J.J. Thompson in 1987, announced that cathode rays consisted of a stream
of ?
Hydrogen
Nuclei
Isotopes
Electrons

Answer:

1s²2s²p⁶3s²p⁴

Explanation:

An atom that is in the ground state has not lost or gained electrons. If we look at the Periodic Table, we can see that the electron configuration of the sulfur atom (S) is [Ne]3s²p⁴. Since the electron configuration of Ne is 1s²2s²p⁶, the complete electron configuration is 1s²2s²p⁶3s²p⁴.

Answer:

d-the reaction released large amounts of energy when nuclei split apart

Explanation:

no explain

Answer:

See explanation

Explanation:

Dalton's atomic theory furnished us with a basis to discuss the theory of atoms. However, not all his ideas holds up under the scruitiny of morden science.

He postulated that atoms were 'indivisible' the discovery of subatomic particles indeed show that there are smaller particles than atoms.

His postulation that atoms can neither be created nor destroyed does not hold water today because atoms are being created in nuclear reactors.

He said that atoms of all elements are exactly alike. Today we know there are isotopes of elements which are not exactly alike.

We can see that the Dalton's atomic theory did not take cognisance of the important role of subatomic particles in studying the structure of the atom. Modern atomic theory tries to look at the importance of these particles in the understanding the structure of the atom.

Answer:

B. insulator

hope it helps

The materials which prevents flow of electric current through it is called insulators. Thus, option B is correct. The materials which allow the current are conductors.

There are three types of substances based on their conducting nature. The materials which are highly conducting electrically at normal condition are called conductors. For example: metals.

Materials which does not conduct electricity at any condition are called insulators. Insulators prevent the flow of free electrons and thus are resistant to electric shock, example: wood

Some materials which does not conduct at normal temperature but, will conduct at higher temperature and also upon  mixed with other materials are called semiconductors. example:  silicon. Therefore, option B is correct.

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Answer:

In the laboratory, sulphur dioxide is prepared by the reaction of metallic sulphite or a metallic bisulphite with dilute acid.

Explanation:

For example, a reaction between the dilute sulphuric acid and sodium sulphite will result in the formation of SO2. 2.

Answer:

The answer is B and D.

Explanation:

prove me wrong

Answer: b an d

Explanation:

Answer:

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Explanation:

Answer:

a particle with jagged rough ends has a high rate of deposition

Answe

Explanation:

1st Remove ( )

2nd select like terms

3rd Move the constant to the left

4th calculate

5th divided both sides

6th use quadratic formula

Answer:

(a) because they are not being mixed

From the following given options, the picture showing the mixture of elements is Picture (a) i.e, Mixture of O₂ and N₂.

In chemistry, a mixture is a material made up of two or more different chemical substances which are not chemically bonded.

A mixture is the physical combination of two or more substances in which the identities are retained and are mixed in the form of solutions, suspensions and colloids.

Therefore, From the following given options, the picture showing the mixture of elements is Picture (a) i.e, Mixture of O₂ and N₂.

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Answer:

Calculate it, times 6.022

Answer:

The formula is Na2C2O4

Explanation:

I hope this helps

Answer:

C. oxidation ..........

The given reaction is the breaking of the carbohydrate C₁₂H₂₂O₁₁ into 12 C and 11 H₂O. Hence, it is a decomposition reaction .

A decomposition reaction is a type of chemical reaction in which a compound breaks down into two or more simpler substances, either through heat, light, or an electrical current.

In a decomposition reaction, a single reactant is converted into two or more products, which can be elements or compounds.

The general equation for a decomposition reaction can be written as:

AB → A + B

where AB is the reactant and A and B are the products.

Decomposition reactions are important in many chemical processes, such as the breakdown of organic matter in soil, the production of industrial chemicals, and the functioning of biological systems.

The given  reaction is the decomposition of C₁₂H₂₂O₁₁ into 12 C and 11 H₂O.

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Your complete question is follows:

C₁₂H₂₂O₁₁ ⇒ 11 H₂O + 12 C

Which type of reaction is

O synthesis

O decomposition

O oxidation

O combustion

Answer:

1. The graph where x axis and y axis are present is called coordinate.

4. 18

Answer: XCl2(aq) + 2 AgNO3(aq) ---> X(NO3)2(aq) + 2 AgCl(s)

Explanation:

Hehe I remembered how...

Answer:

14.351

Explanation:

Answer:

a) 2.632 kg

b) 41.36 kg

Explanation:

Given data:

Mass of CO react = ?

Mass of Fe formed = 3.50 Kg (3.50 /1000 =3500 g)

Mass of CO₂ formed = ?

Solution:

Chemical equation;

Fe₂O₃ + 3CO     →   2Fe + 3CO₂

Number of moles of Fe:

Number of moles = mass/molar mass

Number of moles =  3500 g/55.85 g/mol

Number of moles = 62.67 mol

now we will compare the moles of iron with CO.

            Fe         :       CO

             2          :       3

          62.67     :        3/2×62.67 = 94 mol

Mass of CO:

Mass = number of moles × molar mass

Mass = 94 mol × 28 g/mol

Mass = 2632 g

In kilogram:

2632g × 1 Kg /1000 g

2.632 kg

Now we will compare the moles of Fe with CO₂

                 Fe         :           CO₂

                  2          :           3

               62.67     :        3/2×62.67 = 94 mol

Mass of CO₂:

Mass = number of moles × molar mass

Mass = 94 mol × 44 g/mol

Mass = 4136 g

In kilogram:

4136g × 1 Kg /1000 g

41.36 kg

Answer:

P4O10 + 6H2O → 4H3PO4

so 1,6,4

The balanced equation is :

                                P₄O₁₀ + 6 H₂O ⇒ 4 H₃PO₄

A balanced equation is an equation for a chemical reaction in which the number of atoms for each element in the reaction and the total charge is the same for both the reactants and the products. In other words, the mass and the charge are balanced on both sides of the reaction.

The unbalanced equation is -

                              P₄O₁₀ + H₂O ⇒ H₃PO₄

There are 4 P on the reactant side, to balance P atom we need to add P on the product side also.

                             P₄O₁₀ + H₂O ⇒ 4 H₃PO₄

To balance the O atom on both sides, add coefficient 6 in front of water and this gives the balanced equation is written as -

                              P₄O₁₀ + 6 H₂O ⇒ 4 H₃PO₄

Therefore,

The balanced equation is :

                                P₄O₁₀ + 6 H₂O ⇒ 4 H₃PO₄

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Specific heat capacity of a substance is the amount of heat required to raise the temperature by one degree celsius of one gram of a substance. Therefore, the initial temperature of water is  27.0°C.

Enthalpy term is basically used in thermodynamics to show the overall energy that a matter have. Mathematically, Enthalpy is directly proportional to specific heat capacity of a substances.

Mathematically,

Enthalpy=mass of solution× specific heat capacity of solution ×Change in temperature.

Enthalpy=1000 J

mass of water=0.05kg

Change in temperature=50-initial

specific heat capacity of solution=4.2

Substituting all the given values we get

1000 J= (0.05kg)(4.2)(50-initial)

initial temperature= 27.0°C

Therefore, the initial temperature of water is 27.0°C.

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hi myself thx for the answers

Answer:

Energy of an electron is quantinized means the electrons can possess only specific individually separated values.

These energy levels are stable and are stationary along with different energy value.  The electron remains in the state until energy is absorbed or released.

The electrons absorb energy when it moves from lower energy state to higher energy state. The electrons lose energy when it moves from higher energy state to lower energy state and thus emit radiations corresponding to the energy gap and is called as quanta.

Answer:

(A) there are 12

Explanation:

bc

Answer:

Dissolving?

Explanation:

Answer:

B. Dissovling

Explanation:

Im a smart boy G.

Answer:

68133080.02 g

Explanation:

I believe that the question is to find the mass of air in the room and not the molar mass of air since the molar mass of air was already given in the question as 28.97 g/mol.

Now, if 1 mole of a gas occupies 22.4 L

x moles of air occupies 52,681,428.8 Liters

x = 1 * 52,681,428.8 /22.4

x = 2351849.5 moles of air

Now, number of moles = mass/ molar mass

but molar mass = 28.97 g/mol

2351849.5 = mass/28.97

mass = 2351849.5 * 28.97

mass = 68133080.02 g

Answer:

10000 g BaNO₃

General Formulas and Concepts:

Chemistry - Atomic Structure

Explanation:

Step 1: Define

3.02 × 10²⁵ formulas units BaNO₃

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of Ba - 137.33 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of BaNO₃ - 137.33 + 14.01 + 3(16.00) = 199.34 g/mol

Step 3: Convert

[tex]3.02 \cdot 10^{25} \ formula \ units \ BaNO_3(\frac{1 \ mol \ BaNO_3}{6.022 \cdot 10^{23} \ formula \ units \ BaNO_3} )(\frac{199.34 \ g \ BaNO_3}{1 \ mol \ BaNO_3} )[/tex] = 9996.79 g BaNO₃

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

9996.79 g BaNO₃ ≈ 10000 g BaNO₃

Answer:

energy flow and nutrient cycles ( photosynthesis , food webs, decomposition webs) sediment transport and soil formation. the water cycle. reproduction/ regeneration mechanisms.

Answer:

work and power increases or decreases opposite of the mass

Explanation:

This Is beacuse Work is the product of Mass, Gravity, and Height

a. volume of NO : 41.785 L

b. mass of H2O : 18 g

c. volume of O2 : 9.52 L

Given

Reaction

4 NH₃ (g) + 5 O2 (g) → 4 NO (g) + 6 H2O (l)

Required

a. volume of NO

b. mass of H2O

c. volume of O2

Solution

Assume reactants at STP(0 C, 1 atm)

Products at 1000 C (1273 K)and 1 atm

a. mol ratio NO : O2 from equation : 4 : 5, so mo NO :

[tex]\tt \dfrac{4}{5}\times 0.5=0.4[/tex]

volume NO at 1273 K and 1 atm

[tex]\tt V=\dfrac{nRT}{P}=\dfrac{0.4\times 0.08206\times 1273}{1}=41.785~L[/tex]

b. 15 L NH3 at STP ( 1mol = 22.4 L)

[tex]\tt \dfrac{15}{22.4}=0.67~mol[/tex]

mol ratio NH3 : H2O from equation : 4 : 6, so mol H2O :

[tex]\tt \dfrac{6}{4}\times 0.67=1[/tex]

mass H2O(MW = 18 g/mol) :

[tex]\tt mass=mol\times MW=1\times 18=18~g[/tex]

c. mol NO at 1273 K and 1 atm :

[tex]\tt n=\dfrac{PV}{RT}=\dfrac{1\times 35.5}{0.08206\times 1273}=0.34[/tex]

mol ratio of NO : O2 = 4 : 5, so mol O2 :

[tex]\tt \dfrac{5}{4}\times 0.34=0.425[/tex]

Volume O2 at STP :

[tex]\tt 0.425\times 22.4=9.52~L[/tex]