Which segments of nucleic acide directly indulge in translation in living cells? A. The segments of nucleic acids directly indulged in the translation process are the messenger ribonucleic acids B. The segments of nucleic acids directly indulged in the translation process are the ribonucleic acids C. The segments of nucleic acids directly indulged in the translation process are the complementary deoxyribonucleic acids D. The segments of nucleic acids directly indulged in the translation process are the reversed transcribed ribonucleic acids E. The segments of nucleic acide directly Indulged in the translation process are the complementary deoxyribonucleic acids

Answers

The modification of the function of eukaryotic regulatory transcription factor proteins in eukaryotic cells occurs when regulatory transcription factor proteins bind to DNA and are covalently modified through phosphorylation by kinases to activate or inactivate transcription, option C.

The term "regulatory transcription factor" refers to proteins that regulate gene transcription. These proteins bind to specific DNA sequences in genes and control their transcription. Eukaryotic regulatory transcription factor proteins, like most other proteins, may be covalently modified to change their activity level. These modifications include phosphorylation, acetylation, methylation, and others.

Phosphorylation by kinases is one of the most well-known forms of covalent modification of eukaryotic regulatory transcription factor proteins. Phosphorylation adds a phosphate group to specific amino acid residues, typically serine, threonine, and tyrosine, on regulatory transcription factor proteins. This changes the protein's activity level, allowing it to activate or inactivate transcription. Therefore, option C is the correct answer to the given question.

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Hey,
I need help with the following question from physiology, thank you!
The question: Match the correct concept with the correct meaning.
Concept:
1. Discontinuous capillary
2. Fenestrated capillary
3. End artery
4. Anastomosis
Meanings:
a. A connecting vessel between 2 different networks
b. A vessel without branches
c. A vessel that has a higher degree of permeability
d. A vessel that allows the entry and exit of blood cells

Answers

The given concepts and their corresponding meanings are as follows:

Concepts:

1. Discontinuous capillary

2. Fenestrated capillary

3. End artery

4. Anastomosis

Meanings:

a. A connecting vessel between two different networks

b. A vessel without branches

c. A vessel that has a higher degree of permeability

d. A vessel that allows the entry and exit of blood cells

Explanation:

Discontinuous capillary: A type of capillary that is located only in the liver, bone marrow, and spleen. Its endothelial cells are widely spaced and have many large pores or gaps that allow large molecules to move between the blood and the surrounding tissue. Therefore, its meaning is c, a vessel that has a higher degree of permeability.

Fenestrated capillary: A type of capillary that has small pores (fenestrations) in its endothelial cells, which allows for the movement of smaller molecules (such as water, ions, and other solutes) between the blood and the surrounding tissue. Therefore, its meaning is c, a vessel that has a higher degree of permeability.

End artery: An artery that does not form any significant anastomoses, or connecting branches, with other arteries. Therefore, its meaning is b, a vessel without branches.

Anastomosis: A connection between two blood vessels or nerves, typically between arteries. Therefore, its meaning is a, a connecting vessel between two different networks.

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can you please help me answer these questions for open note final. Human physiology
Multiple choice and/or True False questions will be written to test your understanding of these questions:
Lecture:
1. What is the hierarchy of structural organization?
2. What are the four basic cell types?
3. What are the divisions of body water? ECF….
4. What are the main steps in protein synthesis?
5. What are the main ways to regulate the amount of a specific protein present in a cell?
6. What is osmolarity? 7. What is the normal osmolarity of a typical human fluid?
8. What is homeostasis?
9. What are the four basic types of biomolecules?
10. What is a carbohydrate composed of?
11. What is a protein composed of?
12. What are the five nucleotides?
13. What is a nucleic acid?
14. What is the main component of a cell membrane?
15. What is cytosol?
What is an enzyme?

Answers

Hierarchy of Structural Organization: The hierarchy of structural organization includes the atomic, molecular, organelle, cellular, tissue, organ, system, and organismal levels.

2. Four basic cell types: The four basic cell types are muscle cells, nerve cells, epithelial cells, and connective tissue cells.3. Divisions of body water: Extracellular fluid (ECF), interstitial fluid (IF), and intracellular fluid (ICF) are the three divisions of body water.

4. Main steps in protein synthesis: The main steps of protein synthesis include transcription and translation.5. Ways to regulate the amount of a specific protein present in a cell: Post-transcriptional and post-translational modifications are the two main methods of regulating protein levels in a cell.6. Osmolarity: Osmolarity is the concentration of solutes in a solution.7. Normal osmolarity of a typical human fluid: 300 mOsm/L is the normal osmolarity of a typical human fluid.

8. Homeostasis: Homeostasis is the body's ability to maintain a stable internal environment.9. Four basic types of biomolecules: Carbohydrates, lipids, nucleic acids, and proteins are the four basic types of biomolecules.10. Composition of a carbohydrate: Carbohydrates are made up of carbon, hydrogen, and oxygen.11. Composition of a protein: Proteins are made up of amino acids.12. Five nucleotides: Adenine (A), guanine (G), cytosine (C), thymine (T), and uracil (U) are the five nucleotides.

13. Nucleic acid: Nucleic acids are polymers of nucleotides that store and transmit genetic information.14. Main component of a cell membrane: The main component of a cell membrane is a phospholipid bilayer.15. Cytosol: The fluid that fills the cell, excluding organelles, is called the cytosol.16. Enzyme: An enzyme is a biological catalyst that speeds up chemical reactions by lowering the activation energy required for the reaction to occur.

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17. If the light is on the center of an off center on surround ganglion receptive field, which of the following would occur?
a.The cone in the center depolarizes
b. The horizontal cell depolarize
c. The off center ganglion cell depolarizes
d. The off center bipolar cell depolarizes

Answers

If the light is on the center of an off center-on surround ganglion receptive field, the cone in the center depolarizes. Depolarization occurs when positive ions rush into the neuron, resulting in a change in the neuron's membrane potential from negative to positive. Option a .

What is a receptive field?

A receptive field is a location on the retina in which light stimulation produces a reaction in a neuron, resulting in the production of an action potential. Receptive fields are classified as center-surround and are critical for detecting borders and contrast in visual stimuli. Each ganglion cell in the retina has a receptive field that includes multiple photoreceptors (rods and cones).

When light strikes the center of a center-surround ganglion cell's receptive field, it triggers a response, but when light strikes the surrounding area of the field, it suppresses the ganglion cell's response. As a result, ganglion cells have either on-center or off-center receptive fields. Therefore option a is correct.

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8. Define the cardiovascular proper and associated reflexes. Its clas- sification. 9. Define the reflexogenic zones of the aortic arch and carotid sinus and specify their function. 10. The mechanisms of cardiovascular functional adjustment during physical activity. 11. Classification and possibilities of methods for examining of vascu- lar tone.

Answers

Cardiovascular refers to the heart and blood vessels of the body. The heart pumps blood throughout the body, while blood vessels, such as arteries and veins, transport blood to and from the heart.

Cardiovascular reflexes: It is a reflex that regulates blood pressure through the cardiovascular system. It is responsible for maintaining normal blood pressure levels and preventing excessive changes in blood pressure.Classification: Cardiovascular reflexes can be classified into two types: central and peripheral reflexes. Central reflexes involve the cardiovascular centers located in the medulla oblongata of the brain.

Peripheral reflexes involve sensory receptors located in the walls of blood vessels and the heart.

Reflexogenic zones of the aortic arch and carotid sinus: Reflexogenic zones are specialized areas in the walls of blood vessels that contain nerve endings that respond to changes in blood pressure. The two most important reflexogenic zones are located in the aortic arch and the carotid sinus.

Function: When blood pressure changes, the nerve endings in these areas send signals to the cardiovascular center in the brain. The cardiovascular center then sends signals to the heart and blood vessels to adjust blood pressure.10. Mechanisms of cardiovascular functional adjustment during physical activity:During physical activity, the body's demand for oxygen and nutrients increases.

This demand is met by an increase in blood flow to the muscles and other tissues involved in the activity. This increase in blood flow is achieved through the following mechanisms: Increased heart rate and stroke volume: The heart pumps more blood with each beat and beats more frequently.

Increased cardiac output: The total amount of blood pumped by the heart per minute increases. Increased blood pressure: Blood vessels constrict, which increases blood pressure and helps to maintain blood flow to the muscles.

Classification and possibilities of methods for examining vascular tone:Classification: There are two types of methods for examining vascular tone: invasive and noninvasive. Invasive methods: These methods involve inserting a catheter or other device into a blood vessel to directly measure blood pressure or blood flow.

Examples of invasive methods include angiography, which involves injecting contrast dye into a blood vessel and taking X-ray images. These methods do not require the insertion of a device into a blood vessel. Examples of noninvasive methods include: blood pressure measurement, ECG, echocardiography, and magnetic resonance imaging (MRI).

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What structure does not have an effect on the refraction of light within the eye?
1. Cornea
2. Lens
3. Vitreous humor (body)
4. sclera

Answers

The structure that does not have an effect on the refraction of light within the eye is Sclera. The correct answer is 4. Sclera.

The sclera is the tough, white outer covering of the eyeball. It provides structural support and protection to the eye but does not have a direct effect on the refraction of light within the eye.

On the other hand, the other three structures listed do have a significant impact on the refraction of light within the eye:

1. Cornea: The cornea is the transparent, curved outermost layer of the eye. It is primarily responsible for bending or refracting incoming light, focusing it onto the lens.

2. Lens: The lens is a flexible, transparent structure located behind the iris. It further refracts the incoming light and fine-tunes the focus onto the retina.

3. Vitreous humor (body): The vitreous humor is a gel-like substance that fills the space between the lens and the retina. While not directly involved in refraction, it helps maintain the shape of the eyeball and provides support to the retina.

While the cornea, lens, and vitreous humor all play essential roles in the refraction of light within the eye, the sclera does not have an effect on this process.

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A 68-year-old heart failure patient shows digoxin toxicity in intensive care unit. She has received 125 mcg as standard dose. Serum levels were reported to be 2 ng/mL (2 mcg/L). Target therapeutic level is 0.8 ng/mL. What dose should she receive now onwards to avoid worsening of the toxicity?

Answers

The dosage required to avoid worsening of toxicity for a 68-year-old heart failure patient who shows digoxin toxicity is 20 mcg (0.02 mg).

The first step in determining the dose is to calculate the dose received by the patient:

1 mg = 1000 mcg.

Thus, 125 mcg = 0.125 mg

Next, the concentration of digoxin in the serum is reported to be 2 ng/mL, which is equivalent to 2 mcg/L.Since the target therapeutic level is 0.8 ng/mL, the patient's concentration is well above the therapeutic range. Therefore, the dosage of digoxin should be decreased.The following formula can be used to determine the new dose required to reach the target therapeutic level:

New dose = (target level x Vd x weight) / Cp,

where:

Vd = Volume of distribution (0.7 L/kg for digoxin)

Cp = Concentration in plasma/serum

For the patient in question:

Target level = 0.8 ng/mL

Cp = 2 ng/mL

Vd = 0.7 L/kg

Weight = Assume 70 kg

New dose = (0.8 x 0.7 x 70) / 2 = 19.6 mcg (rounded up to 20 mcg).

Therefore, the patient should receive a new dose of 20 mcg (0.02 mg) to avoid worsening of toxicity.

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