Answer:A' = (15, -15), B' = (9, -9), and C' = (15, -9)
Step-by-step explanation:
To dilate triangle ABC with a center of dilation at the origin (0,0) and a scale factor of 3, you need to multiply the coordinates of each vertex by the scale factor.
Let's calculate the coordinates of triangle A'B'C':
For point A:
x-coordinate of A' = scale factor * x-coordinate of A = 3 * 5 = 15
y-coordinate of A' = scale factor * y-coordinate of A = 3 * (-5) = -15
Therefore, A' = (15, -15)
For point B:
x-coordinate of B' = scale factor * x-coordinate of B = 3 * 3 = 9
y-coordinate of B' = scale factor * y-coordinate of B = 3 * (-3) = -9
Therefore, B' = (9, -9)
For point C:
x-coordinate of C' = scale factor * x-coordinate of C = 3 * 5 = 15
y-coordinate of C' = scale factor * y-coordinate of C = 3 * (-3) = -9
Therefore, C' = (15, -9)
Hence, the correct coordinates of triangle A'B'C' are A' = (15, -15), B' = (9, -9), and C' = (15, -9).
A message is coded into the binary symbols 0 and 1 and the message is sent over a communication channel.
The probability a 0 is sent is 0.4 and the probability a 1 is sent is 0.6. The channel, however, has a random error that
changes a 1 to a 0 with probability 0.1 and changes a 0 to a 1 with probability 0.2. Show your work below.
a. What is the probability a 1 is received?
b. If a 1 is received, what is the probability a 0 was sent?
Answer:
A: the probability that a 1 is received is 0.56.
B: the probability that a 0 was sent given that a 1 is received is (2/25) * (1 - P(0 sent)).
Step-by-step explanation:
To solve this problem, we can use conditional probabilities and the concept of Bayes' theorem.
a. To find the probability that a 1 is received, we need to consider the two possibilities: either a 1 was sent and remained unchanged, or a 0 was sent and got flipped to a 1 by the random error.
Let's denote:
P(1 sent) = 0.6 (probability a 1 is sent)
P(0→1) = 0.2 (probability a 0 is flipped to 1)
P(1 received) = ?
P(1 received) = P(1 sent and unchanged) + P(0 sent and flipped to 1)
= P(1 sent) * (1 - P(0→1)) + P(0 sent) * P(0→1)
= 0.6 * (1 - 0.2) + 0.4 * 0.2
= 0.6 * 0.8 + 0.4 * 0.2
= 0.48 + 0.08
= 0.56
Therefore, the probability that a 1 is received is 0.56.
b. If a 1 is received, we want to find the probability that a 0 was sent. We can use Bayes' theorem to calculate this.
Let's denote:
P(0 sent) = ?
P(1 received) = 0.56
We know that P(0 sent) + P(1 sent) = 1 (since either a 0 or a 1 is sent).
Using Bayes' theorem:
P(0 sent | 1 received) = (P(1 received | 0 sent) * P(0 sent)) / P(1 received)
P(1 received | 0 sent) = P(0 sent and flipped to 1) = 0.4 * 0.2 = 0.08
P(0 sent | 1 received) = (0.08 * P(0 sent)) / 0.56
Since P(0 sent) + P(1 sent) = 1, we can substitute 1 - P(0 sent) for P(1 sent):
P(0 sent | 1 received) = (0.08 * (1 - P(0 sent))) / 0.56
Simplifying:
P(0 sent | 1 received) = 0.08 * (1 - P(0 sent)) / 0.56
= 0.08 * (1 - P(0 sent)) * (1 / 0.56)
= 0.08 * (1 - P(0 sent)) * (25/14)
= (2/25) * (1 - P(0 sent))
Therefore, the probability that a 0 was sent given that a 1 is received is (2/25) * (1 - P(0 sent)).
A message is coded into the binary symbols 0 and 1 and the message is sent over a communication channel. The probability a 0 is sent is 0.4 and the probability a 1 is sent is 0.6. The channel, however, has a random error that changes a 1 to a 0 with probability 0.2 and changes a 0 to a 1 with probability 0.1. (a) What is the probability a 0 is received? (b) If a 1 is received, what is the probability a 0 was sent?
0.005627 to 3 decimal places
(i) Correcting the figures to 3 decimal places:
-0.005627 ≈ -0.006
0.0056 ≈ 0.006
-0.0049327 ≈ -0.005
0.0049 ≈ 0.005
-0.001342 ≈ -0.001
(ii) Correcting the figures to 3 significant figures:
-0.005627 ≈ -0.00563
0.0056 ≈ 0.00560
-0.0049327 ≈ -0.00493
0.0049 ≈ 0.00490
-0.001342 ≈ -0.00134
(i) When rounding to 3 decimal places, we look at the fourth decimal place and round the figure accordingly. If the fourth decimal place is 5 or above, we round up the preceding third decimal place. If the fourth decimal place is less than 5, we simply drop it.
(ii) When rounding to 3 significant figures, we consider the digit in the third significant figure. If the digit in the fourth significant figure is 5 or above, we round up the preceding third significant figure. If the digit in the fourth significant figure is less than 5, we simply drop it.
Rounding to the correct number of decimal places or significant figures is important to maintain precision and accuracy in calculations and measurements. It helps to ensure that the reported values are appropriate for the level of precision required in a given context.
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Pls geometry work help
Answer:
Step-by-step explanation:
Given:
<RPS = 35
<PAQ = 130
Solution:
If <PAQ = 130 then <QAR =50
because they are a linear pair that add to 180
<QAR = mQR = 50
mRS = 2(<RPS) >inscribed angle
mRS = 2(35)
mRS = 70
<PAQ = 130
<PAQ = mPQ
<PSQ = 1/2 (mPQ) >inscribed angle
<PSQ = 1/2 (130)
<PSQ = 65
<PBS = 180 - <RPQ - PSQ >triangle
<PBS = 180 - 35-65
<PBS = 80
<PBS = <QBR >vertical angles
<QBR = 80
<ABQ = 180- <QBR >linear pair
<ABQ = 180 - 80
<ABQ= 100
<AQB = 180 - <ABQ - <QAR >triangle
<AQB = 180 -100 - 50
<AQB = 30
<AQB = <AQS
<AQS =30
mRS = 70
mPS = 180-mRS 180 for semicircle
mPS = 180 - 70
mPS = 110
Adults are encouraged to visit the dentist at least once a year. In the 2019 National College Health
Assessment, 28,021 out of a random sample of 38,433 college students said they had a dental exam in
the last 12 months.
¹American College Health Association-National College Health Assessment (2020). Undergraduate student
reference group data report, Fall 2019. https://www.acha.org/NCHA/ACHA-
NCHA Data/Publications and Reports/NCHA/Data/Reports ACHA-NCHAIIl.aspx
Use the appropriate data analysis tool to construct a 99% confidence interval to estimate the
population proportion of college students who said they had a dental exam in the last 12 months.
Lower Bound
Upper Bound
The boundaries of the 99% confidence interval are
Lower bound = 0.7232Upper bound = 0.7348Constructing the 99% confidence intervalFrom the question, we have the following parameters that can be used in our computation:
Selected, x = 28021
Sample, n = 38433
This means that the proportion, p is
p = 28021/38433
p = 0.729
The 99% confidence interval is then calculated as
CI = p ± z * √(p * (1 - p)/n)
Where
z = 2.576 i.e. the z-score at 99% confidence interval
So, we have
CI = 0.729 ± 2.576 * √(0.729 * (1 - 0.729)/38433)
Evaluate
CI = 0.729 ± 0.0058
Evaluate
CI = (0.7232, 0.7348)
Hence, the confidence interval is (0.7232, 0.7348)
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Which rectangles are similar? Four rectangles have a length of 3 c m and a height of 5 c m, a length of 2 point 5 c m and a height of 5 point 5 c m, a length of 2 point 5 c m, and a height of 2 c m, and a length of 5 c m and a height of 4 c m respectively.
The rectangles that are similar are Rectangle 3 and Rectangle 4.
To determine which rectangles are similar, we need to compare their corresponding side lengths.
Rectangle 1:
Length: 3 cm
Height: 5 cm
Rectangle 2:
Length: 2.5 cm
Height: 5.5 cm
Rectangle 3:
Length: 2.5 cm
Height: 2 cm
Rectangle 4:
Length: 5 cm
Height: 4 cm
To determine similarity, we need to compare the ratios of the corresponding side lengths of the rectangles.
Comparing Rectangle 1 with Rectangle 2:
Length ratio: 3 cm / 2.5 cm = 1.2
Height ratio: 5 cm / 5.5 cm ≈ 0.91
The length ratio and height ratio are not equal, so Rectangle 1 and Rectangle 2 are not similar.
Comparing Rectangle 1 with Rectangle 3:
Length ratio: 3 cm / 2.5 cm = 1.2
Height ratio: 5 cm / 2 cm = 2.5
The length ratio and height ratio are not equal, so Rectangle 1 and Rectangle 3 are not similar.
Comparing Rectangle 1 with Rectangle 4:
Length ratio: 3 cm / 5 cm = 0.6
Height ratio: 5 cm / 4 cm = 1.25
The length ratio and height ratio are not equal, so Rectangle 1 and Rectangle 4 are not similar.
Comparing Rectangle 2 with Rectangle 3:
Length ratio: 2.5 cm / 2.5 cm = 1
Height ratio: 5.5 cm / 2 cm = 2.75
The length ratio and height ratio are not equal, so Rectangle 2 and Rectangle 3 are not similar.
Comparing Rectangle 2 with Rectangle 4:
Length ratio: 2.5 cm / 5 cm = 0.5
Height ratio: 5.5 cm / 4 cm = 1.375
The length ratio and height ratio are not equal, so Rectangle 2 and Rectangle 4 are not similar.
Comparing Rectangle 3 with Rectangle 4:
Length ratio: 2.5 cm / 5 cm = 0.5
Height ratio: 2 cm / 4 cm = 0.5
The length ratio and height ratio are equal, so Rectangle 3 and Rectangle 4 are similar.
Therefore, the rectangles that are similar are Rectangle 3 and Rectangle 4.
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What is the range of this function?
The range of the given graph is expressed as:
Option A: {-∞, ∞}
What is the range of the given function?The range of a function is defined as the set of all the possible output values of y. The formula to find the range of a function is y = f(x).
In a relation, it is only a function if every x value corresponds to only one y value,
Now, looking at the given graph, we see that At x = 0, the function is also y = 0.
However, between 0 and π intervals, we see that the graph approaches positive and negative infinity and as such we can tell that the range is expressed as: {-∞, ∞}
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5 In a Survery of 130 people 80 claimed to be CDO partisans and 60 claimed to be Anc partisan. If 30 of them are both ANC and CDO how many people are none of these two parties
Answer: there are 20 people who claimed to be neither CDO partisans nor ANC partisans.
Step-by-step explanation:
To determine the number of people who are none of these two parties, we need to subtract the total number of people who claimed to be CDO partisans, ANC partisans, and those who claimed to be both from the total number of people surveyed.
Total surveyed people = 130
Number claiming to be CDO partisans = 80
Number claiming to be ANC partisans = 60
Number claiming to be both ANC and CDO = 30
To find the number of people who are none of these two parties, we can calculate it as follows:
None of these two parties = Total surveyed people - (CDO partisans + ANC partisans - Both ANC and CDO)
None of these two parties = 130 - (80 + 60 - 30)
None of these two parties = 130 - 110
None of these two parties = 20
I've been stuck on this problem for a minute, anyone able to show me what to do?
Use the following duration times (seconds) of 24 eruptions of the Old Faithful geyser in Yellowstone National
Park. The duration times are sorted from lowest to highest.
110 120 178 213 234 234 235 237 240 243 245 245
250 250 251 252 254 255 255 259 260 266 269 273
Describe how to calculate the limits to determine outliers for this data set? Identify any outliers.
Answer:
1. 01= 234, 03= 255 (since the data is
already sorted)
2. I0R = 255 - 234= 21
3. Lower limit = 234- 1.5 * 21= 203.5
Upper limit = 255+ 1.5 * 21= 285.5
4. Outliers: 110, 120, 178 (below the
lower limit), and 273 (above the upper
limit)
f(x)=x^2. What is g(x)?
Answer:
D, g(x) = 1/4 x^2
Step-by-step explanation:
You can try plugging in the x and y values into each equation. The answer to this would be D, where if you plug in 2 as the x value, you get 1/4 * 4 which equals 1. This also makes sense because 2x would have a narrower curve while 1/2x would have a wider curve.
Assume that at the current exchange rate, the British pound is worth $1.65 in American dollars. You have some dollar bills and several British pound coins. There are 17 items altogether, which have a total value of $20.25 in American dollars. How many American dollars and how many British pound coins do you have?
Answer:
So we have $11.64 in American dollars and £5 in British pound coin
Step-by-step explanation:
To solve this problem, we can use a system of equations. Let x be the number of American dollars and y be the number of British pound coins. Then we have:
x + y/1.65 = 20.25 (since each British pound coin is worth 1.65 American dollars)
x = 17 - y (since there are 17 items altogether)
Substituting the second equation into the first, we get:
(17 - y) + y/1.65 = 20.25
Multiplying both sides by 1.65, we get:
28.05 - y + y = 33.4125
y = 33.4125 - 28.05
y = 5.3625
Therefore, we have 5 British pound coins and:
x = 17 - y = 17 - 5.3625 = 11.6375
Quadrilateral EFGH is an isosceles trapezoid with bases EH and FG. The measure of angle HGF is (9y + 3)°, and the measure of angle EFG is (By + 5)°.
What is the measure of angle HGF?
The correct Option is A. The measure of angle HGF is 20°.
Quadrilateral EFGH is an isosceles trapezoid with bases EH and FG.
The measure of angle HGF is (9y + 3)°, and the measure of angle EFG is (By + 5)°.
To find the measure of angle HGF, we need to solve for the value of y.
Since EFGH is an isosceles trapezoid, the opposite angles are congruent.
Therefore, the measure of angle EFG is also (9y + 3)°.
To find the value of y, we can set the two expressions equal to each other: (9y + 3)° = (By + 5)°.
Next, we can solve for y by isolating it.
We subtract 3° from both sides: 9y = By + 2.
To get y by itself, we subtract By from both sides: 9y - By = 2.
Finally, we can factor out y: y(9 - B) = 2.
To solve for y, we divide both sides by (9 - B): y = 2 / (9 - B).
Now that we have the value of y, we can substitute it back into the expression for angle HGF: (9y + 3)°.
Thus, the measure of angle HGF is (9(2 / (9 - B)) + 3)°.
Therefore, The correct Option is A.
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need help with tshdjkdkdndndndndkd
The length of this line segment is: B. 2√13 units.
How to determine the distance between the coordinates for each points?In Mathematics and Geometry, the distance between two (2) end points that are on a coordinate plane can be calculated by using the following mathematical equation:
Distance = √[(x₂ - x₁)² + (y₂ - y₁)²]
Where:
x and y represent the data points (coordinates) on a cartesian coordinate.
By substituting the given end points into the distance formula, we have the following;
Distance = √[(4 + 2)² + (1 + 3)²]
Distance = √[(6)² + (4)²]
Distance = √[36 + 16]
Distance = √52
Distance = 2√13 units.
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The table displays the scores of students on a recent exam. Find the mean of the
scores to the nearest 10th.
Score Number of Students
70
6
75
80
85
90
95
3
9
5
7
8
2
The mean of the scores to the nearest tenth is 83.7.
What is the mean?Mean is the average of the given numbers and is calculated by dividing the sum of given numbers by the total number of numbers.
Given the question above, we need to find the mean of the scores to the nearest tenth.
We can find the mean by using the formula below:
[tex]\text{Mean} = \dfrac{\text{Sum of all the observations}}{\text{Total number of observations}}[/tex]
Now,
[tex]\text{Mean} = \dfrac{70(6)+75(3)+80(9)+85(5)+90(7)+95(8)}{6+3+9+5+7+8}[/tex]
[tex]\text{Mean} = \dfrac{420+225+720+425+630+760}{38}[/tex]
[tex]\text{Mean} = \dfrac{3180}{38}[/tex]
[tex]\text{Mean} = 83.7[/tex]
Therefore, the mean of the scores to the nearest tenth is 83.7.
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At what points is the function y=sinx/3x continuous?
Answer: [tex](-\infty, 0) \cup (0, \infty)[/tex]
Step-by-step explanation:
The graph of [tex]\frac{\sin x}{x}[/tex] is continuous for all real [tex]x[/tex] except [tex]x=0[/tex], and multiplying this by [tex]1/3[/tex] does not change this.
A store has a sale with 20% off every item. When you enter the store, you receive a coupon that states that you receive an additional 30% off. Is this equal to a 50% discount? Explain your answer
Answer: Nope
Step-by-step explanation:
No, receiving a 20% discount followed by an additional 30% discount does not result in a total discount of 50%.
To understand why, let's consider an example with an item priced at $100.
If there is a 20% discount applied initially, the price of the item would be reduced by 20%, which is $100 * 0.20 = $20. So the new price after the first discount would be $100 - $20 = $80.
Now, if there is an additional 30% discount applied to the $80 price, the discount would be calculated based on the new price. The 30% discount would be $80 * 0.30 = $24. So the final price after both discounts would be $80 - $24 = $56.
Comparing the final price of $56 to the original price of $100, we can see that the total discount is $100 - $56 = $44.
Therefore, the total discount received is $44 out of the original price of $100, which is a discount of 44%, not 50%.
Hence, receiving a 20% discount followed by an additional 30% discount does not result in a total discount of 50%.
If FE =14 find the length of BC
Please give a very in-depth explanation and I will mark Brainliest!!
HI Your answer is 42
I have calculated it you can trust me
Well you have marked right in the pic
PLEASE MARK AS BRAINLIEST
Express in simplest radical form show work
Answer:
-33x√2
Step-by-step explanation:
[tex]-5x\sqrt{98}+2\sqrt{2x^2}\\\\= -5x\sqrt{2*7^{2} } + 2(x\sqrt{2} )\\\\= -5x(7)(\sqrt{2} ) + 2x\sqrt{2} \\\\= -35x\sqrt{2} +2x\sqrt{2} \\\\= (-35+2)x\sqrt{2}\\ \\=-33x\sqrt{2}[/tex]
A small college has 204 student athletes. The number of students who play soccer is 52. The number of students who play volleyball is 31. The probability that a student plays in both volleyball and soccer is 5/204.What is the probability that a randomly selected student athlete in this school: Plays both soccer and volleyball? Plays volleyball?
To calculate the probabilities, we can use the following information:
Total number of student athletes = 204
Number of students who play soccer = 52
Number of students who play volleyball = 31
Probability of a student playing both soccer and volleyball = 5/204
1. Probability that a student plays both soccer and volleyball:
Let's denote the probability of playing both soccer and volleyball as P(Soccer and Volleyball). From the given information, we know that the number of students who play both soccer and volleyball is 5.
P(Soccer and Volleyball) = Number of students who play both soccer and volleyball / Total number of student athletes
P(Soccer and Volleyball) = 5 / 204
2. Probability that a student plays volleyball:
We want to find the probability of a student playing volleyball, denoted as P(Volleyball).
P(Volleyball) = Number of students who play volleyball / Total number of student athletes
P(Volleyball) = 31 / 204
Therefore, the probability that a randomly selected student athlete in this school plays both soccer and volleyball is 5/204, and the probability that they play volleyball is 31/204.
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Aschalew is able to do apiece of work in 15 days and Abay can do the same work in 20 daya. if they can work together for 4 days, what is the fraction of the work left?
Answer:
8/15
Step-by-step explanation:
1/15(4 + 1/20(4)
4/15 + 4/20 I can reduce 4/20 to 1/5
4/15 + 1/5
4/15 + 3/15 = 7/15
Together they can get 7/15 of the job done. 15/15 - 7/15 is 8/15.
That means that they have 8/15 left to do.
Helping in the name of Jesus.
Find the volume of the solid obtained by rotating the region
bounded by the graphs y=(x-4)^3,the x-axis, x=0, and x=5
about the y-axis? (Express numbers in exact form. Use symbolic
notation and fractions where needed.)
Answer:
Step-by-step explanation:
To find the volume of the solid obtained by rotating the region bounded by the graphs y = (x - 4)^3, the x-axis, x = 0, and x = 5 about the y-axis, we can use the method of cylindrical shells.
The formula for the volume of a solid obtained by rotating a region bounded by the graph of a function f(x), the x-axis, x = a, and x = b about the y-axis is given by:
V = 2π ∫[a, b] x * f(x) dx
In this case, the function f(x) = (x - 4)^3, and the bounds of integration are a = 0 and b = 5.
Substituting these values into the formula, we have:
V = 2π ∫[0, 5] x * (x - 4)^3 dx
To evaluate this integral, we can expand the cubic term and then integrate:
V = 2π ∫[0, 5] x * (x^3 - 12x^2 + 48x - 64) dx
V = 2π ∫[0, 5] (x^4 - 12x^3 + 48x^2 - 64x) dx
Integrating each term separately:
V = 2π [1/5 x^5 - 3x^4 + 16x^3 - 32x^2] evaluated from 0 to 5
Now we can substitute the bounds of integration:
V = 2π [(1/5 * 5^5 - 3 * 5^4 + 16 * 5^3 - 32 * 5^2) - (1/5 * 0^5 - 3 * 0^4 + 16 * 0^3 - 32 * 0^2)]
Simplifying:
V = 2π [(1/5 * 3125) - 0]
V = 2π * (625/5)
V = 2π * 125
V = 250π
Therefore, the volume of the solid obtained by rotating the region bounded by the graphs y = (x - 4)^3, the x-axis, x = 0, and x = 5 about the y-axis is 250π cubic units.
The area of a triangular road sign is 70 square ft. If the base of the sign measures 14 ft, what is the height of the sign?
Answer:
height = 10 ft
Step-by-step explanation:
the area (A) of a triangle is calculated as
A = [tex]\frac{1}{2}[/tex] bh ( b is the base and h the height )
given A = 70 and b = 14 , then
[tex]\frac{1}{2}[/tex] × 14 × h = 70
7h = 70 ( divide both sides by 7 )
h = 10 ft