How can you tell how many valence electrons are contained in one atom of a particular element found in the periodic table of elements?

D. 18.1

K^+H^+G^=180° (sum of int angles of triangle)

K^+30+62=180

K^=88°

GH/sinK=KG/sinH

X/sin88=16/sin62

X*sin62/sin62=16*sin88/sin62

X=18.1

Answer:

Efficency = 28%

Explanation:

We have the load has a weight of:

[tex]w =m*g\\w =12*9.81\\w = 117.72 [N][/tex]

Work in physics is defined as the product of force (weight) by distance.

[tex]W=w*d[/tex]

where:

W = work [J]

w = weight = 117.72[N]

d = distance = 5 [m]

[tex]W=117.72*5\\W=588.6[J][/tex]

Now power is defined as the relationship of work at a certain time.

[tex]P=W/t\\[/tex]

where:

P = power [W]

W = work = 588.6[J]

t = time = 30[s]

[tex]P=588.6/30\\P=19.62[W][/tex]

Now the efficiency of a machine is defined as the power output over the power input to the machine. The power input should always be greater than the power output.

[tex]efficency = \frac{Power_{out}}{Power_{in}}\\Efficeny = \frac{19.62}{70} \\Efficency = 0.28\\Efficency = 28%[/tex]

Answer:

Glycolysis

Pyruvate

Krebs Cycle

Electron Transport Chain

Explanation:

The concept map on ATP production shows the process of cellular respiration in living organisms.

Cellular respiration begins with glucose which is broken down in the process of glycolysis that occur in cytoplasm and gives 2 ATP. Glycolysis gives pyruvate as end product that enter in the process of Krebs Cycle or citric acid cycle as a aerobic process, that occur in mitochondria and produces 2 ATP. This energy is then used in Electron Transport Chain to pump high energy electrons and H+ that produces 36 ATP.

Answer:

Part A;

he mass of the object, m = 2 kg

The initial speed of the object, u = 3 m/s east

The final speed of the object, v = 7 m/s west

The initial kinetic energy of the object = 1/2 × m × u² = 1/2 × 2 × 3² = 9 Joules

The final kinetic energy of the object = 1/2 × m × v² = 1/2 × 2 × 7² = 49 Joules

Based on the change in the momentum produced by the force which changes the direction  of the object, we add the two energy quantities to get the total change in energy as follows;

The change in kinetic energy = 9 J + 49 J = 58 J

The statement is wrong because the change in momentum brought about by the force should be included when finding the the total change in kinetic energy of the object during the 5 seconds period

Part B;

The kinetic energy, K. E. = 1/2 × m × v²

The kinetic energy of the car A = 1/2 × 1000 × 6² = 18,000 J

The kinetic energy of the car B = 1/2 × 1600 × 8² = 51,200 J

The kinetic energy of the car C = 1/2 × 1200 × 8² = 38,400 J

The kinetic energy of the car D = 1/2 × 1600 × 4² = 12,800 J

Given that work required = Force × Distance, and the distance, is constant, we have;

The force required is directly proportional to the energy kinetic energy of the car that is to be stopped

Therefore, we have;

B = 1, C = 2, A = 3, and D = 4

The work needed to stop the car, W = The strength of the applied force, F × The given constant distance to stop, d

∴ W ∝ F.

Explanation:

Part A;

The mass of the object, m = 2 kg

The initial velocity of the object, u = 3 m/s east

The final velocity of the object, v = 7 m/s west

The initial kinetic energy of the object = [tex]1/2 * m * u^2 = 1/2 * 2 *3^2 = 9 \text{ Joules}[/tex]

The final kinetic energy of the object = [tex]1/2 * m * v^2 = 1/2 * 2 * 7^2 = 49 \text{ Joules}[/tex]

Based on the change in the momentum produced by the force which changes the direction  of the object, we add the two energy quantities to get the total change in energy as follows;

The change in kinetic energy = [tex]9 J + 49 J = 58 J[/tex]

The statement is wrong because the change in momentum brought about by the force should be included when finding the the total change in kinetic energy of the object during the 5 seconds period.

Part B;

The kinetic energy, K. E. = 1/2 × m × v²

The kinetic energy of the car A = [tex]1/2 * 1000 *6^2 = 18,000 J[/tex]

The kinetic energy of the car B = [tex]1/2 * 1600 * 8^2 = 51,200 J[/tex]

The kinetic energy of the car C = [tex]1/2 * 1200 * 8^2 = 38,400 J[/tex]

The kinetic energy of the car D =[tex]1/2 * 1600 * 4^2 = 12,800 J[/tex]

Given that work required = Force × Distance, and the distance, is constant, we have;

The force required is directly proportional to the energy kinetic energy of the car that is to be stopped

Therefore, we have;

B = 1, C = 2, A = 3, and D = 4

The work needed to stop the car, W = The strength of the applied force, F × The given constant distance to stop, d.

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Answer:

The Force between the two charges is an attractive force of 16,000N

Explanation:

Expression for the electric force between the two charges is given by

F = (k*q1*q2) / r^2

Here, k = constant = 9 x 10^9 N*m^2 / C^2

q1 = - 2.0x10^-4C

q2 = + 8.0x10^-4C

r = 0.30 m

Substitute the given values in the above expression -

One charge  is + and the other is a -, therefore the net force is an attractive force (opposites atract)

The attraction force is:

F= 9.0x10^9 * 2.0x10^-4 *8.0x10^-4 N/ 0.30^2

F= 16,000N

The force between the two charges will be 16,000 N.It is the force exerted by one charge on another charge.

The electric force between the two charges is directly propotional to the product of the charge and inversly propotional to the square of the distance between them.

The given data in the problem is;

q₁ is the megnitude of charge 1= - 2.0x10⁻⁴ C

q₂ is the megnitude of charge 2 = + 8.0x10⁻⁴ C

k is the propotionallity constant = 9 x 10⁹ Nm² / C²

r is the seperated distance = 0.30 m

F is the electric force=?

The electric force is found as;

[tex]\rm F = \frac{K q_14q_2}{r^2} \\\\ \rm F = \frac{9 \times 10^9 \times 2.0 \times 10^{-4}}{(0.30)^2} \\\\ \rm F = 16,000N[/tex]

Hence the force between the two charges will be 16,000 N.

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Answer:

|Fr| = 50*√2  [N]

Explanation: (See Annex )

En el diagrama de cuerpo libre ( mostrado en el anexo) se ve que, al ser las dos fuerzas iguales (50 N) el paralelogramo formado para encontrar la resultante de las fuerzas (Fr)  es un cuadrado, y la diagonal de ese cuadrado ( que es al mismo tiempo la hipotenusa del triangulo recto OPA ) es igual a:

Hipotenusa = |Fr| = √ (50)² + (50)²

|Fr| = √2* (50)²

|Fr| = 50*√2  [N]

Answer:

diaetes

Explanation:

Answer:

A:  In an adiabatic process, no heat enters or leaves the system

Explanation:

The mass of a cylinder made of barium with a height of 2 inches depends on the radius of the cylinder as defined by the

function m(r) = 7.18872.

which system of equations and solution can be used to represent the radius if the mass of the cylinder is 11,000 grams?

round to the nearest hundredth of an inch.

Answer:

You use a force of 150 N to push a 30 kg crate across the floor for a distance of 10 m. If the crate is moving at a speed of 5 m/s…

Answer:

5) The approximate height is about 80 m. Choice (c)

6) The stone takes about 3 seconds to rise to its maximum height

Explanation:

Free Fall Motion

A free-falling object falls under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall.

If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the gravitational acceleration, which value is [tex]g = 9.8 m/s^2[/tex].

The distance traveled by a dropped object is:

[tex]\displaystyle y=\frac{gt^2}{2}[/tex]

Question 5

Given the stone reaches the ground in t=4 seconds, the height of the tower is:

[tex]\displaystyle y=\frac{9.8*4^2}{2}=78.4\ m[/tex]

The approximate height is about 80 m. Choice (c)

Question 6

Vertical Motion

The vertical motion of an object is controlled by the force of gravity. This means that there is a non-zero net force acting on the object that makes it accelerate downwards.

If the object is thrown upwards at speed vo, its speed at time t is:

[tex]v_f=v_o-g.t[/tex]

The stone reaches its maximum height when the final speed is zero, thus:

[tex]v_o-g.t=0[/tex]

Solving for t:

[tex]\displaystyle t=\frac{v_o}{g}[/tex]

The stone is thrown vertically upwards with vo=30 m/s, thus:

[tex]\displaystyle t=\frac{30}{9.8}[/tex]

[tex]t=3.06\ s[/tex]

[tex]t\approx 3\ s[/tex]

The stone takes about 3 seconds to rise to its maximum height

Answer:

400Pa

Explanation:

use pressure = force/area

[tex]\\ \rm\longmapsto Pressure=\dfrac{Force}{Area}[/tex]

[tex]\\ \rm\longmapsto Force=Pressure(Area)[/tex]

[tex]\\ \rm\longmapsto Force=200(0.5)[/tex]

[tex]\\ \rm\longmapsto Force=100N[/tex]

Explanation:

According to the Second Law of Thermodynamics, heat will always flow spontaneously from hot to cold, and never the other way around. A refrigerator causes heat to flow from cold to hot by inputting work, which cools the space inside the refrigerator. thermal energy is transferred from the cool air inside the refrigerator to the warmer air in the kitchen. ... As a liquid, the refrigerant absorbs thermal energy from the cool air inside the refrigerator and changes to a gas.

Explanation:

gas vibrate and moves freely at high speeds, liquid vibrate, move about, and slide past each other. solid vibrate (jiggle) but generally do not move from place to place

hope it helps you

Answer:

As a substance freezes, its particles lose some of their freedom of motion and become more orderly.

Explanation:

Answer:

They get closer and slow down

Explanation:

Answer:Galaxies

Explanation:

I know about this stuff, I hope it helped!

Answer:

B-galaxies

Explanation:

e2020

Answer:

The resultant velocity of the helicopter is [tex]\vec v_{H} = \left(89.894\,\frac{m}{s}, -93.348\,\frac{m}{s}\right)[/tex].

Explanation:

Physically speaking, the resulting velocity of the helicopter ([tex]\vec v_{H}[/tex]), measured in meters per second, is equal to the absolute velocity of the wind ([tex]\vec v_{W}[/tex]), measured in meters per second, plus the velocity of the helicopter relative to wind ([tex]\vec v_{H/W}[/tex]), also call velocity at still air, measured in meters per second. That is:

[tex]\vec v_{H} = \vec v_{W}+\vec v_{H/W}[/tex] (1)

In addition, vectors in rectangular form are defined by the following expression:

[tex]\vec v = \|\vec v\| \cdot (\cos \alpha, \sin \alpha)[/tex] (2)

Where:

[tex]\|\vec v\|[/tex] - Magnitude, measured in meters per second.

[tex]\alpha[/tex] - Direction angle, measured in sexagesimal degrees.

Then, (1) is expanded by applying (2):

[tex]\vec v_{H} = \|\vec v_{W}\| \cdot (\cos \alpha_{W},\sin \alpha_{W}) +\|\vec v_{H/W}\| \cdot (\cos \alpha_{H/W},\sin \alpha_{H/W})[/tex] (3)

[tex]\vec v_{H} = \left(\|\vec v_{W}\|\cdot \cos \alpha_{W}+\|\vec v_{H/W}\|\cdot \cos \alpha_{H/W}, \|\vec v_{W}\|\cdot \sin \alpha_{W}+\|\vec v_{H/W}\|\cdot \sin \alpha_{H/W} \right)[/tex]

If we know that [tex]\|\vec v_{W}\| = 25\,\frac{m}{s}[/tex], [tex]\|\vec v_{H/W}\| = 125\,\frac{m}{s}[/tex], [tex]\alpha_{W} = 240^{\circ}[/tex] and [tex]\alpha_{H/W} = 325^{\circ}[/tex], then the resulting velocity of the helicopter is:

[tex]\vec v_{H} = \left(\left(25\,\frac{m}{s} \right)\cdot \cos 240^{\circ}+\left(125\,\frac{m}{s} \right)\cdot \cos 325^{\circ}, \left(25\,\frac{m}{s} \right)\cdot \sin 240^{\circ}+\left(125\,\frac{m}{s} \right)\cdot \sin 325^{\circ}\right)[/tex][tex]\vec v_{H} = \left(89.894\,\frac{m}{s}, -93.348\,\frac{m}{s}\right)[/tex]

The resultant velocity of the helicopter is [tex]\vec v_{H} = \left(89.894\,\frac{m}{s}, -93.348\,\frac{m}{s}\right)[/tex].

Answer:

2 reasons because there are not many of them and they have so much energy that it is hard to capture one at all

Answer:

they have a lot of energy that can prove difficult to capture

Explanation:

Answer:

0.035 J/g°C

Explanation:

From the question given above, the following data were obtained:

Heat (Q) absorbed = 2500 J

Mass (M) = 1.2 Kg

Initial Temperature (T₁) = 10 °C

Final Temperature (T₂) = 70 °C

Specific heat capacity (C) =?

Next, we shall determine the change in temperature. This can be obtained as follow:

Initial Temperature (T₁) = 10 °C

Final Temperature (T₂) = 70 °C

Change in temperature (ΔT) =

ΔT = T₂ – T₁

ΔT = 70 – 10

ΔT = 60 °C

Thus, the change in the temperature of the substance is 60 °C

Next, we shall convert 1.2 Kg to grams (g). This can be obtained as follow:

1 Kg = 1000 g

Therefore,

1.2 Kg = 1.2 Kg × 1000 g / 1 Kg

1.2 Kg = 1200 g

Thus, 1.2 Kg is equivalent to 1200 g.

Finally, we shall determine the specific heat capacity of substance. This can be obtained as follow:

Heat (Q) absorbed = 2500 J

Mass (M) = 1200 g

Change in temperature (ΔT) = 60 °C

Specific heat capacity (C) =?

Q = MCΔT

2500 = 1200 × C × 60

2500 = 72000 × C

Divide both side by 72000

C = 2500 / 72000

C = 0.035 J/g°C

Therefore, the specific heat capacity of the substance is 0.035 J/g°C

Answer:

104.59 m

Explanation:

The following data were obtained from the question:

Horizontal velocity (u) = 13 ms¯¹

Horizontal distance (s) = 60 m

Height (h) =?

Next, we shall determine the time taken for the car to get to the ground. This can be obtained as follow:

Horizontal velocity (u) = 13 ms¯¹

Horizontal distance (s) = 60 m

Time (t) =?

s = ut

60 = 13 × t

Divide both side by 13

t = 60 / 13

t = 4.62 s

Finally, we shall determine the height cliff. This can be obtained as follow:

Time (t) = 4.62 s

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) =?

h = ½gt²

h = ½ × 9.8 × 4.62²

h = 4.9 × 21.3444

h = 104.59 m

Thus, the height of the cliff is 104.59 m

Answer:

their ability to conduct electricity

Answer:

0.5kg

Explanation:

Mass = Weight / Gravitational field strength

Mass = 4.9 / 9.8

Mass = 0.5

Answer:do you know how to draw a electronics configuration

Explanation:

Answer:

Sonography- using sound waves to image internal structures

Brachytherapy-  Therapy where radiatio is placed inside or next to the diseased area

lithiotripsy- The physical breakage of stones by the application of pulsed ulrasound

radiopharmaceuticals-   internally delivered and targeted ionizing radiation

Explanation:

Answer:

Here are the answers :D

Explanation:

I just did it right now on Edg22 and I got it correct :D

Answer:

Total displacement

The displacement of the car is 10 kilometers due East and 5 kilometers due North.

The magnitude of the displacement of the car is approximately 11.180 kilometers.

Total distance

The total distance of the car is 15 kilometers.

Explanation:

According to the statement the car shows the following path, whose displacement is represented by the following formula: (All distances are measured in kilometers)

[tex]\vec r = \vec r_{1} + \vec r_{2}+\vec r_{3}[/tex] (1)

Where:

[tex]\vec r_{1}[/tex] - First displacement to the east.

[tex]\vec r_{2}[/tex] - Displacement to the north.

[tex]\vec r_{3}[/tex] - Second displacement to the east.

If we know that [tex]\vec r_{1} = (5,0)[/tex], [tex]r_{2} = (0,5)[/tex] and [tex]r_{3} = (5,0)[/tex], then the displacement of the car is:

[tex]\vec r = (10, 5)[/tex]

The displacement of the car is 10 kilometers due East and 5 kilometers due North.

The magnitude of the displacement represents the distance of the car from point of departure in a straight line and is determined by the Pythagorean Theorem:

[tex]\|\vec r\| = \sqrt{10^{2}+5^{2}}[/tex]

[tex]\|\vec r\| \approx 11.180\,km[/tex]

The magnitude of the displacement of the car is approximately 11.180 kilometers.

The distance travelled of the car is the sum of magnitudes of the displacement of the car, each of them are calculated by Pyhtagorean Theorem:

[tex]d = \|\vec r_{1}\| + \|\vec r_{2}\| + \|\vec r_{3}\|[/tex] (2)

[tex]d = 5\,km + 5\,km + 5\,km[/tex]

[tex]d = 15\,km[/tex]

The total distance of the car is 15 kilometers.

Answer:

The most abundant gas in Earth’s atmosphere is nitrogen, followed by oxygen, which is needed to burn wood and fuel. The third-most abundant gas is argon. The amount of carbon dioxide in the atmosphere is very small, making up just 0.33% of the atmosphere, but it is very important because plants use it to make simple sugars. Another important gas is water vapor, which condenses around small particles in the atmosphere to form clouds and then rain.

Explanation:

The atmospere of the earth is made up of different types of gases like Nitrogen, oxygen, Carbon di oxide etc.

Atmosphere is defined as the envelope of the gases covered the whole planet of earth and is responsible to save us from ultravoilet rays and entrape the radiation to maintain the ideal temperature on the surface of earth by green house effect.

The most abundant gas in Earth’s atmosphere is nitrogen, followed by oxygen, which is needed to burn wood and fuel. The third-most abundant gas is argon.

The amount of carbon dioxide in the atmosphere is very small, making up just 0.33% of the atmosphere, but it is very important because plants use it to make simple sugars.

Another important gas is water vapor, which condenses around small particles in the atmosphere to form clouds and then rain.

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Answer:

heterogeneous mixture has components that are not evenly distributed. This means that you can easily distinguish between the different components.

Answer:

C. It transforms electrical energy into mechanical energy

Answer: C

Explanation:

Answer:

0.273 liters are needed to accomplish this task without boiling.

Explanation:

The minimum boiling point of kerosene is [tex]150\,^{\circ}C[/tex]. According to this question, we need to determine the minimum volume of liquid such that heat received is entirely sensible, that is, with no phase change.

If we consider a steady state process and that energy interactions with surrounding are negligible, then we get the following formula by the Principle of Energy Conservation:

[tex]\rho_{k}\cdot V_{k}\cdot c_{k}\cdot (T-T_{k,o}) = m_{t}\cdot c_{t}\cdot (T_{t,o}-T)[/tex] (1)

Where:

[tex]\rho_{k}[/tex] - Density of kerosene, measured in kilograms per cubic meter.

[tex]V_{k}[/tex] - Volume of kerosene, measured in cubic meters.

[tex]c_{k}[/tex], [tex]c_{t}[/tex] - Specific heats of the kerosene and tin, measured in joule per kilogram-Celsius.

[tex]T_{k,o}[/tex], [tex]T_{t,o}[/tex] - Initial temperatures of kerosene and tin, measured in degrees Celsius.

[tex]T[/tex] - Final temperatures of the kerosene-tin system, measured in degrees Celsius.

Please notice that the block of tin is cooled at the expense of the temperature of the kerosene until thermal equilibrium is reached.

From (1), we clear the volume of kerosene:

[tex]V_{k} = \frac{m_{t}\cdot c_{t}\cdot (T_{t,o}-T)}{\rho_{k}\cdot c_{k}\cdot (T-T_{k,o})}[/tex]

If we know that [tex]m_{t} = 1.83\,kg[/tex], [tex]c_{t} = 218\,\frac{J}{kg\cdot ^{\circ}C}[/tex], [tex]T_{t,o} = 88\,^{\circ}C[/tex], [tex]T_{k,o} = 24.0\,^{\circ}C[/tex], [tex]T = 57\,^{\circ}C[/tex], [tex]c_{k} = 2010\,\frac{J}{kg\cdot ^{\circ}C}[/tex] and [tex]\rho_{k} = 820\,\frac{kg}{m^{3}}[/tex], then the volume of the liquid needed to accomplish this task without boiling is:

[tex]V_{k} = \frac{(1.83\,kg)\cdot \left(218\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (88\,^{\circ}C-57\,^{\circ}C)}{\left(820\,\frac{kg}{m^{3}} \right)\cdot \left(2010\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (57\,^{\circ}C-24\,^{\circ}C)}[/tex]

[tex]V_{k} = 2.273\times 10^{-4}\,m^{3}[/tex]

[tex]V_{k} = 0.273\,L[/tex]

0.273 liters are needed to accomplish this task without boiling.

Answer:

0.03 A

Explanation:

Answer:

30A

Explanation:

I (current)= p (power) / V (voltage)

I= 6.9*10^3 / 230

I= 30A

Answer:

The velocity after 2.5 seconds is 11.3 m/s

Explanation:

Given;

u = 35.8 m/s

t = 2.50s

g = 9.8 m/s^2

Mathematically;

V = U-gt

Substituting these values;

V = 35.8-2.5(9.8)

V = 35.8-24.5

V = 11.3 m/s