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Answer:

$21600

Step-by-step explanation:

Net income is calculated by deducting all company expenses from its total revenue. Net income is given by the formula:

Net income = Revenue - cost of goods sold - operating expenses - tax.

But Gross margin = gross profit = Revenue - cost of goods sold. Hence:

Net income = Gross margin - operating expenses - tax.

Substituting gives:

Net income = $50000 - $23000 - $5400

Net income = $21600

Answer:

the answer is:

(12) + (18) = 30

Answer:

A

Step-by-step explanation:

Answer:

yes

Step-by-step explanation:

The required expression represents the number of students on the bus would be S < 40.

Inequality can be defined as the relation of the equation containing the symbol of ( ≤, ≥, <, >) instead of the equal sign in an equation.

Here,
According to the question,
The number of students the bus holds, s which is less than 40,
So
S is less than 40
S < 40  
[in math we have inequality represent the less than relation or greater than the relation with symbols "<"  and ">"]

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Solve for

y

in the first equation.

Tap for more steps...

y

=

−

20

+

4

x

−

2

x

−

2

y

=

10

Replace all occurrences of

y

in

−

2

x

−

2

y

=

10

with

−

20

+

4

x

.

y

=

−

20

+

4

x

−

2

x

−

2

(

−

20

+

4

x

)

=

10

Simplify

−

2

x

−

2

(

−

20

+

4

x

)

.

Tap for more steps...

y

=

−

20

+

4

x

−

10

x

+

40

=

10

Solve for

x

in the second equation.

Tap for more steps...

y

=

−

20

+

4

x

x

=

3

Replace all occurrences of

x

in

y

=

−

20

+

4

x

with

3

.

y

=

−

20

+

4

(

3

)

x

=

3

Simplify

−

20

+

4

(

3

)

.

Tap for more steps...

y

=

−

8

x

=

3

The solution to the system of equations can be represented as a point.

(

3

,

−

8

)

The result can be shown in multiple forms.

Point Form:

(

3

,

−

8

)

Equation Form:

x

=

3

,

y

=

−

8

The solution of the given system of linear equations using substitution method is [tex]x = -1, y = 18[/tex].

The substitution method can be defined as a way to solve a linear system algebraically. The substitution method works by substituting one y-value with the other. To solve it easily, the method involves finding the value of the x-variable in terms of the y-variable. After that, we then end up substituting the value of x-variable in the second equation. This helps us to directly find the value of the y-variable. We can now put the value of y in any of the given equations to find x.

The given system of equations are:

[tex]y + 8x = 10[/tex]..... (1)

[tex]2y - 4x = 40[/tex]..... (2)

The given value of [tex]x = - 1[/tex]. Therefore, the given value of 'x' satisfies for both the equations given.

Now using substitution method, substituting the value of 'x' in the equation(1), we will get the value of 'y'.

Therefore:

[tex]y + 8(-1) = 10[/tex]

⇒ [tex]y = 10 + 8[/tex]

⇒ [tex]y = 18[/tex]

Again, we can verify the value of 'y' by substituting the value of 'x' in equation (2).

Therefore,

[tex]2y - 4(-1) = 40[/tex]

⇒ [tex]2y = 40 - 4[/tex]

⇒ [tex]y = \frac{36}{2}[/tex]

⇒ [tex]y = 18[/tex]

Hence,

The solution of the given system of linear equations using substitution method is [tex]x = -1, y = 18[/tex].

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Answer:

560 is the answer

Step-by-step explanation:

if you divide  by you get 70 so times 70 by 8 to get 560

Answer: 560 miles

Step-by-step explanation: the car travels at a speed of 70 miles per hour. Therefore, multiply 70 by 8 and you get 560

Answer:

Step-by-step explanation:

There are several ambiguities in your question upon which I feel disinclined to speculate. It cries out for an explanatory diagram:

For example (i.e. including but not only!):  

1. What is the essential distinction between a plane and a regular pyramid?

2. Does each of the two solids have all of its own edges equal, independently of the other solid? Or are the corresponding edges of the two solids equal? Or are all edges of both solids equal?

Answer:

[tex] \dfrac{1}{5^8} = \dfrac{1}{390625} [/tex]

Step-by-step explanation:

[tex](5^{-2})^4 = 5^{-2 \times 4} = 5^{-8} = \dfrac{1}{5^8} = \dfrac{1}{390625}[/tex]

Pretend this is the answer in da comments

Answer:

Part A: 24

Part B: 256

Step-by-step explanation:

Part A

Without Repetition means that once you use a number out of the given four, it can't be used again.

Answer: 4*3*2* 1 = 24

Part B

Part B allows repetition. That means that the numbers can be used as many as 4 times.

Answer: 4*4*4*4 = 256

Answer: 15(3+4)

Step-by-step explanation:

First, we want to find the GCF of these numbers

The greatest number they can both be divided by is 15

All of the possible factors are 1, 3, 5, 9, 15, and 15 is the highest

So 15 is the GCF

We then divide these numbers to get the equation

45/15=3

60/15=4

So the new equation would be (3+4)

We then add the GCF outside the parenthesis so you can distribute it in order to get the original numbers

So the distributive equation would be 15(3+4)

Answer 15(3+4)

Answer:

We conclude that the point (-3, 0) does NOT satisfy the inequality.

Step-by-step explanation:

Given the expression

[tex]y\ge \:\left|x\right|+3\:\:\:\:[/tex]

putting x = -3 and y = 6

[tex]6\ge \left|-3\right|+3\:\:\:[/tex]

Apply absolute rule: |-a| = a

[tex]6\ge \:6[/tex]

TRUE

Thus, the point (-3, 6) satisfies the inequality.

Given the expression

[tex]y\ge \:\left|x\right|+3\:\:\:\:[/tex]

putting x = 0 and y = 4

[tex]4\ge \left|0\right|+3[/tex]

Apply absolute rule: |a| = a, a≥0

[tex]4\ge \:3[/tex]

TRUE

Thus, the point (0, 4) satisfies the inequality.

Given the expression

[tex]y\ge \:\left|x\right|+3\:\:\:\:[/tex]

putting x = -3 and y = 0

[tex]0\ge \left|-3\right|+3\:\:\:[/tex]

Apply absolute rule: |-a| = a

[tex]0\ge \:6[/tex]

FALSE

Thus, the point (-3, 0) does NOT satisfy the inequality.

Therefore, we conclude that the point (-3, 0) does NOT satisfy the inequality.

Answer:

In multiplication the answer is called PRODUCT and in division the answer is called quotient.

Step-by-step explanation:

I hope that helps and you get a good grade :)

The answer to a multiplication problem is called a Product.                                                    The answer to a division problem is called the quotient.

Answer:

A. -3

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Step-by-step explanation:

Step 1: Define

-9p - 17 = 10

Step 2: Solve for p

Answer:

Either [tex]\displaystyle \frac{-1522}{\sqrt{41}}[/tex] (approximately [tex]-238[/tex]) or [tex]\displaystyle \frac{1522}{\sqrt{41}}[/tex] (approximately [tex]238[/tex].)

Step-by-step explanation:

Let [tex]a[/tex] denote the first term of this geometric series, and let [tex]r[/tex] denote the common ratio of this geometric series.

The first five terms of this series would be:

First equation:

[tex]a\, r^4 - a = 150[/tex].

Second equation:

[tex]a\, r^3 - a\, r = 48[/tex].

Rewrite and simplify the first equation.

[tex]\begin{aligned}& a\, r^4 - a \\ &= a\, \left(r^4 - 1\right)\\ &= a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) \end{aligned}[/tex].

Therefore, the first equation becomes:

[tex]a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) = 150[/tex]..

Similarly, rewrite and simplify the second equation:

[tex]\begin{aligned}&a\, r^3 - a\, r\\ &= a\, \left( r^3 - r\right) \\ &= a\, r\, \left(r^2 - 1\right) \end{aligned}[/tex].

Therefore, the second equation becomes:

[tex]a\, r\, \left(r^2 - 1\right) = 48[/tex].

Take the quotient between these two equations:

[tex]\begin{aligned}\frac{a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right)}{a\cdot r\, \left(r^2 - 1\right)} = \frac{150}{48}\end{aligned}[/tex].

Simplify and solve for [tex]r[/tex]:

[tex]\displaystyle \frac{r^2+ 1}{r} = \frac{25}{8}[/tex].

[tex]8\, r^2 - 25\, r + 8 = 0[/tex].

Either [tex]\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}[/tex] or [tex]\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}[/tex].

Assume that [tex]\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}[/tex]. Substitute back to either of the two original equations to show that [tex]\displaystyle a = -\frac{497\, \sqrt{41}}{41} - 75[/tex].

Calculate the sum of the first five terms:

[tex]\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= -\frac{1522\sqrt{41}}{41} \approx -238\end{aligned}[/tex].

Similarly, assume that [tex]\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}[/tex]. Substitute back to either of the two original equations to show that [tex]\displaystyle a = \frac{497\, \sqrt{41}}{41} - 75[/tex].

Calculate the sum of the first five terms:

[tex]\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= \frac{1522\sqrt{41}}{41} \approx 238\end{aligned}[/tex].

Answer:

chetta es polla airemeris di quana premeria

Step-by-step explanation:

Answer:

Month 1:

Calculate Balance (by adding interest to existing balance): 678.34*(1 + 0.217/12) = 690.606648333333 = 690.61

Make payment: 690.61 - 235 = 455.61

Old Balance: 690.61

New Balance: 455.61

--------------------------------------------------------------

Month 2:

Calculate Balance (by adding interest to existing balance): 455.61*(1 + 0.217/12) = 463.8489475 = 463.85

Make payment: 463.85 - 235 = 228.85

Old Balance: 463.85

New Balance: 228.85

--------------------------------------------------------------

Month 3:

Calculate Balance (by adding interest to existing balance): 228.85*(1 + 0.217/12) = 232.988370833333 = 232.99

Make payment: 232.99 - 232.99 = 0

Old Balance: 232.99

New Balance: 0

--------------------------------------------------------------

Payments Made: 235, 235, 232.99

Number of Payments Made: 3

Total Cost: 235 + 235 + 232.99 = 702.99

Total Cost: $702.99

Total Interest: 702.99 - 678.34 = 24.65

Answer:

(a) Describe a property of squares that is also a property of rectangles.

(b) Describe a property of squares that is NOT necessarily a property of all rectangles.

(c) Describe a property of rhombi that is also a property of squares.

(d) Describe a property of rhombi that is NOT necessarily a property of all parallelograms.

(e) Describe a property that applies to ALL parallelograms.

Answer:

x = 27

Step-by-step explanation:

[tex]x - 21 = 6[/tex]

Add 21 to both sides.

[tex]x = 6 + 21[/tex]

[tex]x = 27[/tex]

[tex]\boxed{\boxed{\pink{\bf\leadsto No }}}[/tex]

No , theres not enough information provided to Prove that both the triangles are congruent. Here in the figure we can see that there are two triangles ∆ BDA and ∆ BDC. And its given that

The congruence conditions for two ∆s are :-

1) SAS ( Side Angle Side )

→ Two triangles are said to be congruent by SAS if two respective sides of the two triangles and the included angle between two sides are equal.

2) AAS ( Angle Angle Side )

→ Two triangles are said to be congruent by AAS if two angles and one side of triangle is congruent to other two angles and one side of the triangle .

3) SSS ( Side Side Side )

→ Two triangles are said to be congruent by SAS if all the three sides of one triangle is equal to three sides of the other triangle.

4) RHS ( Right Hypotenuse Side )

→ In two right-angled triangles, if the length of the hypotenuse and one side of one triangle, is equal to the length of the hypotenuse and corresponding side of the other triangle, then the two triangles are congruent.

And the given data doesn't satisfies any of the conditions.

No, there are not enough information provided to Prove that both the triangles are congruent.

Two triangles are said to be congruent if the length of the sides is equal, a measure of the angles are equal and they can be superimposed.

In the figure we can see that there are two triangles ∆ BDA and ∆ BDC. And its given that

AB = BC

BD = BD ( common side )

The congruence conditions for two ∆s are :-

1) SAS ( Side Angle Side )

Two triangles are said to be congruent by SAS Postulate if two respective sides of the two triangles and the included angle between two sides are equal.

2) AAS ( Angle Angle Side )

Two triangles are said to be congruent by AAS Postulate if two angles and one side of triangle is congruent to other two angles and one side of the triangle .

3) SSS ( Side Side Side )

Two triangles are said to be congruent by SAS Postulate if all the three sides of one triangle is equal to three sides of the other triangle.

4) RHS ( Right Hypotenuse Side )

In two right angled triangles, if the length of the hypotenuse and one side of one triangle, is equal to the length of the hypotenuse and corresponding side of the other triangle, then the two triangles are congruent.

The given data doesn't satisfies any of the conditions.

Hence, there is not enough information provided to Prove that two triangles are congruent .

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Answer:

-10

Step-by-step explanation:

4x+py=5

Is also 2x+(p/2)y=5/2

And the other is 2x-5y+6=0

As the lines are parallel

2/2=(p/2)/(-5)

p= -10

Answer:

Books due to this week=1260

Step-by-step explanation:

F-books checked out=12500*(2/5)=5000

nonF-books checked out=19000*(2/5)=7600

Total checked books=5000+7600=12600

Books due to this week = (1/10)*12600=1260

Answer:

the answer is option A.

Answer:

[tex]No\ Solutions[/tex]

Step-by-step explanation:

[tex]We\ are\ given\ that,\\-x+2y=7\\x-2y=7\\By\ simply\ adding\ the\ system\ of\ equations,\\(-x+x)+(2y-2y)=(7+7)\\0+0=14\\Hence,\\0=14\\As\ the\ equation\ above\ doesnt\ make\ sense\ as\ 0\ doesn't\ equal\ to\ 14,\\There\ are\ no\ solutions\ that\ satisfy\ the\ equation.[/tex]

Answer:

D.

Step-by-step explanation:

The dot in the answer means multiply.

Answer:

Therefore the smallest parameters is  (6,6) and a dimension of 24 inches

Step-by-step explanation:

From the question we are told that

area of dimension is  [tex]A=36[/tex]

Generally the perimeter of  rectangle is given as

      [tex]x,y=36[/tex]

Given by

      [tex](x,y)=2x+2y[/tex]

Mathematical solving for perimeter of rectangle

    [tex]x=\frac{36}{y}[/tex]

    [tex]f(y)= 2\frac{36}{2} +2y\\f(y)= \frac{72}{y} +2y[/tex]

Generally in finding minimum perimeter

     [tex]f'(y)=\frac{-72}{y^2} +2=0\\[/tex]

     [tex]y=6[/tex]

[tex]f(6,6)=2(6)+2(6) \\f(6,6)=24 inches[/tex]

Therefore the smallest parameters is  (6,6) and a dimension of 24 inches

Answer:

Step-by-step explanation:

From the question we are told that

Altitude of Height 1.4miles

4miles west

a) From the question

[tex]f(x)=ax3+bx2+cx+d[/tex] on interval (-4,0)

The descent can be expressed in [tex]\triangle _x =-4,0[/tex]

therefore  initial points is (-4 , 1.4).

final co-ordinate is given by (0,0) as its landing

Mathematically solving in above  cubic equation

 [tex]0 = 0 + 0 + 0 + d \\[/tex]

[tex]d = 0[/tex]

[tex]1.4 = -64a + 16b -4c + d[/tex]

[tex]1 = -45.7a + 11.4b-2.9c+d[/tex]

Generally in this case Slope of tangent at point of descent is zero.assuming flight was initially straight before descent

     [tex]f'(x) = 3ax^2 + 2bx+c[/tex]

    [tex]f'(-4) = 48a -8b + c = 0[/tex]

    [tex]f'(0) = c = 0[/tex]

Mathematically solving above equations we have

[tex]a = \frac{1}{40} \ and \ b = \frac{3}{20}[/tex]

Therefore having found a and b the Cubic equation is given as

[tex]f(x) = \frac{1}{40}x^3 + \frac{3}{20}x^2[/tex]

b)descent at its greatest rate

[tex]f(x)=\frac{1.4}{40} x^3 + \frac{129}{20} x^2[/tex]

[tex]f(x)=\frac{1.4}{40} x^3 + \frac{129}{20} x^2[/tex]

Answer:

(1,3) (2,6) (3,9) (4,12)

Step-by-step explanation:

Meanwhile the x value increases by 1, the y value increases by 3.