Which object is in static equilibrium?

4.55 seconds

Given, Speed = 330.0 m/s

To find the time, it will take for the sound of thunder to travel 1.5 km, we have to apply the formula for speed :

[tex]speed = \frac{distance}{time} [/tex]

This implies that:-

[tex]time = \frac{distance}{speed} [/tex]

So, Let's get started with the steps -

Step 1- Convert 1.5 km to metres.

[tex]1.5 \: km \: \\ = > \: 1.5 \times 1000 \\ = > 1500 \: m[/tex]

Step 2- Now, to get time, substitute the values you got now in "time=distance/speed"

[tex]t = \frac{1500}{330}[/tex]

[tex] => t = 4.55 \: seconds[/tex]

Therefore, the answer is 4.55 seconds

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Answer:

95

Explanation:

Answer:

false

Explanation:

discovered colours of the rainbow

Answer:

False

Explanation:

Have the day you deserve :)

Answer:

solid

Explanation:

Gold is a chemical element with symbol Au and atomic number 79. Classified as a transition metal, Gold is a solid at room temperature.

El valor de L del tramo rugoso B a C con coeficiente de fricción igual a 0,6, recorrido por el cuerpo de 2 kg cuando se suelta del punto A es 5.00 m.  

El valor de L se puede calcular a partir de la definición de trabajo:

[tex]W = F_{\mu}*d[/tex]  (1)

En donde:

[tex]F_{\mu}[/tex]: es la fuerza aplicada sobre el cuerpo en el tramo de B a C = fuerza de roce = -μN (el signo menos se debe a que está en dirección opuesta a la del movimiento)

μ: es el coeficiente de roce = 0,6

N: es la normal = mg

m: es la masa del cuerpo = 2 kg

g: es la aceleración debida a la gravedad = 9,81 m/s²

d: es la distancia = L =?

Por otra parte, el trabajo también se define como la diferencia de energía mecánica entre los puntos B y C.

[tex] W = E_{C} - E_{B} [/tex]   (2)

Al igualar la ecuación (1) con la (2) tenemos:

[tex]E_{C} - E_{B} = F_{\mu}*d[/tex]   (3)

En el punto C, la energía es cero (0) dado que el cuerpo se detiene y en el punto B la energía que tiene el objeto es la cinética:  

[tex] E_{B} = \frac{1}{2}mv_{B}^{2} [/tex]      

En donde:  

[tex]v_{B}[/tex]: es la velocidad del cuerpo en el punto B

La velocidad del cuerpo en el punto B se puede calcular mediante conservación de energía entre los puntos A y B:

[tex] E_{A} = E_{B} [/tex]          

En el punto A, el cuerpo tiene energía potencial gravitacional, por lo tanto:

[tex] mgh = \frac{1}{2}mv_{B}^{2} [/tex]    (4)

En donde:

h: es la altura = 3 m

Entonces, la velocidad en el punto B es (eq 4):

[tex] v_{B} = \sqrt{\frac{2mgh}{m}} = \sqrt{2*9,81 m/s^{2}*3 m} = 7,67 m/s [/tex]

Ahora, la ecuación (3) queda como sigue:  

[tex] 0 - \frac{1}{2}mv_{B}^{2} = -\mu N*L [/tex]  

[tex] \frac{1}{2}2 kg*(7.67 m/s)^{2} = 0,6*2 kg*9,81 m/s^{2}*L [/tex]  

Resolviendo para L, tenemos:

[tex] L = \frac{\frac{1}{2}2 kg*(7.67 m/s)^{2}}{0,6*2 kg*9,81 m/s^{2}} = 5.00 m [/tex]

Por lo tanto, el valor de L es 5.00 m.

Encuentra más sobre trabajo aqui:

Espero que te sea de utilidad!  

Answer:

[tex]resolving \: \\ (\downarrow_{ + }) \: s = ut + \frac{1}{2} g {t}^{2} \\ u = 0 ,\: g = 9.81m. {s}^{ - 2} , \: t = 5s \\ s =h= \frac{1}{2} g {t}^{2}, = \frac{1}{2} (9.81){5}^{2}\\=4.9\times25 \\ h=122.6m[/tex]

Answer:

b

Explanation:

es

la b

[tex]\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2[/tex]

[tex]\\ \sf\longmapsto 163=0(6.92)+\dfrac{1}{2}a(6.92)[/tex]

[tex]\\ \sf\longmapsto 163=3.46a[/tex]

[tex]\\ \sf\longmapsto a=\dfrac{163}{3.46}[/tex]

[tex]\\ \sf\longmapsto a=47.1m/s^2[/tex]

We want to find at what angle a projectile is launched given that at the highest point, the speed is 6m/s.

The launch angle of the projectile is 60°.

Remember that the only acceleration will appear on the vertical axis, and this is the gravitational acceleration, this means that on the horizontal axis we will have a constant speed.

Also remember that when an object is on its highest point, the vertical velocity is equal to zero, then it only has horizontal velocity (which we know it is a constant).

Then we can conclude that the horizontal velocity is equal to 6m/s.

If the angle is measured from the horizontal axis, we will have that the horizontal velocity is a projection on the x-axis of the initial speed, this is:

12m/s*cos(θ) = 6m/s

Now we can solve this for theta.

cos(θ) = (6m/s)/(12 m/s) = 1/2

θ = Acos(1/2) = 60°

The launch angle of the projectile is 60°.

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Answer:

Final velocity = 7.4m/s

Explanation:

Use the equation:

acceleration = (final velocity - initial velocity)/time

Rearrange to get:

final velocity = (acceleration * time) + initial velocity

Now just substitute with the values you already have:

Final velocity = (-9.8m/s^2 * 0.7s) + 0.5m/s

Final velocity = 7.36m/s

We are using 2 sig-figs, so:

Final Velocity = 7.4m/s

Answer: Convection currents in the molten mantle cause the plates to slowly move about the Earth a few centimeters each year. Many ocean floor features are a result of the interactions that occur at the edges of these plates.

Explanation:

The convection currents can be seen in a crowd, in the ocean, and can also be felt underground.

A convection current simply means the process that has to do with the movement of energy from one particular place to another.

A convention current is also known as convection heat transfer. Convention currents are due to differential heating. This brings about the circulation patterns that are referred to as convection currents that can be found in the atmosphere, water, and the mantle.

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Answer:

I know someone that has the answer

Explanation:

A

Answer:

p c o e

Explanation:

Answer:

Explanation:

pcoe

Answer:

Your answer will be D.

The ball is traveling at a steady speed until it hits an unbalanced force and changes direction.

Explanation:

The ball is traveling at a steady speed until it hits an unbalanced force and changes direction. The correct option is D.

Thus, An unbalanced external force acts upon an item, Newton's first law of motion, often known as the law of inertia, asserts that an object at rest will remain at rest and an object in motion will continue to move in the same direction and at the same pace.

When a baseball is struck with a bat, it is originally at rest or moving steadily forward.

The ball experiences an imbalanced force when it is struck by the bat, altering its direction and speed. The bat's application of external force is what causes this shift in motion.

Thus, The ball is traveling at a steady speed until it hits an unbalanced force and changes direction. The correct option is D.

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Answer:

Explanation:

The correct answer is: Weak nuclear forces are involved when certain types of atoms break down. Strong nuclear forces are responsible for holding atoms together.

Answer:

It should be less energy

Explanation:

The further away from the nucleus, the more it holds, correct? So those closer to the nucleus hold less electrons. So therefore, the ones that are closer must have more energy than the outer electrons.

Answer:

the answer is option c

Explanation:

if we keep materials in unlabelled containers we can mix them up and use 2 dangerous acids to make an explosion

Answer:

soln

work done= 200J

Time taken = 5 sec

power=?

We know that,

power=w/t

= 2000/5

= 400W

Explanation:

hopw this will help you

Answer:

Displacement=10 meters

Explanation:

The displacement is the direct path from the first contact with the ball and the last spot it was seen in. The ball was kicked north 8 meters, meaning it was kicked vertically upward, and then it was kicked east 6 meters, or to the right. If we were to draw the displacement we would see that this is a right triangle. That means we can use the Pythagorean Theorem:

[tex]a^2+b^2=c^2\\8^2+6^2=c^2\\64+36=c^2\\c^2=100\\\sqrt{c} =\sqrt{100} \\c=10[/tex]

Boom.

The displacement is 10 m toward the northeast. The first option is correct.

The displacement is a vector quantity having both magnitude and direction. It is equal to the path length between the initial and final positions.

Given:

North displacement, y=8 m

East displacement, x= 6 m

The net displacement is calculated using Pythagoras' theorem as the displacements are perpendicular to each other.

The displacement is given by:

d=√(x²+y²)

d=√(8²+6²)

d=10 m

So, the displacement is 10 m.

Therefore, the displacement is 10 m toward the northeast. The first option is correct.

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Answer:

Yoour MOM

Explanation:

Answer:

1 / f = 1 / o + 1 / i

1 / image distance + 1 / object distance = 1  focal length

If the object distance is large the image will be at about the focal length

The value of 1 / f is fixed for any one particular lense

As the object distance decreases the image must increase

The above equation can also be written as

o i / (i + o) = f    or i / (i / o + 1)  = f

If for instance o was very large the image would be at the focal length

Answer:

The average velocity from 5 to 6 seconds is -27 m/s

Given the time, the final velocity and the acceleration, we can calculate the initial velocity using the kinematic equation A:

[tex]v = v_o + a \Delta t[/tex]

A skateboarder flies horizontally off a cement planter. After a time of 3 seconds (Δt), he lands with a final velocity (v) of −4.5 m/s. Assuming the acceleration is -9.8 m/s² (a), we can calculate the initial velocity of the skateboarder (v₀) using the kinematic equation A.

[tex]v = v_o + a \Delta t\\\\v_o = v - a \Delta t = (-4.5 m/s) - (-9.8 m/s^{2} ) \times 3 s = 24.9 m/s[/tex]

Given the time, the final velocity and the acceleration, we can calculate the initial velocity using the kinematic equation A:

[tex]v = v_o + a \Delta t[/tex]

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Answer:

A

Explanation:

Answer: C Because it has more dots in the rectangle meaning that if it has more dots than others then it has a higher density according to the model

Explanation:

Answer:

Explanation:

It transfers from mechanical energy, to electrical energy to chemical energy. The energy transformation in an electromagnet is from chemical to electrical to electromagnetic waves. The north poles of two different magnets will attract each other.

Answer:

When we can get the Kinetic energy from this formula KE= 1/2 M V^2and we can get the potential energy from this formula PE =  M g H

we can set that the kinetic energy at the bottom of the fall equals the potential energy at the top so, KE = PE

1/2 MV^2 = M g H

1/2 V^2 = g H

when V is the velocity, g is an acceleration of gravitational force (9.8 m^2/s) and H is the height of the fall (8 m).

∴ v^2 = 2 * 9.8 * 8 = 156.8

∴ v= √156.8 = 12.5 m/s